Question

(x-2)^2-5x+10=0
giúp mình vs,....

Answer 1

\(\left(x-2\right)^2-5x+10=0\)

\(\Leftrightarrow\left(x-2\right)^2+5\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(x+3\right)=0\)

\(\left\{{}\begin{matrix}x-2=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)

Vậy \(x=2\) hoặc \(x=-3\)

Answer 2

(x - 2)² - 5x + 10 = 0

\(\Rightarrow\) x² - 4x + 4 - 5x = -10

\(\Rightarrow\) x² - 9x = -14

\(\Rightarrow\) x² - 9x = 7² - 9 . 7

\(\Rightarrow\) x = 7

Answer 3

(x-2)²-5x+10=0
=>x2-4x+4-5x+10=0

=>x2-9x+14=0

=>x2-2x-7x+14=0

=>(x2-2x)-(7x-14)=0

=>x(x-2)-7(x-2)=0

=>(x-2)(x-7)=0

=>\(\left[{}\begin{matrix}x-2=0\\x-7=0\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=2\\x=7\end{matrix}\right.\)