Question

tìm x:

\(9-\left(1-x\right)^2=0\)

Answer 1

\(9-\left(1-x\right)^2=0\) \(\Rightarrow\left(1-x\right)^2=9\)

\(\Rightarrow\left[{}\begin{matrix}1-x=3\\1-x=-3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-2\\x=4\end{matrix}\right.\)

Answer 2

\(9-\left(1-x\right)^2=0\)

\(\Rightarrow\left(1-x\right)^2=9-0\)

\(\Rightarrow\left[{}\begin{matrix}\left(1-x\right)^2=3^2\\\left(1-x\right)^2=\left(-3\right)^2\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}1-x=3\\1-x=-3\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=1-3\\x=1+3\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-2\\x=4\end{matrix}\right.\)