2: =>(3x-7)^2=25/144=(5/12)^2

=>3x-7=5/12 hoặc 3x-7=-5/12

=>3x=5/12+7=89/12 hoặc 3x=7-5/12=79/12

=>x=89/36 hoặc x=79/36

3:Sửa đề: |2x-3|=|x+1|

=>2x-3=x+1 hoặc 2x-3=-x-1

=>x=4 hoặc 3x=2

=>x=2/3 hoặc x=4

4: =>3x+1=5 hoặc 3x+1=-5

=>3x=4 hoặc 3x=-6

=>x=-2 hoặc x=4/3

1: =>\(2x-7=\sqrt[3]{\dfrac{26}{63}}\)

=>\(2x=\sqrt[3]{\dfrac{26}{63}}+7\)

=>\(x=\dfrac{1}{2}\cdot\left(\sqrt[3]{\dfrac{26}{63}}+7\right)\)

a: 2x-3/2+3/4=-4

=>2x-3/4=-4

=>2x=-13/4

hay x=-13/8

b: \(\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)\cdot\left(\dfrac{-3}{2}-\dfrac{10}{3}\right)=\dfrac{2}{5}\)

\(\Leftrightarrow-\dfrac{2}{3}x-\dfrac{3}{5}=\dfrac{2}{5}:\dfrac{-29}{6}=\dfrac{-2}{5}\cdot\dfrac{6}{29}=\dfrac{-12}{145}\)

=>2/3x+3/5=12/145

=>2/3x=-15/29

hay x=-45/58

c: \(\dfrac{x}{2}-\left(\dfrac{3}{5}x-\dfrac{13}{5}\right)=-\left(\dfrac{7}{10}x+\dfrac{7}{5}\right)\)

=>1/2x-3/5x+13/5=-7/10x-7/5

=>-1/10x+7/10x=-7/5-13/5

=>3/5x=-2

hay x=-2:3/5=-10/3

Đúng thì TICK nka !

2x(x-5)-x(3+2x)= 26

2x^2-10x-3x-2x^2=26

-13x=26 x=-2

Vậy x=-2.

b) giống

tìm x biết:

(3x-1) [- 1/2x+5]=0

1/4+1/3:(2x-1)=-5

[2x+3/5]² - 9/25=0

-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6

[x+1/2]x [2/3-2x]=0

17/2-|2x-3/4|=-7/4

2/3x-1/2x =5/12

(x+1/5)²+17/25=26/25

[x.44/7+3/7].11/5-3/7=-2

3[3x-1/2]+1/9=0

Toán lớp 6Tìm x

 Trả lời  Câu hỏi tương tự

Chưa có ai trả lời câu hỏi này,bạn hãy là người đâu tiên giúp nguyenvanhoang giải bài toán này !

3(3x-1/2)^3+1/9=0

`@` `\text {Ans}`

`\downarrow`

`a)`

`(2x - 1)^2 + 1 = 26`

`\Rightarrow (2x - 1)^2 = 26 - 1`

`\Rightarrow (2x - 1)^2 = 25`

`\Rightarrow (2x - 1)^2 = (+-5)^2`

`\Rightarrow`\(\left[{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}2x=6\\2x=-4\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}x=6\div2\\x=-4\div2\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)

Vậy, `x \in`\(\left\{-2;3\right\}\)

`b)`

`(2x - 4)^3 + 2 = 66`

`\Rightarrow (2x - 4)^3 = 66 - 2`

`\Rightarrow (2x - 4)^3 = 64`

`\Rightarrow (2x - 4)^3 = 4^3`

`\Rightarrow 2x - 4 = 4`

`\Rightarrow 2x = 8`

`\Rightarrow x = 8 \div 2`

`\Rightarrow x = 3`

Vậy, `x = 3`

`c)`

\(7^{x+2}+5\cdot7^{x+1}+15=603\)

`\Rightarrow 7^x . 7^2 + 5 . 7^x . 7 = 603 - 15`

`\Rightarrow 7^x . 7^2 + 35 . 7^x = 588`

`\Rightarrow 7^x . (7^2 + 35) = 588`

`\Rightarrow 7^x . 84 = 588`

`\Rightarrow 7^x = 588 \div 84`

`\Rightarrow 7^x = 7`

`\Rightarrow 7^x = 7^1`

`\Rightarrow x = 1`

Vậy, `x = 1.`

\(#48Cd\)

\(a)\left(2x-1\right)^2+1=26\)

\(\left(2x-1\right)^2=25\)

\(TH1:2x-1=5\)

\(2x=6\)

\(x=3\)

\(TH2:2x-1=-5\)

\(2x=-4\)

\(x=-2\)

Vậy........

\(b)\left(2x-4\right)^3+2=66\)

\(\left(2x-4\right)^3=64=4^3\)

\(2x-4=4\)

\(2x=8\)

\(x=4\)

\(c)7^x+2+5.7^x+1+15=603\)

\(7^x\left(1+5\right)=603-15-1-2\)

\(7^x.6=585\)

Bạn xem lại phần này nhé . x tìm ra không được chẵn lắm á cậu.

Bạn xem lại câu a

a,(2x-1)²+1=26

=>(2x-1)²=26-1=25=5²

=>2x-1=5 và -5

=>x=(5+1):2=3 và x=(-5+1):2=-2

b,(2x-4)³+2=66

=>(2x-4)³=66-2=64=4³

=>2x-4=4

=>x=(4+4):2=4

c,7^x+2+5\(\cdot\)7^x+1+15=603

=>7^x\(\cdot\)7²+5\(\cdot\)7^x\(\cdot\)7=603-15=588

=>7^x(7²+5\(\cdot\)7)=588

=>7^x\(\cdot\)84=588

=>7^x=588:84=7

=>x=1

Gỉai:

a, x=0,5

b,55/6

a, 51

b, 60 

c, 245

mk làm lun nha

a, 2x^2-6x-3x-2x^2=26

-9x=26

x=-26/9

b,x^2+2.x.4+16-(x^2-1)=16

x^2+8x+16-x^2+1=16

8x=-1

x=-1/8

c,(2x)^2-2.2x.1+1-4(x^2-7^2)=0

4x^2-4x+1-4x^2+196=0

-4x=-197

x=197/4

d,x^2-5x-4x+20=0

-9x=-20

x=20/9 

**** cho mk nha