\(4x\left(x-2\right)+8x-16=0\\ \Rightarrow4x\left(x-2\right)+8\left(x-2\right)=0\\ \Rightarrow\left(4x+8\right)\left(x-2\right)=0\\ \Rightarrow\left\{{}\begin{matrix}4x+8=0\\x-2=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}4x=0-8=-8\\x=0+2=2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-8:4=-2\\x=2\end{matrix}\right.\)
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=>(x-2)(4x+8)=0
=>x=-2 hoặc x=2
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