g: Ta có: \(3\left(2x-1\right)\left(3x-1\right)-\left(2x-3\right)\left(9x-1\right)=0\)

\(\Leftrightarrow3\left(6x^2-5x+1\right)-\left(18x^2-29x+3\right)=0\)

\(\Leftrightarrow18x^2-15x+3-18x^2+29x-3=0\)

\(\Leftrightarrow14x=0\)

hay x=0

w

* Trả lời:

\(\left(1\right)\) \(-3\left(1-2x\right)-4\left(1+3x\right)=-5x+5\)

\(\Leftrightarrow-3+6x-4-12x=-5x+5\)

\(\Leftrightarrow6x-12x+5x=3+4+5\)

\(\Leftrightarrow x=12\)

\(\left(2\right)\) \(3\left(2x-5\right)-6\left(1-4x\right)=-3x+7\)

\(\Leftrightarrow6x-15-6+24x=-3x+7\)

\(\Leftrightarrow6x+24x+3x=15+6+7\)

\(\Leftrightarrow33x=28\)

\(\Leftrightarrow x=\dfrac{28}{33}\)

\(\left(3\right)\) \(\left(1-3x\right)-2\left(3x-6\right)=-4x-5\)

\(\Leftrightarrow1-3x-6x+12=-4x-5\)

\(\Leftrightarrow-3x-6x+4x=-1-12-5\)

\(\Leftrightarrow-5x=-18\)

\(\Leftrightarrow x=\dfrac{18}{5}\)

\(\left(4\right)\) \(x\left(4x-3\right)-2x\left(2x-1\right)=5x-7\)

\(\Leftrightarrow4x^2-3x-4x^2+2x=5x-7\)

\(\Leftrightarrow-x-5x=-7\)

\(\Leftrightarrow-6x=-7\)

\(\Leftrightarrow x=\dfrac{7}{6}\)

\(\left(5\right)\) \(3x\left(2x-1\right)-6x\left(x+2\right)=-3x+4\)

\(\Leftrightarrow6x^2-3x-6x^2-12x=-3x+4\)

\(\Leftrightarrow-15x+3x=4\)

\(\Leftrightarrow-12x=4\)

\(\Leftrightarrow x=-\dfrac{1}{3}\)

dấu [] là giá trị tuyệt đối nha

...

\(y'=7\left(-x^2+3x+7\right)^6.\left(-x^2+3x+7\right)'\)

\(=7\left(-2x+3\right)\left(-x^2+3x+7\right)^6\)

a) \(2x\left(3x+1\right)+3x\left(4-2x\right)=7\)

\(\Rightarrow6x^2+2x+12x-6x^2=7\)

\(\Rightarrow14x=7\Rightarrow x=\frac{1}{2}\)

b) \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)

\(72-20x-36x+84=30x-240-6x-84\)

\(\Rightarrow-20x-36x-30x+6x=-240-84-72-84\)

\(-80x=-480\)

x = 6

c) \(\left(3x+2\right).\left(2x+9\right)-\left(x+2\right).\left(6x+1\right)=\left(x+1\right)-\left(x-6\right)\)

\(\Rightarrow6x^2+4x+27x+18-6x^2-12x-x-2=x+1-x+6\) ( chỗ này bn tự phân tích ik nha, mk chỉ đưa ra kp sau khi phân tích thôi, ko thì viết ra dài lắm)

\(\Rightarrow18x+16=7\)

18x = -9

x = -2

18x = 

a) \(\Leftrightarrow4x^2-10x-4x^2-3x=19\\ \Leftrightarrow-13x=19\\ \Leftrightarrow x=-\dfrac{19}{13}\)

b) \(\Leftrightarrow\left(x-7\right)\left(3x+5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=7\\x=-\dfrac{5}{3}\end{matrix}\right.\)

Gọi a,b,c,... cho dễ nhé!

a,\(7+2x=22-3x\)

\(\Leftrightarrow2x+3x=22-7\)

\(\Leftrightarrow5x=15\)

\(\Leftrightarrow x=3\)

Vậy...

b,\(x-12+4x=25+2x-1\)

\(\Leftrightarrow x+4x-2x=25-1+12\)

\(\Leftrightarrow3x=36\)

\(\Leftrightarrow x=12\)

Vậy...

c,\(7-\left(2x+4\right)=-\left(x+4\right)\)

\(\Leftrightarrow7-2x-4=-x-4\)

\(\Leftrightarrow-2x+x=-4+4-7\)

\(\Leftrightarrow-x=-7\)

\(\Leftrightarrow x=7\)

Vậy...

d,\(8x-3=5x+12\)

\(\Leftrightarrow8x-5x=12+3\)

\(\Leftrightarrow3x=15\)

\(\Leftrightarrow x=5\)

Vậy...

e,\(x+2x+3x-19=3x+5\)

\(\Leftrightarrow x+2x+3x-3x=5+19\)

\(\Leftrightarrow3x=24\)

\(\Leftrightarrow x=8\)

Vậy...

f,\(\left(x-1\right)-\left(2x-1\right)=9-x\)

\(\Leftrightarrow x-1-2x+1=9-x\)

\(\Leftrightarrow x-2x+x=9-1+1\)

\(\Leftrightarrow0x=9\) (Vô lý)

Vậy...

a, \(7+2x=22-3x\)

\(\Rightarrow7+2x-22+3x=0\)

\(\Rightarrow5x-15=0\)

\(\Rightarrow5x=15\Rightarrow x=3\)

b, \(x-12+4x=25+2x-1\)

\(\Rightarrow3x-12-24-2x=0\)

\(\Rightarrow x-36=0\Rightarrow x=36\)

c, \(7-\left(2x+4\right)=-\left(x+4\right)\)

\(\Rightarrow7-2x-4=-x-4\)

\(\Rightarrow3-2x+x+4=0\)

\(\Rightarrow-x=-7\Rightarrow x=7\)

d, \(8x-3=5x+12\)

\(\Rightarrow8x-3-5x-12=0\)

\(\Rightarrow3x-15=0\)

\(\Rightarrow3x=15\Rightarrow x=5\)

e, \(x+2x+3x-19=3x+5\)

\(\Rightarrow6x-19-3x-5=0\)

\(\Rightarrow3x-24=0\)

\(\Rightarrow3x=24\Rightarrow x=8\)

f, \(\left(x-1\right)-\left(2x-1\right)=9-x\)

\(\Rightarrow x-1-2x+1-9+x=0\)

(hình như câu này bị sai đề rồi, bạn xem lại đề nhé)

Chúc bạn học tốt!

a: \(\Leftrightarrow6x^2+2x+12x-6x^2=7\)

=>14x=7

hay x=1/2

b: \(\Leftrightarrow72-20x-36x+84=30x-240-6x-84\)

=>-56x+156=24x-324

=>-80x=-480

hay x=6

c: \(\Leftrightarrow6x^2+27x+4x+18-6x^2-x-12x-2=x+1-x+6=7\)

=>18x+16=7

=>18x=-9

hay x=-1/2