\(\left(0,5\times m-0,75\right):4=2,5\)

\(0,5\times m-0,75=2,5\times4\)

\(0,5\times m-0,75=10\)

\(0,5\times m=10+0,75\)

\(0,5\times m=10,75\)

\(m=10,75:0,5\)

\(m=21,5\)

`@` `\text {Ans}`

`\downarrow`

`(0,5 \times m - 0,75) \div 4 = 2,5`

`=> 0,5 \times m - 0,75 = 2,5 \times 4`

`=> 0,5 \times m - 0,75 = 10`

`=> 0,5 \times m = 10 + 0,75`

`=> 0,5 \times m = 10,75`

`=> m = 10,75 \div 0,5`

`=> m =21,5`

Vậy, `m=21,5`.

\(\left(\dfrac{1}{2}+1\right)\times\left(\dfrac{1}{3}+1\right)\times\left(\dfrac{1}{4}+1\right)\times\left(\dfrac{1}{5}+1\right)\times\left(\dfrac{1}{6}+1\right)\)

\(=\dfrac{3}{2}\times\dfrac{4}{3}\times\dfrac{5}{4}\times\dfrac{6}{5}\times\dfrac{7}{6}\)

\(=\dfrac{3\times4\times5\times6\times7}{2\times3\times4\times5\times6}\)

\(=\dfrac{7}{2}\)

( 

2

1

 +1)×( 

3

1

 +1)×( 

4

1

 +1)×( 

5

1

 +1)×( 

6

1

 +1)

=

3

2

×

4

3

×

5

4

×

6

5

×

7

6

= 

2

3

 × 

3

4

 × 

4

5

 × 

5

6

 × 

6

7

=

3

×

4

×

5

×

6

×

7

2

×

3

×

4

×

5

×

6

= 

2×3×4×5×6

3×4×5×6×7

=

7

2

= 

2

7

\(a\times2+a:2=5\)

\(a\times2+a\times\dfrac{1}{2}=5\)

\(a\times\left(2+\dfrac{1}{2}\right)=5\)

\(a\times\dfrac{5}{2}=5\)

\(a=5:\dfrac{5}{2}\)

\(a=2\)

Vậy \(a=2\)

\(2,25-\left(5\times a-125:5\right)=0\)

\(2,25-5\times a+25=0\)

\(27,25-5\times a=0\)

\(5\times a=27,25\)

\(a=27,25:5\)

\(a=5,45\)

Vậy a=5,45

ta có \(\frac{x}{y}=\frac{7}{20}\Rightarrow\frac{x}{7}=\frac{y}{20}\Rightarrow\frac{x}{14}=\frac{y}{40}\Rightarrow\frac{2x}{28}=\frac{5y}{200}\left(1\right)\)

       \(\frac{y}{z}=\frac{5}{8}\Rightarrow\frac{y}{5}=\frac{z}{8}\Rightarrow\frac{y}{40}=\frac{z}{64}\Rightarrow\frac{5y}{200}=\frac{2z}{128}\left(2\right)\)

          \(\left(1\right)\&\left(2\right)\Rightarrow\frac{2x+5y-2z}{28+200-128}=\frac{100}{100}=1\)

                       \(\frac{2x}{28}=1\Rightarrow x=\frac{28.1}{2}=14\)

                          \(\frac{5y}{200}=1\Rightarrow y=\frac{200.1}{5}=40\)

                          \(\frac{2z}{128}=1\Rightarrow z=\frac{128.1}{2}=64\)

\(\frac{x}{y}=\frac{7}{20};\frac{y}{z}=\frac{5}{8}\Rightarrow\frac{x}{7}=\frac{y}{20};\frac{y}{5}=\frac{z}{8}\Rightarrow\frac{x}{35}=\frac{y}{100};\frac{y}{100}=\frac{z}{160}\Rightarrow\frac{x}{35}=\frac{y}{100}=\frac{z}{160}\)

áp dụng tính chất của dãy tỉ số bằng nhau ta có:

\(\frac{x}{35}=\frac{y}{100}=\frac{z}{160}=\frac{2x+5y-2z}{2.35+5.100-2.160}=\frac{100}{250}\)= số lẽ sai đề     

Ta có:

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=\frac{2x-2}{4}=\frac{3y-6}{9}\)

Áp dụng tính chất của dãy tỉ số = nhau ta có:

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{\left(2x-2\right)+\left(3y-6\right)-\left(z-3\right)}{4+9-4}\)

\(=\frac{\left(2x+3y-z\right)-5}{9}=\frac{50-5}{9}=\frac{45}{9}=5\)

\(\Rightarrow\begin{cases}x-1=2.5=10\\y-2=3.5=15\\z-3=4.5=20\end{cases}\)\(\Rightarrow\begin{cases}x=11\\y=17\\z=23\end{cases}\)

Vậy x = 11; y = 17; z = 23

g: x:(-7)-6=-15

=>x:(-7)=-15+6=-9

=>\(x=\left(-9\right)\left(-7\right)=9\cdot7=63\)

h: \(x:12+\left(-12\right)=-37\)

=>\(x:12=\left(-37\right)-\left(-12\right)=-37+12=-25\)

=>\(x=-25\cdot12=-300\)

i: \(x:\left(-25\right)+81=85\)

=>\(x:\left(-25\right)=85-81=4\)

=>\(x=4\cdot\left(-25\right)=-100\)

k: \(\left(-31\right)\cdot x=-93\)

=>\(x=\dfrac{-93}{-31}=\dfrac{93}{31}\)

=>x=3

l: 5x+1=-4

=>5x=-4-1=-5

=>\(x=-\dfrac{5}{5}=-1\)

m: \(\left(-12\right)\cdot x+34=10\)

=>\(\left(-12\right)\cdot x=10-34=-24\)

=>12x=24

=>x=24/12=2

4 5/7 + 3,25 + 2/7 - 1/4

= 4 + 5/7 + 13/4 + 2/7 - 1/4

= 4 + (5/7 + 2/7) + (13/4 - 1/4)

= 4 + 1 + 3

= 8

Ta có: 

\(\dfrac{5}{7}+3,25+\dfrac{2}{7}-\dfrac{1}{4}\)

\(=\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\left(3,25-0,25\right)\)

\(=\dfrac{7}{7}+3\)

\(=1+3\)

\(=4\)

Vậy: \(4=\dfrac{5}{7}+3,25-\dfrac{2}{7}-\dfrac{1}{4}\)

` @ L I N H `

4 5/7 + 3,25 + 2/7 - 1/4

= 4 + 5/7 + 13/4 + 2/7 - 1/4

= 4 + (5/7 + 2/7) + (13/4 - 1/4)

= 4 + 1 + 3

= 8

\(5x^2+10y^2-6xy-4x-2y+3\)

\(=\left(x^2-6xy+9y^2\right)+\left(4x^2-4x+1\right)+\left(y^2-2y+1\right)+1\)

\(=\left(x-3y\right)^2+\left(2x-1\right)^2+\left(y-1\right)^2+1>0\)  (đpcm)

p/s: chúc bạn học tốt

Hi hi mik cảm ơn bn và mik cx chúc bn học tốt nha!!!^-^!!!