Lời giải:

a. 

$=5^{6-3}+2^{3-2}=5^3+2^1=125+2=127$
b.

$=3333:3+225:15=1111+15=1126$

c.

$=15.2^3+4.3^2-5.7=15.8+4.9-35=120+36-35=120+1=121$

d.

$=5.4^2-18:3^2=5.16-18:9=80-2=78$

e.

$=6^2:4.3+2.5^3=36:4.3+2.125$

$=9.3+250=27+250=277$

f.

$=80-(4.25-3.8)=80-(100-24)=80-100+24=-20+24=4$

\(5\cdot4^2-18:3^2\)

\(=5\cdot16-18:9\)

\(=80-2\)

\(=78\)

________________

\(6^2:4\cdot3+2\cdot5^3\)

\(=36:12+2\cdot125\)

\(=3+250\)

\(=253\)

_______________

\(80-\left(4\cdot5^2-3\cdot2^3\right)\)

\(=80-\left(4\cdot25-3\cdot8\right)\)

\(=80-\left(100-24\right)\)

\(=80-76\)

\(=4\)

6² : 4 . 3 + 2 . 5³

= 36 : 4 . 3 + 2 . 125

= 9 . 3 + 250

= 27 + 250

= 277

Hai bài còn lại xem của bạn Phong nhé. Bài này Phong giải chưa chính xác nên Thầy giải lại cho em!

TA có\(\frac{2^{12}.3^5.4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3}\)

=\(\frac{2^{12}.3^5.2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}-\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3}\)

=\(\frac{2^{24}.3^9}{2^{12}.3^5.\left(3+1\right)}-\frac{5^{10}.7^3.\left(1-7\right)}{5^9.7^3}\)

=\(2^{20}.3^4-30\)

\(B=5.3^2+4.3^2=3^2\left(5+4\right)=9.9=9^2\)

\(C=5^3+6^3+59=125+216+59=400=20^2\)

\(D=5.4^3+2^4.5+41=320+80+41=441=21^2\)

b: \(5\cdot3^2+4\cdot3^2=3^2\cdot9=3^4\)

c: \(5^3+6^3+59=20^2\)

\(5\cdot4^3+2^4\cdot5+41=21^2\)

:)?

giúp e với em cần gấp ạ

\(A=3^2\cdot4^3-3^2+333\)

\(=3^2\cdot63+333\)

\(=3^2\cdot\left(63+37\right)\)

\(=30^2\)

\(B=5\cdot3^2+4\cdot3^2=3^2\cdot9=9^2\)