Question

3x(3x - 8) - 9x^2 + 8 = 0

Answer 1

Lời giải:

\(3x(3x-8)-9x^2+8=0\)

\(\Leftrightarrow 9x^2-24x-9x^2+8=0\)

\(\Leftrightarrow 8-24x=0\Leftrightarrow x=\frac{1}{3}\)

Answer 2

3x ( 3x - 8 ) - 9x² + 8 = 0  

9x² - 24x - 9x² + 8 = 0

( 9x² - 9x² ) - 24x + 8 = 0

- 24x + 8 = 0

-24x = -8

x = \(\dfrac{1}{3}\)

Vậy x = \(\dfrac{1}{3}\)