Question

phân tích thành nhân tử

\(\left(4x+1\right)\left(12x-1\right)\left(3x+2\right)\left(x+1\right)-4\)

Answer 1

\(\left(4x+1\right)\left(12x-1\right)\left(3x+2\right)\left(x+1\right)-4\\ =\left(12x^2+11x+2\right)\left(12x^2+11x-1\right)-4\\ =\left(12x^2+11x+0,5+1,5\right)\left(12x^2+11x+0,5-1,5\right)-4\\ =\left(12x^2+11x+0,5\right)^2-\left(1,5\right)^2-4\\ =\left(12x^2+11x+0,5\right)^2-6,25\\ =\left(12x^2+11x+0,5\right)^2-\left(2,5\right)^2\\ =\left(12x^2+11x+3\right)\left(12x^2+11x-2\right)\)