( 5x- 24 ) x 38 = 2 x 311
Phân tích đa thức thành nhân tử:
1, x^3-x+y^3-4
2, 4x^2-y^2+4x+1
3, x^4+2x^3+x^2
4, x^2+5x-6
5, 7x-6x^2-2
6, 5x^2+5xy-x-y
7, 2x^2+3x-5
8,x^4-5x^2+4
9, x^3-5x^2+45-9x
10, x^4-2x^3-2x^2-2x-3
11, 81x^4+4
12,x^5+x+1
13, x^4+6x^3+7x^2-6x+1
14, x(x+4)(x+6)(x+10)+128
2: =(2x+1)^2-y^2
=(2x+1+y)(2x+1-y)
3: =x^2(x^2+2x+1)
=x^2(x+1)^2
4: =x^2+6x-x-6
=(x+6)(x-1)
5: =-6x^2+3x+4x-2
=-3x(2x-1)+2(2x-1)
=(2x-1)(-3x+2)
6: =5x(x+y)-(x+y)
=(x+y)(5x-1)
7: =2x^2+5x-2x-5
=(2x+5)(x-1)
8: =(x^2-1)*(x^2-4)
=(x-1)(x+1)(x-2)(x+2)
9: =x^2(x-5)-9(x-5)
=(x-5)(x-3)(x+3)
c) 2x + 36 : 12 = 5 3 d) ( 5x – 2 4 ) . 38 = 2. 311
trả lời giúp mình ạ
a: \(2x+36:12=5\cdot3\)
\(\Leftrightarrow2x+3=15\)
hay x=6
`2x + 36 : 12 = 53`
`<=>2x + 3 = 53`
`<=>2x = 50`
`<=> x = 25`
d)
`(5x-24).38=2.311`
`<=> 5x-24 = 311/19`
`<=> x = (311/19 + 24) :5`
`<=> x = 767/95`
c) (7x + x – 28) :100 – 38 = 9.
d) 936 – (4x + 5x ) = 900
e) 280 + 78 : (135 – x :7) =286
f) x – 18 :3 = 16 + 16 : 23.
g) (3x – 10) : 10 = 20.
h) (3x – 24 ).73= 2.74
i) 123 – 5.( x + 4) = 38.
k) [(6x – 72) :2 – 84].28 = 5628.
m) 2x – 138 = 23.32.
n) [(10 - x).2 + 7]:3 -2 = 3.
Trình bày kết quả rõ ràng nha cảm ơn mọi người rất nhiều❤❤❤
c) (7x + x – 28) :100 – 38 = 9
<=> 8x - 28 = 4700
<=> x = 591
d) 936 – (4x + 5x ) = 900
<=> 9x = 36
<=> x = 4
a) \(\left(3x+2\right)^2-\left(3x-2\right)^2=5x+38\)
\(\Leftrightarrow\left[\left(3x+2\right)-\left(3x-2\right)\right]\left[\left(3x+2\right)+\left(3x-2\right)\right]=5x+38\)
\(\Leftrightarrow\left(3x+2-3x+2\right)\left(3x+2+3x-2\right)=5x+38\)
\(\Leftrightarrow4\cdot6x=5x+38\)
\(\Leftrightarrow24x-5x=38\)
\(\Leftrightarrow19x=38\Leftrightarrow x=\dfrac{38}{19}=2\)
Vậy \(S=\left\{2\right\}\)
b) \(\left(x+1\right)\left(x^2-2x+1\right)-2x=2\left(x-1\right)\left(x+1\right)\)
\(\Leftrightarrow x^3-2x^2+x+x^2-2x+1-2x=2\left(x^2-1\right)\)
\(\Leftrightarrow x^3-2x^2+x+x^2-2x+1-2x=2x^2-2\)
\(\Leftrightarrow x^3-2x^2+x+x^2-2x+1-2x-2x^2+2=0\)
\(\Leftrightarrow x^3-3x^2-3x+3=0\)
PT vô nghiệm , không tìm được x
Vậy \(S=\varnothing\)
c) \(3\left(x-2\right)^2+9\left(x-1\right)=3\left(x^2+x-3\right)\)
\(\Leftrightarrow3\left(x^2-2x+4\right)+9\left(x-1\right)=3\left(x^2+x-3\right)\)
\(\Leftrightarrow3x^2-6x+12+9x-9=3x^2+3x-9\)
\(\Leftrightarrow3x^2-6x+12+9x-9-3x^2-3x+9=0\)
\(\Leftrightarrow0x+12=0\)
PT vô nghiệm
Vậy \(S=\varnothing\)
Câu cuối tương tự
Bài 2:
a) 37 x 7 - 17 x 11 + 13 x 37 + 17 x 21
b) 55 x 52 : 54 - 28 : 24
c) 311 x 12 + 312 x 5 - 314
`#040911`
`a)`
\(37 \times 7 - 17 \times 11 + 13 \times 37 + 17 \times 21\)
`= 37 \times (7 + 13) + 17 \times (21 - 11)`
`= 37 \times 20 + 17 \times 10`
`= 10 \times (37 \times 2 + 17)`
`= 10 \times 91`
`= 910`
`b)`
\(5^5 \times 5^2 \div 5^4 - 2^8 \div 2^4\)
`=`\(5^{5+2-4}-2^{8-4}\)
`= 5^3 - 2^4`
`= 125 - 16`
`= 109`
`c)`
\(3^{11}\times12+3^{12}\times5-3^{14}\)
`=`\(3^{11}\times\left(12+3\times5-3^3\right)\)
`=`\(3^{11}\times\left(12+15-27\right)\)
`=`\(3^{11}\times0=0\)
a) = 259 - 187 + 481 + 357
= 910
b) = 57 : 54 - 24
= 53 - 24
= 125 - 16
= 109
Bài 2:
a, 37 x 7 - 17 x 11 + 13 x 37 + 17 x 21
= ( 37 x 7 + 13 x 37) + ( 17 x 21 - 17 x 11)
= 37 x ( 7 + 13) + 17 x ( 21 - 11)
= 37 x 20 + 17 x 10
= 740 + 170
= 910
b, 55 x 52 : 54 - 28 : 24
= 57: 54 - 24
= 53 - 16
= 125 - 16
= 109
c, 311 x 12 + 312 x 5 - 314
311 x ( 12 + 3 x 5 - 133)
= 311 x ( 12 + 15 - 33)
= 311 x ( 27 - 27)
= 311 x 0
= 0
a;(x^2-5x)^2+10(x^2-5x)+24=0 b;(x^2+5x)-2(x^2+5x)=24