Sau khi phân tích đa thức \(x^4-4x^2+3\) thành nhân tử, ta có kết quả là
\(\left(x+1\right)\left(x-1\right)\left(x-\sqrt{3}\right)\left(x+\sqrt{3}\right)\).\(\left(x+1\right)^2\left(x-\sqrt{3}\right)\left(x+\sqrt{3}\right)\).\(\left(x-1\right)^2\left(x-\sqrt{3}\right)\left(x+\sqrt{3}\right)\).\(\left(x+1\right)^2\left(x-\sqrt{3}\right)^2\).Hướng dẫn giải:\(x^4-4x^2+3=x^4-x^2-3x^2+3\)
\(=x^2\left(x^2-1\right)-3\left(x^2-1\right)\)
\(=\left(x^2-1\right)\left(x^2-3\right)\)
\(=\left(x+1\right)\left(x-1\right)\left(x-\sqrt{3}\right)\left(x+\sqrt{3}\right)\).
