Question

Rút gọn đa thức sau : 3(3^2+1)(3^4+1)(3^8+1)(3^16+1)

mn giúp mik vs nha

Answer 1

\(=3\dfrac{\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)}{8}\)

\(=\dfrac{3\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)}{8}\)

\(=\dfrac{3\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)}{8}\)

\(=\dfrac{3\left(3^{16}-1\right)\left(3^{16}+1\right)}{8}\)

\(=\dfrac{3\left(3^{32}-1\right)}{8}\)