Question

Tính: 8x^3-(2x+y)*(4x^2-2xy+y^2)

Answer 1

8x³-(2x+y).(4x²-2xy+y²)

=\(\left(2x\right)^3-\left(2x+y\right).\left[\left(2x\right)^2-2x.y+y^2\right]\)

= \(\left(2x\right)^3-\left[\left(2x\right)^3+y^3\right]\)

= \(\left(2x\right)^3-\left(2x\right)^3-y^3\)

= -y³

^{Học tốt !}

Answer 2

\(8x^3-\left(2x+y\right)\left(4x^2-2xy+y^2\right)\)

\(=8x^3-8x^3-y^3\)

\(=-y^3\)