Question

1 = \(\dfrac{1}{x}+\dfrac{1}{\left(\dfrac{x}{x-1}\right)^2}\)tìm x

Answer 1

`1=1/x+1/[(x/[x-1])^2]`          `ĐK: x \ne 0,x \ne 1`

`<=>1=1/x+[(x-1)^2]/[x^2]`

  `=>x^2=x+x^2-2x+1`

`<=>x=1` (ko t/m)

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