D = 16^8 - 1 / (2 + 1) (2^2 + 1) (2^4 + 1) (2^8 + 1) (2^16 + 1)
BP
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rút gọn biểu thức
a) A=16^8 -1/(2+1)(2^2+1)(2^4+1)(2^8+1(3^16+1)
b) B=(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)/9^16-1
giúp mk vs ah mk đang cần gấp ah
a) Ta có: \(A=\dfrac{16^8-1}{\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}\)
\(=\dfrac{2^{32}-1}{\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}\)
\(=\dfrac{2^{32}-1}{\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}\)
\(=\dfrac{2^{32}-1}{\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)}\)
\(=\dfrac{2^{32}-1}{\left(2^{16}-1\right)\left(2^{16}+1\right)}\)
\(=\dfrac{2^{32}-1}{2^{32}-1}=1\)
b) Ta có: \(B=\dfrac{\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)}{9^{16}-1}\)
\(=\dfrac{\left(3^2-1\right)\cdot\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)}{2\cdot\left(3^{32}-1\right)}\)
\(=\dfrac{\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)}{2\cdot\left(3^{32}-1\right)}\)
\(=\dfrac{\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)}{2\left(3^{32}-1\right)}\)
\(=\dfrac{\left(3^{16}-1\right)\left(3^{16}+1\right)}{2\left(3^{32}-1\right)}=\dfrac{1}{2}\)
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Tính nhanh
C=50^2-49^2+48^2-47^2+...+2^2-1^2
D=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
E=(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
c;=(50-49)(50+49)+(48-47)(48+47)+.............+(2+1)(2-1)
=50+49+48+............+1
=(50+1)50=2550:2=1275
d;=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1
e;=(3-1)(3+1)(3^2+1)...........(3^16+1)
=(3^2-1)(3^2+1)..............(3^16+1)
=(3^16-1)(3^16+1)=3^32-1
tu tinh ket qua luy thua tao khong thua hoi dau
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Rút gọn biểu thức:
A) x – ( x/2 + 1/2 )
B) (x/2 – 1/2) : 2 + 1/2
C) (x/2 – 1/2) – (x/4 + 1/4)
D) (x/4 – 3/4) : 2 + 1/2
E) (x/4 – 3/4) – (x/8 + 1/8)
F) (x/8 – 7/8) : 2 + 1/2
G) (x/8 – 7/8) – (x/16 + 1/16)
H) (x/16 – 15/16) : 2 + 1/2
I) (x/16 – 15/16) – (x/32 + 1/32)
2 tính : a) 1+1/4+1/8+1/16 =
=
b) 2-1/8-1/12-1/16 =
=
c) 4/99 x 18/5 : 12/11 + 3/5 =
=
d) ( 1-3/4 ) x ( 1+ 1/3 ) : ( 1- 1/3 ) =
=
a) 1 + 1/4 + 1/8 + 1/16
= 16/16 + 4/16 + 2/16 + 1/16
= 23/16
b) 2 - 1/8 - 1/12 - 1/16
= 96/48 - 6/46 - 4/48 - 3/48
= 83/48
c) 4/99 × 18/5 : 12/11 + 3/5
= 8/55 : 12/11 + 3/5
= 2/15 + 3/5
= 2/15 + 9/15
= 11/15
d) (1 - 3/4) × (1 + 1/3) : (1 - 1/3)
= 1/4 × 4/3 : 2/3
= 1/3 : 2/3
= 2
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1 + 1/4 + 1/8 + 1/16
= 16 + 4 + 2 + 1 / 16
=23/16
2-1/8-1/12-1/16
= 96 - 6 - 4 - 3 / 48
= 83 / 48
4/99 x 18/5 : 12 /11 + 3/5
= 4/99 x 18/5 x 11/12 + 3/5
= 2/15 + 3/5
= 11/15
(1 - 3/4) x (1+1/3) : (1-1/3)
= 1/4 x 4/3 : 2/3
= 1/4 x 4/3 x 3/2
= 1/2
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Tính (16*8-1)/(2+1)(2*2+1)(2*4+1)(2*8+1)(2*16+1)
Giúp mk vs 😉😉
dưới mẫu nè: (2+1)(2^2+1)(2*4+1)(2*8+1)(2*16+1)=(2*4-1)(2*4+1)(2*8+1)(2*16+1)(*vì 2+1=2*2-1)
cứ như thế thì được: 2*32-1
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Ta có : \(\frac{16^8-1}{\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}\)
\(=\frac{\left(2^4\right)^8-1}{\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}\)
\(=\frac{2^{32}-1}{\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}\)
\(=\frac{2^{32}-1}{\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}\)
\(=\frac{2^{32}-1}{\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)}\)
\(=\frac{2^{32}-1}{\left(2^{16}-1\right)\left(2^{16}+1\right)}\)
\(=\frac{2^{32}-1}{2^{32}-1}=1\)
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\(\text{ 3(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^{16} + 1)}\) 3(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^16 + 1)
1*2*4+2*4*8+4*8*16+8*16*32/1*3*4+2*6*8+4*12*16+8*24*32
Tính
1*2*4+2*4*8+4*8*16+8*16*32/1*3*4+2*6*8+4*12*16+8*24*32 = 56744
1*2*4+2*4*8+4*8*16+8*16*32/1*3*4+2*6*8+4*12*16+8*24*32 = 56744
#nhớ tk
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giúp e vs nha mn, e cần gấp lắm ạ. thanks trc ạ
a, (2^2+1)(2^4+1)(2^8+1)(2^16+1)
b,24(5^2+1)(5^4+1)(5^8+1)(5^16+1)
c,48(7^2+1)(7^4+1)(7^8+1)(7^16+1)
\(\text{a) }\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\\ =\dfrac{3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}{3}\\ =\dfrac{\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}{3}\\ \\ =\dfrac{\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}{3}\\ =\dfrac{\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)}{3}\\ =\dfrac{\left(2^{16}-1\right)\left(2^{16}+1\right)}{3}\\ =\dfrac{2^{32}-1}{3}\\ \)
\(\text{b) }24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ =\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ =\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right) \\ =\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ =\left(5^{16}-1\right)\left(5^{16}+1\right)\\ =5^{32}-1\\ \)
\(\text{c) }48\left(7^2+1\right)\left(7^4+1\right)\left(7^8+1\right)\left(7^{16}+1\right)\\ =\left(7^2-1\right)\left(7^2+1\right)\left(7^4+1\right)\left(7^8+1\right)\left(7^{16}+1\right)\\ =\left(7^4-1\right)\left(7^4+1\right)\left(7^8+1\right)\left(7^{16}+1\right)\\ =\left(7^8-1\right)\left(7^8+1\right)\left(7^{16}+1\right)\\ =\left(7^{16}-1\right)\left(7^{16}+1\right)\\ =7^{32}-1\)
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1+1=....;2+2=...;4+4=...;8+8=...;16+16=...
1+1=2 ;2+2=4 ;4+4=8 ;8+8=16 ;16+16=32
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có giỏi thì mét cô đi
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