Question

tính nhanh
a) ( 9a^2 - 16b^2) : ( 4b - 3a )
b) (25a^2 - 30ab + 9b^2) : (3b - 5a )
c) ( 27a^3 - 27a^2 + 9a - 1) : (9a^2 - 6a + 1)

Answer 1

a,\(\dfrac{9a^2-16b^2}{4b-3a}=\dfrac{\left(3a-4b\right)\left(3a+4b\right)}{\text{4b-3a}}=-3a-4b\)

b,\(\dfrac{25a^2-30ab+9b^2}{3b-5a}=\dfrac{\left(5a-3b\right)^2}{3b-5a}=3b-5a\)

c,\(\dfrac{27a^3-27a^2+9a-1}{9a^2-6a+1}=\dfrac{27a^3-9a^2-18a^2+6a+3a-1}{9a^2-6a+1}=\dfrac{\left(3a-1\right)\left(9a^2-6a+1\right)}{9a^2-6a+1}=3a-1\)