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BẠn tham khảo nha

bài thứ nhất : Talk about your family customs and traditions

Almost everyone in the house will have a traditional custom. My house also has and I think everyone's customs will be similar to mine, that is, every 30 New Year's Eve my house is cleaned. Old things will be bought new to replace. And most especially, this traditional package of banh chung, banh tet, everyone must have. As soon as the cake is wrapped, we will sit together, we even stay up until night to steam the cake. Because of wrapping the cake, we sat together again and became closer. I really like this custom.

BÀi 2: Talk about your favorite festival in Vietnam

My favorite festival is Tet. Tet is the New Year's Eve moment between the old year and the new year. Before Tet, everyone is busy cleaning the house, preparing the peach blossom branches, making the trays, .. .. On New Year's Eve is also considered a reunion day for families to review the old stories of the past year and wish a prosperous and prosperous new year. On the first day of Tet, children are given money to celebrate their age, as well as adults' wishes for their children to grow up. That's why I love Tet so much.

Em phải : 

- Không xả rác bừa bãi 

- Không phá rừng , đốt rừng 

- Hạn chế đi các phương tiện có khói , bụi ( nên đi xe đạp )

- Không dùng túi ni lông 

- ...

đi xe đạp hoặc đi bộ đến trường

Hạn chế sử dụng túi nilon

Không xả rác bừa bãi

Vứt rác đúng nơi quy định

Trồng nhiều cây xanh

Tích cực tham gia phong trào bảo vệ môi trường

Câu 2: 

uses crt;

var a:array[1..100]of integer;

i,n,t:integer;

begin

clrscr;

write('Nhap n='); readln(n);

for i:=1 to n do

begin

write('A[',i,']='); readln(a[i]);

end;

t:=0;

for i:=1 to n do 

if (4<a[i]) and (a[i]<15) then t:=t+a[i];

writeln(t);

readln;

end.

\(a,A=0,2\left(5x-1\right)-\dfrac{1}{2}\left(\dfrac{2}{3}x+4\right)+\dfrac{2}{3}\left(3-x\right)\)

\(=x-0,2-\dfrac{1}{3}x-2+2-\dfrac{2}{3}x\)

\(=\left(-0,2-2+2\right)+\left(x-\dfrac{1}{3}x-\dfrac{2}{3}x\right)\)

\(=-0,2\)

\(b,B=\left(x-2y\right)\left(x^2+2xy+4y^2\right)-\left(x^3-8y^3+10\right)\)

\(=x^3-8y^3-x^3+8y^3-10\)

\(=-10\)

\(c,C=4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)-4x\)

\(=4\left(x^2+2x+1\right)+\left(4x^2-4x+1\right)-8\left(x^2-1\right)-4x\)

\(=4x^2+8x+4+4x^2-4x+1-8x^2+8-4x\)

\(=13\)

a) \(A=0,2\left(5x-1\right)-\dfrac{1}{2}\left(\dfrac{2}{3}x+4\right)+\dfrac{2}{3}\left(3-x\right)\)

\(A=x-\dfrac{1}{5}-\dfrac{1}{3}x-2+2-\dfrac{2}{3}x\)

\(A=\left(x-\dfrac{1}{3}x-\dfrac{2}{3}x\right)-\left(\dfrac{1}{5}+2-2\right)\)

\(A=-\dfrac{1}{5}\)

Vậy: ...

b) \(B=\left(x-2y\right)\left(x^2+2xy+4y^2\right)-\left(x^3-8y^3+10\right)\)

\(B=\left[x^3-\left(2y\right)^3\right]-\left[x^3-\left(2y\right)^3\right]-10\)

\(B=-10\)

Vậy: ...

c) \(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x+1\right)\left(x-1\right)-4x\)

\(=4\left(x^2+2x+4\right)+\left(4x^2-4x+1\right)-8\left(x^2-1\right)-4x\)

\(=4x^2+8x+4+4x^2-4x+1-8x^2+8-4x\)

\(=\left(4x^2+4x^2-8x^2\right)+\left(8x-4x-4x\right)+\left(4+1+8\right)\)

\(=13\)

Vậy:...

=x−0,2−13x−2+2−23x=�−0,2−13�−2+2−23�

b) \(27x^3-54x^2+36x=8\)

\(\Rightarrow27x^3-54x^2+36x-8=0\)

\(\Rightarrow\left(3x\right)^3-3.\left(3x\right)^2.2+3.3x.2^2-2^3=0\)

\(\Rightarrow\left(3x-2\right)^3=0\)

\(\Rightarrow3x-2=0\)

\(\Rightarrow3x=2\)

\(\Rightarrow x=\dfrac{2}{3}\)

(2x-5)^2-(5+2x)^2=0
<=>(2x-5-5-2x)(2x-5+5+2x)=0
<=>(-10).(4x)=0
<=>(-40x)=0
<=>x =0
27x^3-54x^2+36x=8
<=>27x^3-54x^2+36x-8=0
<=>(3x-2)^3=0
<=>3x-2=0
<=>3x=2
<=>x=2/3

a,\(\left(2x-5\right)^2-\left(5+2x\right)^2=0\)

\(\Rightarrow\left(2x-5\right)^2+\left(2x-5\right)^2=0\)

Do \(\left(2x-5\right)^2\ge0\)

\(\Rightarrow\left(2x-5\right)^2=0\)

\(\Rightarrow2x-5=0\)

\(\Rightarrow x=\dfrac{5}{2}\)

@Yukru giúp câu b với!