X x 9.6 + X x 40% = 2.18

X x (9.6+40%) = 2.18

X x 10 = 2.18

X = 2.18 : 10

X = 0.218

1+x=2

x=2-1

x=1

=))))))

a, 53 x 39 + 47 x 39 + 53 x 21- 47 x 21

= ( 53 + 47 ) x 39 + ( 53 - 47 ) x 21

= 100 x 39 + 6 x 21

= 3900 + 126

= 4026

Mấy phần khác bạn tự làm đi

a, [39x( 47+53 )] + [ 21x( 53+47)]

= [ 39x100 ] + [ 21x100 ]

= 3900 + 2100

=6000

d,ta có : 1/1.2 = 1-1/2

             1/2.3=1/2 - 1/3

             1/3.4=1/3 - 1/4

             ....

             1/56.57=1/56 - 1/57

             1/57.58= 1/57 - 1/58 

=> = 1 - 1/2 + 1/2 -1/3 + 1/3 - 1/4 + ... + 1/56 - 1/57 + 1/57 -1/58

     = 1 - 1/58

     = 57/58

e, 89 x 5 + 89 x 1 + 89 x 4

= 89 x ( 5 + 1 + 4 )

= 89 x 10

=890

nhớ cho mình còn mấy phần khác thì lười không muốn làm. 

\(\left[\left(X-\dfrac{1}{2}\right)\div6+4\right]\times\dfrac{2}{3}=\dfrac{3}{5}\times\dfrac{40}{6}\)

\(\left[\left(X-\dfrac{1}{2}\right)\div6+4\right]\times\dfrac{2}{3}=4\)

\(\left[\left(X-\dfrac{1}{2}\right)\div6+4\right]=4\times\dfrac{3}{2}\)

\(\left(X-\dfrac{1}{2}\right)\div6+4=6\)

\(\left(X-\dfrac{1}{2}\right)\div6=6-4\)

\(\left(X-\dfrac{1}{2}\right)\div6=2\)

\(\left(X-\dfrac{1}{2}\right)=2\times6\)

\(X-\dfrac{1}{2}=12\)

\(X=\dfrac{24}{2}+\dfrac{1}{2}\)

\(X=\dfrac{23}{2}\)

[(\(x-\dfrac{1}{2}\)):6 + 4]  \(\times\) \(\dfrac{2}{3}\) = \(\dfrac{3}{5}\) \(\times\) \(\dfrac{40}{6}\)

[(\(x\) - \(\dfrac{1}{2}\)):6 + 4] \(\times\) \(\dfrac{2}{3}\) = 4

(\(x-\dfrac{1}{2}\)): 6 + 4 = 4 : \(\dfrac{2}{3}\)

(\(x\) - \(\dfrac{1}{2}\)) : 6 + 4 = 6

(\(x\) - \(\dfrac{1}{2}\)) : 6       =  6 - 4

(\(x\) - \(\dfrac{1}{2}\)) : 6      = 2

\(x-\dfrac{1}{2}\)            =  2 \(\times\) 6

\(x-\dfrac{1}{2}\)            = 12

\(x\)                    = 12 + \(\dfrac{1}{2}\)

\(x\)                    = \(\dfrac{25}{2}\)

Em cần trợ giúp gì vậy em. cô không thấy đề bài em ạ

Sai đề :

2 x 53 x 12 + 4 x 6 x 87 - 3 x 8 x 40

= 12 x 2 x 53 + 4 x 6 x 87 - 3 x 8 x 40

= 24 x 53 + 24 x 87 - 24 x 40

= 24 x ( 53 + 87 - 40 )

= 24 x ( 140 - 40 )

= 24 x 100

= 2400

Sai đề :

2 x 53 x 12 + 4 x 6 x 87 - 3 x 8 x 40

= 12 x 2 x 53 + 4 x 6 x 87 - 3 x 8 x 40

= 24 x 53 + 24 x 87 - 24 x 40

= 24 x ( 53 + 87 - 40 )

= 24 x ( 140 - 40 )

= 24 x 100

= 2400

Sai đề :

