Ta có: \(\frac{x+1}{x-3}-\frac{1-x}{x+3}-\frac{2x\left(1-x\right)}{9-x^2}\)
= \(\frac{\left(x+1\right)\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}-\frac{\left(1-x\right)\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}+\frac{2x\left(1-x\right)}{\left(x-3\right)\left(x+3\right)}\)
= \(\frac{x^2+4x+3-x+3+x^2-3x+2x-2x^2}{\left(x-3\right)\left(x+3\right)}\)
= \(\frac{2x+6}{\left(x-3\right)\left(x+3\right)}\)
= \(\frac{2\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}=\frac{2}{x-3}\)
Tính
a/ \(\left(x-3\right)\left(x^2+3x+9\right)\)
b/ \(\left(x-2\right)\left(x^2+2x+4\right)\)
c/ \(\left(x+4\right)\left(x^2-4x+16\right)\)
d/ \(\left(x-3y\right)\left(x^2+3xy+9y^2\right)\)
e/ \(\left(x^2-\frac{1}{3}\right)\left(x^4+\frac{1}{3}x^2+\frac{1}{9}\right)\)
f/ \(\left(\frac{1}{3}x+2y\right)\left(\frac{1}{9}x^2-\frac{2}{3}xy+4y^2\right)\)
Tính
\(1.\left(x+2y\right)^2\)
\(2.\left(2x+3y\right)^2\)
\(3.\left(x+\frac{1}{3}\right)^4\)
\(4.\left(2x+y^2\right)^3\)
\(5.\left(\frac{x}{2}-2y\right)\)
\(6.\left(\sqrt{2x-y}\right)^4\)
\(7.\left(x+1\right)\left(x^2-x+1\right)\)
\(8.\left(x-3\right)\left(x^2+3x+9\right)\)
Rút gọn rồi tính giá trị biểu thức :
a) \(A=\left(x+3\right)^2+\left(x-3\right).\left(x+3\right)-2.\left(x+2\right).\left(x-4\right)\); với x = \(-\frac{1}{2}\)
b) \(B=\left(3x+4\right)^2-\left(x-4\right).\left(x+4\right)-10x\); với x = \(-\frac{1}{10}\)
c) \(C=\left(x+1\right)^2-\left(2x-1\right)^2+3.\left(x-2\right).\left(x+2\right)\); với x = 1
d) \(D=\left(x-3\right).\left(x+3\right)+\left(x-2\right)^2-2x.\left(x-4\right)\); với x = -1
Tính:
1) \(\left(5x^2-2\right)\)\(\left(5x^2+2\right)\)
2) \(\left(2a+\frac{1}{2}\right)+\left(2a-\frac{1}{2}\right)\)
3) \(\left(3x^2-y\right)\left(3x^2+y\right)\)
4) \(\left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right)\)
5) \(\left(\frac{3}{4}x+2\right)\left(\frac{3}{4}x-2\right)\)
6) \(\left(\frac{1}{2}x^2-5y\right)^2\)
7) \(\left(1+3a^2\right)\left(3a^2-1\right)\)
M = \(\frac{x^2}{x^2-2x+1}: \left(\frac{x+1}{x}-\frac{1}{1-x}+\frac{2-x^2}{x^2-x}\right)\)
a,Rút gọn
b,Tìm x để B<1
c,Tìm min M khi x>1
Tính
a/ \(\left(x+\frac{1}{6}y+3\right)^2\)
b/ \(\left(x+y\right)^2+\left(x+y\right)^2\)
c/ \(\left(2x+3\right)^2-\left(x+1\right)^2\)
P= \(\left(\frac{1}{x-2}-\frac{2}{x^2-4}\right):\frac{2x-3}{x^2-4}\)
a tìm ĐKXĐ và Rút gọn
b với x>\(\frac{3}{2}\) tìm GTNN của M=x*P
Rút gọn:
a) \(\left(x+2\right)^2\)- (\(^{^{ }x^2}\)-4x)
b) (2x+3) (2x-3)-\(\left(x+5\right)^2\)
c) \(^{\left(x+1\right)^2}\)-\(\left(x-1\right)^2\)
d) 5(x+2) (x-2)-\(\frac{1}{2}\)\(\left(6-8x\right)^2\)
1) cho các số a,b,c dương thỏa mãn \(a^3+b^3+c^3=3abc\). CMRa=b=c
2) cho x,y,z thỏa mãn xyz=1 và \(x+y+z=\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\). Tính A=\(x^{2018}+2019^y-z^x\)
3) Cho \(\frac{ay-bx}{c}=\frac{cx-az}{b}=\frac{bz-cy}{a}.CMR\left(ax+by+cz\right)^2=\left(x^2+y^2+z^2\right)\left(a^2+b^2+c^2\right)\)