\(\left(\dfrac{1}{2}\right)^{100}:2^{-10}.2^5\\ =\left(\dfrac{1}{2}\right)^{100}.2^{10}.2^5\\ =\dfrac{1}{2^{100}}.2^{15}\\ =\dfrac{2^{15}}{2^{100}}\\ =\dfrac{1}{2^{85}}\)

\(Hello\) \(FDC\) \(nha!\)

=\(\left(\dfrac{1}{2}\right)^{100}:2^{-5}\)

=  \(\left\{\left(\dfrac{1}{2}\right)^4\right\}^{50}.2^5\)

= 2\(^{50}.2^5\)

=2\(^{55}\)

bạn đăng bài sang box toán đi nhé:)

\(\dfrac{x+1}{x-1}+\dfrac{x-2}{x+2}+\dfrac{x-3}{x+3}+\dfrac{x+4}{x-4}=0\)

\(\Leftrightarrow\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x-4\right)+\left(x-2\right)\left(x-1\right)\left(x+3\right)\left(x-4\right)+\left(x-3\right)\left(x-1\right)\left(x+2\right)\left(x-4\right)+\left(x+4\right)\left(x-1\right)\left(x+2\right)\left(x+3\right)=0\)

\(\Leftrightarrow4x^4+20x-96=0\)

\(\Leftrightarrow4\left(x^4+5x-24\right)=0\)

\(\Leftrightarrow x^4+5x-24=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-2,45...\\x=1,94...\end{matrix}\right.\)

Vậy: \(S=\left\{-2,45...;1,94...\right\}\)

\(\left(8x-4x^2-1\right)\left(x^2+2x-1\right)=4\left(x^2+x+1\right)\)

\(11x^2+6x-4x^4-1=4x^2+4x+4\)

\(11x^2+6x-4x^4-4x^2-4x-4=0\)

\(7x^2+2x-4x^4-5=0\)

\(\left(x-1\right)\left(x-1\right)\left(-4x^2-8x-5\right)=0\)

bn lm nốt nha , ko có dấu hoặc nên mk làm đến đây thôi 

Cảm ơn nha ! Nhưng sao mình ko ấn đúng cho bạn được !? hic

= \(\dfrac{2x^3+5-x^3-4}{x^2-x+1}\) = \(\dfrac{x^3-1}{x^2-x+1}\)

\(\dfrac{2x^3+5 -x^3-4}{x^2-x+1}=\dfrac{x^3+1 }{x+1}\)

câu này luôn \(\dfrac{2x^2y^5}{xy^2z}-\dfrac{4x^2y^3}{xy^2z}\)

Vậy xét là \(\frac{1}{2}+1\)nhé.

a,\(\frac{3}{2}x\frac{4}{3}x\frac{5}{4}x...x\frac{1000}{999}\)

=3x4x5x...x1000/2x3x4x...x999

=1000/2=500

b, c tương tự câu a

)(1/2+1)x(1/3+1)x(1/4+1)x...x(1/999+1) 

b)(1/2-1)x(1/3-1)x(1/4-1)x...x(1/1000-1)

c)3/2² x 8/3² x 15/4² x .... x 99/10²

mình ko biết làm chép lại de thui

tự tính đi nhớ

(1/2 + 1/3 + 1/4 +........+1/10 ) x X = 1/9 + 2/8 + .....+ 8/2 + 9/1

( 1/2 + 1/3 + 1/4 + ... + 1/10 ) x X = 1 + ( 1/9 + 1 ) + ( 2/8 + 1 ) + ... + ( 8/2 + 1 ) 

( 1/2 + 1/3 + 1/4 + ... + 1/10 ) x X = 10/10 + 10/9 + 10/8 + ... + 10/2 

( 1/2 + 1/3 + 1/4 + ... + 1/10 ) x X = 10 . ( 1/10 + 1/9 + 1/8 + ... + 1/2 )

X = \(\frac{10.\left(\frac{1}{10}+\frac{1}{9}+\frac{1}{8}+...+\frac{1}{2}\right)}{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{9}+\frac{1}{10}}\)

X = 10

 +Hình như B con thiếu 1/1 phải ko? 
B=1/1+1/2+1/3+1/4+...+1/9 
A=9/1+8/2+7/3+...+1/9=9+8/2+7/3+...+1/9 
=1+(1/9+1)+(2/8+1)+(3/7+1)+....+(8/2+1) 
=10/10+10/9+10/8+...+10/2=10(1/10+1/9+.... 
Vậy A=10B.Suy ra A:B=10 
+Nếu mà không thiếu thì dùng máy tính FX500MS,ES,phần mềm..v..v ta sẽ có 
A=4861/252 
B=4609/2520 
A/B=48610/4609

nếu B ko thiếu 1/1 thì mk chịu

e

= 1/48

a) 1/8 x 1/6 = 1/48

1/48

Nguyễn Trà My

Phần a)

\(3\times\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)

\(32-3x+13=76-x\)

\(116-3x=76-x\)

\(116-76=3x-x\)

\(46=2x\)

\(x=46\div2\)

\(x=13\)

a)  \(3.\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)

\(3.\left(\frac{1}{2}-x\right)+x=\frac{7}{6}-\frac{1}{3}\)

\(\Rightarrow\frac{3}{2}-3x+x=\frac{5}{6}\)

\(-3x+x=\frac{5}{6}-\frac{3}{2}\)

\(2x=-\frac{2}{3}\)

\(x=-\frac{2}{3}:2\)

\(x=-\frac{1}{3}\)