a:Sửa đề: \(\dfrac{1}{4}a^2+2ab+4b^2\)
\(=\left(\dfrac{1}{2}a\right)^2+2\cdot\dfrac{1}{2}a\cdot2b+\left(2b\right)^2\)
\(=\left(\dfrac{1}{2}a+2b\right)^2\)
b: Sửa đề:\(y^4-\dfrac{1}{3}y^4+\dfrac{1}{36}\)
\(=y^8-2\cdot y^4\cdot\dfrac{1}{6}+\dfrac{1}{36}\)
\(=\left(y^4-\dfrac{1}{6}\right)^2\)