Question

Thực hiện phép chia:

1) \(\left(x^2-6x+9\right):\left(3-x\right)\)

2) \(\left(x^3-8\right):\left(x^2+2x+4\right)\)

3) \(\left(2x^3+x^2-x+3\right):\left(x^2-x+1\right)\)

Answer 1

1: \(=\dfrac{\left(3-x\right)^2}{3-x}=3-x\)

2: \(=\dfrac{\left(x-2\right)\left(x^2+2x+4\right)}{x^2+2x+4}=x-2\)

3: \(=\dfrac{2x^3-2x^2+2x+3x^2-3x+3}{x^2-x+1}=2x+3\)