`9/7 : 7/8 + 2^3 . 2 - 7/4 : 5/8`

`= 9/7 . 8/7 + 2^4 - 7/4 . 8/5`

`= 72/49 + 16 - 56/20`

`= 72/49 + 16/1 - 14/5`

`= 72/49 + 784/49 - 14/5`

`= 856/49 - 14/5`

`= 4280/245 - 686/245`

`= 3594/245`

`#` `\text{DKhanhhqlv}`

\(\dfrac{9}{7}:\dfrac{7}{8}+2^3.2-\dfrac{7}{4}:\dfrac{5}{8}\\ =\dfrac{72}{49}+8.2-\dfrac{14}{5}\\ =\dfrac{72}{49}+16-\dfrac{14}{5}\\ =\dfrac{856}{49}-\dfrac{14}{5}\\ =\dfrac{3594}{245}\)

bài này làm rồi nhé

`9/4 :7/+2^3 * 2-7/4 :5/8`

`= 9/4 * 8/7 + 8*2-7/4 * 8/5`

`= 18/7 + 16 - 14/5`

`= 130/7 -14/5`

`= 552/35`

`9/4 : 7/8 + 2^3 . 2 - 7/4 : 5/8`

`= 9/4 xx 8/7 + 8 . 2 - 7/4 xx 8/5`

`= 18/7 + 16 + 14/5`

`= 130/7 + 14/5`

`=650/35 + 98/35`

`=748/35`

`@ `\(\text{BNg BaooTrannn}\)

Đề bài yêu cầu gì?

a) \(\dfrac{\left(-3\right)^7\cdot2^8}{6^7}\)

\(=\dfrac{-1\cdot3^7\cdot2^8}{\left(2\cdot3\right)^7}=\dfrac{-1\cdot3^7\cdot2^7\cdot2}{2^7\cdot3^7}=-1\cdot2=-2\)

b) \(\dfrac{-3\cdot7^4+7^3}{7^5\cdot6-7^3\cdot2}\)

\(=\dfrac{-3\cdot7\cdot7^3+7^3}{7^3\cdot7^2\cdot6-7^3\cdot2}\)

\(=\dfrac{7^3\left(-3\cdot7+1\right)}{7^3\left(7^2\cdot6-2\right)}=\dfrac{-3\cdot7+1}{7^2\cdot6-2}\)

\(=\dfrac{-21+1}{294-2}=\dfrac{-20}{290}=\dfrac{-2}{29}\)

b) \(\dfrac{5^3\cdot3^5}{5^3\cdot0,5+125\cdot2\cdot5}\)

\(=\dfrac{5^3\cdot3^5}{5^3\cdot0,5+5^3\cdot2\cdot5}=\dfrac{5^3\cdot3^5}{5^3\left(0,5+2\cdot5\right)}\)

\(=\dfrac{3^5}{0,5+2\cdot5}=\dfrac{243}{10,5}=\dfrac{162}{7}\)

Mk sửa đề nha :

\(C=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+\frac{12}{7}\)

   \(=\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)

   \(=\frac{-5}{7}.1+\frac{12}{7}\)

   \(=\frac{-5}{7}+\frac{12}{7}\)

   \(=1\)

Study well ! >_<

đây là toán mà

=2011^2011.(7^2-3.2^4-1)

=2011^2011.(49-3.16-1)

=2011^2011.(49-48-1)

=2011^2011.0

=0

Vote nhá