Question

(x³-2x²y+3xy²):(-1/2x)
(3x²y²+6x²y³-12xy):3xy

Answer 1

\(\left(x^3-2x^2y+3xy^2\right):\left(-\dfrac{1}{2}x\right)=-2x^2+4xy+6y^2\)

\(\left(3x^2y^2+6x^2y^3-12xy\right):3xy=3xy+6xy^2-12\)