2 x 53 x 12 + 4 x 6 x 87 - 3 x 8 x 40

= 12 x 2 x 53 + 4 x 6 x 87 - 3 x 8 x 40

= 24 x 53 + 24 x 87 - 24 x 40

= 24 x ( 53 + 87 - 40 )

= 24 x ( 140 - 40 )

= 24 x 100

= 2400

\(\frac{75}{100}+\frac{3}{4}\cdot29+75\%\cdot30+0.75\cdot40\)

\(=0,75+0,75\cdot29+0,75\cdot30+0,75\cdot40\)

\(=0,75\cdot\left(1+29+30+40\right)\)

\(=0,75\cdot100\)

\(=75\)

\(\left(2x+1\right)^2-3\left(x-1\right)^2-\left(x+1\right)\left(x-1\right)\)

\(=\left(2.\left(-\frac{1}{2}\right)+1\right)^2-3\left(-\frac{1}{2}-1\right)^2-\left(-\frac{1}{2}+1\right)\left(-\frac{1}{2}-1\right)\)

\(=-3\left(-\frac{9}{4}\right)-\frac{1}{2}.\left(-\frac{3}{2}\right)\)

\(=\frac{27}{4}+\frac{3}{4}=\frac{31}{4}\)

còn đâu tự lm nha ! 

\(\Leftrightarrow\left(x^4-20x^2+100\right)-36=0\)

\(\Leftrightarrow\left(x^2-10\right)^2=36\)

\(\Leftrightarrow\left[{}\begin{matrix}x^2-10=6\\x^2-10=-6\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x^2=16\\x^2=4\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\pm4\\x=\pm2\end{matrix}\right.\)

\(x^4-20x^2+64=0\)

Đặt \(t=x^2\)

\(PT\Leftrightarrow t^2-20t+64=0\\ \Leftrightarrow t^2-16t-4t+64=0\\ \Leftrightarrow t\left(t-16\right)-4\left(t-16\right)=0\\ \Leftrightarrow\left(t-16\right)\left(t-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}t-16=0\\t-4=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}t=16\\t=4\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x^2=16\\x^2=4\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\pm\sqrt{16}\\x\pm\sqrt{4}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\pm4\\x=\pm2\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=4\\x=-4\\x=2\\x=-2\end{matrix}\right.\\ Vậyx\in\left\{4;-4;2;-2\right\}\)

\(\Leftrightarrow x^3\left(x-2\right)+10x\left(x-2\right)=0\)

\(\Leftrightarrow x\left(x-2\right)\left(x^2+10\right)=0\)

\(\Leftrightarrow x\left(x-2\right)=0\) (do \(x^2+10>0;\forall x\))

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

`x^4-2x^3+10x^2-20x=0`

`<=>x^3(x-2)+10x(x-2)=0`

`<=>(x^3+10x)(x-2)=0`

`<=>x(x^2+10)(x-2)=0`

`<=>`$\left[\begin{matrix} x=0\\ x^2+10=0\\x-2=0\end{matrix}\right.$

`<=>`$\left[\begin{matrix} x=0\\ x^2=-10 \ \rm(loại) \\x=2\end{matrix}\right.$

Vậy `S={0;2}`

Ta có: \(x^4-2x^3+10x^2-20x=0\)

\(\Leftrightarrow x^3\left(x-2\right)+10x\left(x-2\right)=0\)

\(\Leftrightarrow x\left(x-2\right)\left(x^2+10\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

2x-2016=2018

2x        =2018+2016

2x        =4034

x          =4034:2

x          =2017

3^x +1=82

3^x     =82-1

3^x     =81

3^x     =3⁴

x      =4

20x-11=20x+2x-12

20x-11=x(20+2)-12

20x-11=22x-12

20x    =22x-12+11

20x    =22x-1

22x-2x=22x-1

2x       =1

x         =1:2

x         =0,5

(x+1)+(x+2)+(x+3)+(x+4)=26

x+x+x+x+1+2+3+4        =26

4x+10                           =26

4x                                =26-10

4x                                =16

x                                  =16:4

x                                  =4