Nè, tui là người khác, nhưng vẫn giúp được mà, huh? Cái này tui làm chi tiết cho dễ hiểu
(x2 - 4x + 16)(x + 4) - x(x + 1)(x + 2) + 3x2 = 0
⇒ x3 + 64 - x(x2 + 3x +2) + 3x2 = 0
⇒ x3 - x3 - 3x2 - 2x + 3x2 = -64
⇒ -2x = -64
⇒ x = 32
Tìm x:
a.\(5x-3\left\{4x-2\left[4x-3(5x-2)\right]\right\}=182\)
b.\(\left(x+2\right)\left(x+3\right)-\left(x-2\right)\left(x+5\right)=0\)
c.\(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
Giúp mk vs!!
Tìm x biết : (đề không sai)
1.\(-4x\left(x-7\right)+4x\left(x^2-5\right)\) \(=28x^2-13\)
2.\(\left(4x^2-5x\right)\left(3x+2\right)-7x\left(x-7\right)\)= \(\left(-4+x\right)\left(-2x+3\right)+12x^3+2x^2\)
3.\(\left(-4x^2-3\right)\left(2x+5\right)-\left(8x-3\right)\) \(\left(-x^2+2\right)=-5x^2\left(x-6\right)-3x^2-4\)
4.\(\left(x-7\right)\left(x+5\right)-\left(x-3\right)\left(x-2\right)\) \(=15x^2\left(x+1\right)-\left(3x^2-1\right)\) \(\left(5x^2-2\right)-21x^2\)
5.\(\left(x-3\right)\left(-x+10\right)+\left(x-8\right)\left(x+3\right)\) \(=\left(5x^2-1\right)\left(x+3\right)-5x^3-15x^2\)
6.\(\left(-2x^2+5\right)\left(-x+3\right)-x^2\left(2x-6\right)\) \(=\left(x-1\right)\left(x+1\right)-\left(x-2\right)\left(x+4\right)\)
Tìm x, biết
a) \(\left(3x+2\right)\left(2x+9\right)-\left(x+2\right)\left(6x+1\right)=\left(x+1\right)-\left(x-6\right)\)
b) \(3\left(2x-1\right)\left(3x-1\right)-\left(2x-3\right)\left(9x-1\right)=0\)
tìm x, biết:
\(a,-4x\left(x-7\right)+4x\left(x^2-5\right)=28x^2-13\)
\(b,\left(4x^2-5x\right)\left(3x+2\right)-7x\left(x+5\right)\) \(=\left(-4+x\right)\left(-2x+3\right)+12x^2+2x^2\)
Tìm \(x\) , biết:
a) \(\left(x+2\right)\left(x+3\right)-\left(x-2\right)\left(x+5\right)=6\)
b) \(\left(3x+2\right)\left(2x+9\right)-\left(x+2\right)\left(6x+1\right)=\left(x+1\right)-\left(x-6\right)\)
c) \(3\left(2x-1\right)\left(3x-1\right)-\left(2x-3\right)\left(9x-1\right)=0\)
CÁC BẠN LÀM NHANH GIÚP MIK NHA!
\(^{3x^2\left(a^2+b^2\right)-3a^2b^2+3\left[x^2+\left(a+b\right)x+ab\right]\left[x\left(x-a\right)-b\left(x-a\right)\right]:2x^2=\dfrac{3}{2}x^2}\)
Tính giá trị
P=\(\left\{\left[ã-2\left(a+2\right)\right]\left[a\left(x-1\right)+2\right]+2\left(-a^2+4\right)3a^2.x\right\}:\left(-2ax\right)\)
Biết a=2 và x=1
Tìm x :
\(\left(2x^2+1\right)\cdot\left(3x^2-1\right)-\left(4x^2-3\right)\cdot\left(x^2+1\right)=x\cdot\left(2x^2+1\right)\)
Giải phương trình:
n) \(\left|3-x\right|+x^2-x\left(x+4\right)=0\)
m)\(\left(x-1\right)^2+\left|x+21\right|-x^2-13=0\)
e) \(\left|5x\right|=3x-2\)
g)\(\left|-2,5x\right|=x-12\)
h) \(\left|5x\right|-3x-2=0\)
i)\(\left|-2x\right|+x-5x-3=0\)
Chứng tỏ biểu thức sau không phụ thuộc vào biến x:
\(\left(3x^2-2x+1\right)\left(x^2+2x+3\right)-4x\left(x^2-1\right)-3x^2\left(x^2+2\right)\)
