Question

1. a) \(\left(x-1\right)\left(x+1\right)\left(x+2\right)\)

b) \(\dfrac{1}{2}x^2y^2\left(2x+y\right)\left(2x-y\right)\)

Answer 1

a, \(\left(x-1\right)\left(x+1\right)\left(x+2\right)\)

\(=\left(x^2-1\right)\left(x+2\right)\)

\(=x^3-x+2x^2-1\)

b, \(\dfrac{1}{2}x^2y^2\left(2x+y\right)\left(2x-y\right)\)

\(=\dfrac{1}{2}x^2y^2\left(4x^2-y^2\right)\)

\(=2x^4y^2-\dfrac{1}{2}x^2y^4\)

Answer 2

yêu cầu làm gì bạn

Answer 3

( x - 1 ) ( x + 1 ) ( x + 2 ) = ( x² - 1 ) ( x + 2 ) = x³ +x - 2

12x2y2(2x+y)(2x−y)" id="MathJax-Element-2-Frame" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline; float:none; font-size:18px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:normal; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal; word-wrap:normal" tabindex="0">12x2y2(2x+y)(2x−y) = 2x⁴y² - 1/2x²y⁴

Answer 4

\(a,\left(x-1\right)\left(x+1\right)\left(x+2\right)=\left(x^2-1\right)\left(x+2\right)=x^3+2x^2-x-2\)\(b,\dfrac{1}{2}x^2y^2\left(2x+y\right)\left(2x-y\right)=\dfrac{1}{2}x^2y^2\left(4x^2-y^2\right)=2x^4y-\dfrac{1}{2}x^2y\)