\(=\left(x+2\right)\left(5x-3-2x\right)\)

1) \(x\left(x-1\right)+\left(1-x\right)^2\)

\(=x\left(x-1\right)+\left(x-1\right)^2\)

\(=\left(x-1\right)\left(x+x-1\right)\)

\(=\left(x-1\right)\left(2x-1\right)\)

2) \(2x\left(x-2\right)-\left(x-2\right)^2\)

\(=\left(x-2\right)\left[2x-\left(x-2\right)\right]\)

\(=\left(x-2\right)\left(2x-x+2\right)\)

\(=\left(x-2\right)\left(x+2\right)\) 

3) \(3x\left(x-1\right)^2-\left(1-x\right)^3\)

\(=3x\left(x-1\right)^2+\left(x-1\right)^3\)

\(=\left(x-1\right)^2\left(3x+x-1\right)\)

\(=\left(x-1\right)^2\left(4x-1\right)\)

4) \(3x\left(x+2\right)-5\left(x+2\right)^2\)

\(=\left(x+2\right)\left[3x-5\left(x+2\right)\right]\)

\(=\left(x+2\right)\left(3x-5x-10\right)\)

\(=\left(x+2\right)\left(-2x-10\right)\)

\(=-2\left(x+2\right)\left(x+5\right)\)

mình biết nội quy rồi nên đưng đăng nội quy

ai chơi bang bang 2 kết bạn với mình

mình có nick có 54k vàng đang góp mua pika 

ai kết bạn mình cho

      \(x^3-2x-4\)

\(=x^3-2x^2+2x^2-4x+2x-4\)

\(=x^2\left(x-2\right)+2x\left(x-2\right)+2\left(x-2\right)\)

\(=\left(x^2+2x+2\right)\left(x-2\right)\)

Đặt x^2+2x=t =>3t^2-2t-1=3t^2-3t+t-1=3t(t-1)+(t-1)=(t-1)(3t+1)

=>(x^2+2x-1)(3x^2+6x+1)

a) \(x^2-2x-4y^2-4y=\left(x^2-2x+1\right)-\left(4y^2+4y+1\right)\)

\(=\left(x-1\right)^2-\left(2y+1\right)^2=\left(x-1-2y-1\right)\left(x-1+2y+1\right)\)

\(=\left(x-2y-3\right)\left(x+2y\right)\)

b) \(x^2-4x^2y^2+y^2+2xy=\left(x^2+2xy+y^2\right)-4x^2y^2\)

\(=\left(x+y\right)^2-4x^2y^2=\left(x+y-2xy\right)\left(x+y+2xy\right)\)

c) \(x^6-x^4+2x^3+2x^2=\left(x^6+2x^3+1\right)-\left(x^4-2x^2+1\right)\)

\(=\left(x^3+1\right)^2-\left(x^2-1\right)^2=\left(x^3+1-x^2+1\right)\left(x^3+1+x^2-1\right)=x^2\left(x^3-x^2+2\right)\left(x+1\right)\)

d) \(x^3+3x^2+3x+1-8y^3=\left(x+1\right)^3-8y^3=\left(x+1-2y\right)\left(x^2+2x+1+2xy+2y+4y^2\right)\)

d) x^3 + 2x^2 + 3x + 1 

Bó tay  

e) x^2 - 2x - 4y^2 - 4y 

= x^2 - 2x + 1 - 4y^2 - 4y - 1 

= ( x + 1 )^2 - ( 4y^2 + 4y + 1 )

= (  x + 1 )^2 - ( 2y + 1 )^2 

= ( x+ 1 - 2y - 1 )( x + 1 + 2y + 1 )

= ( x - 2y )(x + 2y +2 )

4x2 là gì 

\(x^2-2x-4y^2-4y\)

\(=\left(x^2-2x+1\right)-\left(4y^2+4y+1\right)\)

\(=\left(x-1\right)^2-\left(2y+1\right)^2\)

\(=\left(x-1-2y-1\right)\left(x-1+2y+1\right)\)

\(=\left(x-2y-2\right)\left(x+2y\right)\)

hk tốt

^^

Đặt \(x^4-2x^3-x^2-2x+1=\left(x^2+ax+1\right)\left(x^2+bx+1\right)=x^4+bx^3+x^2+ãx^3+abx^2+ax+x^2+bx+1\)

=> \(x^4-2x^3-x^2-2x+1=x^4+\left(a+b\right)x^3+\left(ab+2\right)x^2+\left(a+b\right)x+1\)

=> \(\hept{\begin{cases}a+b=-2\\ab+2=-1\\a+b=-2\end{cases}}\Rightarrow a=-3;b=1\)

       \(x^4-2x^3-x^2-2x+1\)

\(=\left(x^4+x^3+x^2\right)-3x^3-3x^2-3x+\left(x^2+x+1\right)\)

\(=x^2\left(x^2+x+1\right)-3x\left(x^2+x+1\right)+\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^2-3x+1\right)\)

Chúc bạn học tốt.

8: \(=\left(x-2y\right)\cdot x\cdot\left(x+3\right)\)

9: \(=\left(5x+2\right)\left(x-3\right)-x\left(x-3\right)\)

\(=\left(x-3\right)\left(4x+2\right)\)

=2(2x+1)(x-3)

3: \(=2\left(x+2\right)\left(25x-15-x\right)\)

\(=2\left(x+2\right)\left(24x-15\right)\)

=6(x+2)(8x-5)