Question

Ai làm ơn giúp em đc ko ạ🙏🙏🙏

Answer 1

\(a,=\left(x+4\right)^3=\left(6+4\right)^3=10^3=1000\\ b,=x^3-1+x^3-27=2x^3-28\\ =2\left(-1\right)^3-28=-2-28=-30\\ c,=\left[4x-6-4\left(3-x\right)\right]\left[4x-64++4\left(3-x\right)\right]=6\left(8x-18\right)=12\left(4x-9\right)\\ =12\left(-7\cdot4-9\right)=12\left(-37\right)=-444\)