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 1a2d3a4c5b6a

Câu 6:

\(U=I.R=10.1,5=15\left(V\right)\)

Câu 7:

\(P=U.I\Rightarrow U=\dfrac{P}{I}=\dfrac{10}{0,5}=20\left(V\right)\)

Câu 8:

\(R_{tđ}=\dfrac{R_1.R_2}{R_1+R_2}=\dfrac{10.30}{10+30}=7,5\left(\Omega\right)\)

Áp dụng tc dtsbn:

\(\dfrac{2y+z-x}{x}=\dfrac{2z-y+x}{y}=\dfrac{2x+y-z}{z}=\dfrac{2x+2y+2z}{x+y+z}=\dfrac{2\left(x+y+z\right)}{x+y+z}=2\\ \Rightarrow\left\{{}\begin{matrix}2y+z-x=2x\\2z-y+x=2y\\2x+y-z=2z\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}2y+z=3x\\2z+x=3y\\2x+y=3z\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}3x-2y=z\\3y-2z=x\\3z-2x=y\end{matrix}\right.;\left\{{}\begin{matrix}3x-z=2y\\3y-x=2z\\3z-y=2z\end{matrix}\right.\\ \Rightarrow P=\dfrac{xyz}{2x\cdot2y\cdot2z}=\dfrac{1}{8}\)

Chọn D

\(\dfrac{2y+z-x}{x}=\dfrac{2z-y+x}{y}=\dfrac{2x+y-z}{z}=\dfrac{2\left(x+y+z\right)}{x+y+z}=2\)

\(\Rightarrow\left\{{}\begin{matrix}2y+z-x=2x\\2z-y+x=2y\\2x+y-z=2z\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}2y+z=3x\\2z+x=3y\\2x+y=3z\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}3x-2y=z\\3y-2z=x\\3z-2x=y\end{matrix}\right.\) và \(\left\{{}\begin{matrix}3x-z=2y\\3y-x=2z\\3z-y=2x\end{matrix}\right.\)

Thay vào A:

\(A=\dfrac{z.x.y}{2y.2z.2x}=\dfrac{1}{8}\)

Vì x>0, y>0, z>0 ⇒ x+y+z>0

Áp dụng t/c dtsbn ta có:

\(\dfrac{2y+z-x}{x}=\dfrac{2z-y+x}{y}=\dfrac{2x+y-z}{z}=\dfrac{2y+z-x+2z-y+x+2x+y-z}{x+y+z}=\dfrac{2\left(x+y+z\right)}{x+y+z}=2\)

\(\dfrac{2y+z-x}{x}=2\Rightarrow2y+z-x=2x\Rightarrow2y+z=3x\\ \dfrac{2z-y+x}{y}=2\Rightarrow2z-y+x=2y\Rightarrow2z+x=3y\\ \dfrac{2x+y-z}{z}=2\Rightarrow2x+y-z=2z\Rightarrow2x+y=3z\)

\(A=\dfrac{\left(3x-2y\right)\left(3y-2z\right)\left(3z-2x\right)}{\left(3x-z\right)\left(3y-x\right)\left(3z-y\right)}\)

\(\Rightarrow A=\dfrac{\left(2y+z-2y\right)\left(2z+y-2z\right)\left(2x+y-2x\right)}{\left(2y+z-z\right)\left(2z+x-x\right)\left(2x+y-y\right)}\)

\(\Rightarrow A=\dfrac{xyz}{2x.2y.2z}\)

\(\Rightarrow A=\dfrac{1}{8}\)

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working

directly

Working ( stop+V-ing)
Directly

III. 

A. 

1. B

2. C

3. B

4. A

5. D

B. 

1. C

2. B

3. B

4. A

5. C

1 b c b a d

2 c b b a c nha

Đề dài thế này sao giải thích nhanh cho e đc

Part 1

1 C

2 B

3 D

4 C

5 B

6 A

Part 2

1 T

2 F

3 F

4 F

V

1 That old house has just been bought

2 If he doesn't take these pills, he won't be better

3 I suggest taking a train

4 Spending the weekend in the countryside is very wonderful

 

nhiều thật đấy

\(\dfrac{19}{20}-x=\dfrac{8}{5}+\dfrac{3}{4}\)
\(\dfrac{19}{20}-x=\dfrac{32}{20}+\dfrac{15}{20}\)
\(\dfrac{19}{20}-x=\dfrac{47}{20}\)
\(x=\dfrac{19}{20}-\dfrac{47}{20}\)
\(x=\dfrac{-28}{20}=\dfrac{-7}{5}\)

#DatNe

\(\dfrac{19}{20}-x=\dfrac{8}{5}+\dfrac{3}{4}\\ \dfrac{19}{20}-x=\dfrac{47}{20}\\ x=\dfrac{19}{20}-\dfrac{47}{20}\\ x=-\dfrac{28}{20}\\ x=-\dfrac{7}{5}.\)

1 correct

2 success => only success

3 was released => released

4 correct

5 focused on => on

6 as a => a

7 correct

8 each others => others

9 satisfy with => satisfy

10 correct

11 correct