Question

1.phân tích đa thức thành nhân tử

ab(x^2+y^2)+xy(a^2+b^2)

ab(x^2+1)+x(a^2+b^2)

x^3-3x^2+3x-1-8y^3

x^4+3x^3-9x-9

x^2+6x-y^2+9

x^2+y^2-z^2-9t^2-2xy+6zt

7x^2-7xy-4x+4y

x^4+3x^3-9x-27

3a^2-6ab+3b^2-12c^2

x^2+3cs(2-3cd)-10xy-1+25y^2

Answer 1

b: \(=abx^2+ab+a^2x+b^2x\)

\(=bx\left(ax+b\right)+a\left(ax+b\right)\)

\(=\left(ax+b\right)\left(bx+a\right)\)

c: \(=\left(x-1\right)^3-8y^3\)

\(=\left(x-1-2y\right)\left(x^2-2x+1+2xy-2y+4y^2\right)\)

d: \(=\left(x^2-3\right)\left(x^2+3\right)+3x\left(x^2-3\right)\)

\(=\left(x^2-3\right)\left(x^2+3x+2\right)\)

e: \(=\left(x+3\right)^2-y^2=\left(x+3+y\right)\left(x+3-y\right)\)