\(4a^2-9=\left(2a\right)^2-3^2=\left(2a-3\right)\left(2a+3\right)\)
\(2x^2-3x+1=2x^2-2x-x+1=2x\left(x-1\right)-\left(x-1\right)=\left(x-1\right)\left(2x-1\right)\)
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\(4a^2-9=\left(2a\right)^2-3^2=\left(2a-3\right)\left(2a+3\right)\\ 2x^2-3x+1=2x^2-2x-x+1=2x\left(x-1\right)-\left(x-1\right)=\left(x-1\right)\left(2x-1\right)\)
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4a2−9
=(2a)2−32
=(2a−3)(2a+3)
b)2x2−3x+1
=2x2−2x−x+1
=2x(x−1)−(x−1)
=(x−1)(2x−1)
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