Thuc hien phep tinh
(2x-3)3-(2x-1)2x(2x+1)+3(x-9) (x-2)3-(x-1)x(x+1)-13xTuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
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thuc hien phep tinh:1/(x-1)-(x^3-x)/(x^2+1).(1/(x^2-2x+1)+1/(1-x^2))
Giup mk not bai nay , dang gap !
Thuc hien phep tinh:
a, (x -2) ^3 -x(x+1)(x-1) + 6x(x -3)
b, (x-2)(x^2 - 2x +4)(x+2)(x^2 +2x + 4)
Thanks moi ng nha !
1.Thuc hien phep tinh sau:
a,(3x^2-4x+5)(2x^2-4)-2x(3x^3-4x^2+8)
b,(1-3x+x^2)(2-4x)+2x(2x^2+5)
a ) \(\left(3x^2-4x+5\right)\left(2x^2-4\right)-2x\left(3x^3-4x^2+8\right)\)
\(=\left(3x^2-4x+5\right).2x^2-4\left(3x^2-4x+5\right)-6x^4+8x^3-16x\)
\(=6x^4-8x^3+10x^2-12x^2+16x-20-6x^4+8x^3-16x\)
\(=\left(6x^4-6x^4\right)+\left(8x^3-8x^3\right)-\left(12x^2-10x^2\right)+\left(16x-16x\right)-20\)
\(=-2x^2-20\)
b ) \(\left(1-3x+x^2\right)\left(2-4x\right)+2x\left(2x^2+5\right)\)
\(=2\left(1-3x+x^2\right)-4x\left(1-3x+x^2\right)+4x^3+10x\)
\(=2-6x+2x^2-4x+12x^2-4x^3+4x^3+10x\)
\(=\left(4x^3-4x^3\right)+\left(12x^2+2x^2\right)+\left(10x-6x-4x\right)+2\)
\(=14x^2+2\)
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1) Thuc hien phep tinh cong 2 phan thuc \(\dfrac{2x}{x^2-2x+1}+\dfrac{x+1}{x-1}\) duoc ket qua la:
A. \(\dfrac{x^2+2x+1}{\left(x-1\right)^2}\) B. \(\dfrac{x^2+2x-1}{\left(x-1\right)^2}\) C. \(\dfrac{x^2-x-1}{\left(x-1\right)^2}\) D. \(\dfrac{x^2-2x-1}{\left(x-1\right)^2}\)
thuc hien phep tinh :
\(\frac{1}{x-1}-\frac{x^3-x}{x^2+1}\left(\frac{1}{x^2-2x+1}+\frac{1}{1-x^2}\right)\)
Tinh x
a)3.(2x-1)-x.(3x-2)=3x.(1-x)+2
b)2x3.(2x-3)-x2.(4x2-6x+2)=0
thuc hien phep nhan
(x2+x+1).(x3-x2+1)
giup minh nha thu bay minh nop cho thay roi cam on
a) \(3\left(2x-1\right)-x\left(3x-2\right)=3x\left(1-x\right)+2\)
\(6x-3-3x^2+2x=3x-3x^2+2\)
\(6x-3x^2+2x-3x+3x^2=2+3\)
\(5x=5\)
\(x=1\)
b) \(2x^3\left(2x-3\right)-x^2\left(4x^2-6x+2\right)=0\)
\(4x^4-6x^3-4x^4+6x^2-2x^2=0\)
\(-2x^2=0\)
\(x^2=0\)
\(x=0\)
\(\left(x^2+x+1\right)\left(x^3-x^2+1\right)\)
\(=x^5+x^4+x^3-x^4-x^3-x^2+x^2+x+1\)
\(=x^5+x+1\)
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Bai 1: Thuc hien phep tinha) 2x(3x2-5 X+3). b) -2X ( x2+5x-3). c) --1/2x2(2x3-4x+3).Bai 2 Thuc hien phep tinh.a) (2x-1)(x2+5-4). b) -(5x-4)(2x+3). c) (2x-y)(4x2-2xy+y2).d) (3x-4)(x+4)+(5-x)(2x2+3x-1). e)7x(x-4)-(7x+3)(2x2-x+4)
Đọc tiếp
Bai 1: Thuc hien phep tinh
a) 2x(3x2-5 X+3). b) -2X ( x2+5x-3). c) --1/2x2(2x3-4x+3).
Bai 2 Thuc hien phep tinh.
a) (2x-1)(x2+5-4). b) -(5x-4)(2x+3). c) (2x-y)(4x2-2xy+y2).
d) (3x-4)(x+4)+(5-x)(2x2+3x-1). e)7x(x-4)-(7x+3)(2x2-x+4)
a) 2x(3x^2 -5x + 3) = 6x^3 - 10x^2 + 6x
b) -2x(x^2 +5x-3) = -2x^3 - 10x^2 + 6x
c) 2 dấu trừ liền nhau??
bài 2:
a) \(\left(2x-1\right)\left(x^2+1\right)=2x^3-x^2+2x-1\)
b) \(-\left(5x-4\right)\left(2x+3\right)=-\left(10x^2-8x+15x-12\right)=-10x^2-7x+12\)
c) \(\left(2x-y\right)\left(4x^2-2xy+y^2\right)=8x^3-4x^2y-4x^2y+2xy^2+2xy^2-y^3=8x^3-8x^2y+2xy^2-y^3\)
d) \(\left(3x-4\right)\left(x+4\right)+\left(5-x\right)\left(2x^2+3x-1\right)=3x^2+8x-16+10x^2-2x^3+15x-3x^2-5+x=10x^2+24x-21\)
e) \(7x\left(x-4\right)-\left(7x+3\right)\left(2x^2-x+4\right)=7x^2-28x-\left(14x^3+6x^2-7x^2-3x+28x+12\right)=-14x^2+8x^2-53x-12\)
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\(2x\left(3x^2-5x+3\right)\)
\(=2x.3x^2-2x.5x+2x.3\)
\(=6x^3-10x^2+6x\)
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Thuc hien phep tinh
1) \(\frac{1}{x+2}+\frac{3}{x^2-4}+\frac{x-14}{\left(x^2+4x+4\right).\left(x-2\right)}\)
2) \(\frac{x+1}{x-3}-\frac{1-x}{x+3}-\frac{2x.\left(1-x\right)}{9-x^2}\)
thuc hien phep tinh
a.left(dfrac{2x+1}{2x-1}-dfrac{2x-1}{2x+1}right):dfrac{4x}{10x-5}
b.left(dfrac{1}{x^2+1}-dfrac{2-x}{x+1}right):left(dfrac{1}{x}+1-2right)
c.dfrac{1}{x-1}-dfrac{x^3-x}{x^2+1}.left(dfrac{1}{x^2-2x+1}+dfrac{1}{1-x^2}right)
d.left(dfrac{x^2+xy}{x^3+x^2y+xy^2+y^3}+dfrac{y}{x^2+y^2}right):left(dfrac{1}{x-y}-dfrac{2xy}{x^3-x^2y+xy^2-y^3}right)
Đọc tiếp
thuc hien phep tinh
a.\(\left(\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}\right):\dfrac{4x}{10x-5}\)
b.\(\left(\dfrac{1}{x^2+1}-\dfrac{2-x}{x+1}\right):\left(\dfrac{1}{x}+1-2\right)\)
c.\(\dfrac{1}{x-1}-\dfrac{x^3-x}{x^2+1}.\left(\dfrac{1}{x^2-2x+1}+\dfrac{1}{1-x^2}\right)\)
d.\(\left(\dfrac{x^2+xy}{x^3+x^2y+xy^2+y^3}+\dfrac{y}{x^2+y^2}\right):\left(\dfrac{1}{x-y}-\dfrac{2xy}{x^3-x^2y+xy^2-y^3}\right)\)
a: \(=\dfrac{4x^2+4x+1-\left(4x^2-4x+1\right)}{\left(2x-1\right)\left(2x+1\right)}\cdot\dfrac{5\left(2x-1\right)}{4x}\)
\(=\dfrac{8x}{2x+1}\cdot\dfrac{5}{4x}=\dfrac{10}{2x+1}\)
c: \(=\dfrac{1}{x-1}-\dfrac{x\left(x-1\right)\left(x+1\right)}{x^2+1}\cdot\left(\dfrac{x+1-x+1}{\left(x-1\right)^2\cdot\left(x+1\right)}\right)\)
\(=\dfrac{1}{x-1}-\dfrac{x}{x^2+1}\cdot\dfrac{2}{\left(x-1\right)}=\dfrac{x^2+1-2x}{\left(x-1\right)\left(x^2+1\right)}=\dfrac{x-1}{x^2+1}\)
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