1: ĐKXĐ:  \(x\notin\left\{0;3\right\}\)

\(\dfrac{x+3}{x}-\dfrac{x}{x-3}+\dfrac{9}{x^2-3x}\)

\(=\dfrac{x+3}{x}-\dfrac{x}{x-3}+\dfrac{9}{x\left(x-3\right)}\)

\(=\dfrac{\left(x+3\right)\left(x-3\right)-x^2+9}{x\left(x-3\right)}\)

\(=\dfrac{x^2-9-x^2+9}{x\left(x-3\right)}\)

=0

2: ĐKXĐ: \(x\notin\left\{0;1\right\}\)

\(\dfrac{3}{x}-\dfrac{5}{x-1}+\dfrac{3x+2}{x^2-x}\)

\(=\dfrac{3}{x}-\dfrac{5}{x-1}+\dfrac{3x+2}{x\left(x-1\right)}\)

\(=\dfrac{3x-3-5x+3x+2}{x\left(x-1\right)}\)

\(=\dfrac{x-1}{x\left(x-1\right)}=\dfrac{1}{x}\)

Giúp mk câu hỏi này vs

\(2x\left(3x^2-7x+2\right)\)

\(=6x^3-14x^2+4x\)

\(\left(x-2\right)\left(3x^2+2x+4\right)\)

\(=3x^3+\left(-4x^2\right)+\left(-8\right)\)

\(\left(3x^2y^2+6x^2y^3-12xy\right)\div3xy\)

\(=xy+2xy-4\)

x^2/x-2+4-4x/x-2 ???

1) 2x(3x^2-7x+2)

<=> \(6x^3-14x^2+4x\)

2) (x-2)(3x^2+2x+4)

<=> \(3x^3-4x^2-8\)

3) (3x^2y^2+6x^2y^3-12xy)÷3xy

<=> xy + 2xy² -4 

4) X^2/x-2+4-4x/x-2

<=> \(\dfrac{x^2-4x+4}{x-2}=\dfrac{\left(x-2\right)^2}{x-2}=x-2\)

Ta có:

\(\left(x-1\right).\left(x+1\right).\left(x+2\right)\)

\(=\left(x^2+x-x-1\right).\left(x+2\right)\)

\(=\left(x^2-1\right).\left(x+2\right)\)

\(=x^3+2x^2-x-2\)

\(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot\left(1-\frac{1}{5}\right)\cdot....\cdot\left(1-\frac{1}{2003}\right)\cdot\left(1-\frac{1}{2004}\right)\)

\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot....\cdot\frac{2002}{2003}\cdot\frac{2003}{2004}\)

\(=\frac{1\cdot2\cdot3\cdot4\cdot....\cdot2002\cdot2003}{2\cdot3\cdot4\cdot5\cdot....\cdot2003\cdot2004}\)

\(=\frac{1}{2004}\)

phân số thứ nhất bằng 0/2 =0

vậy tích đó chắc chắn bằng 0

chuẩn ko mn?

\(=\dfrac{6x^3+3x^2-10x^2-5x+4x+2}{2x+1}=3x^2-5x+2\)

\(3^2\cdot5+2^3\cdot10-3^4:3\\ =9\cdot5+8\cdot10-3^4\\ =45+80-27\\ =98\)

\(3^2.5+2^3.10-3^4:3\)

\(=9.5+8.10-3^3\)

\(=45+80-27\)

\(=125-27\)

\(=98\)

\(#WendyDang\)

Anh ơi, dòng 2 ( \(3^4:3\) thì ra \(3^3\) -> a mới đổi thành được \(27\) chứ ạ? )

ko hiểu

Bài làm

1) 29( 85 - 47 ) + 85( 47 - 29 )

= 29 . 85 - 29 . 47 + 85 . 47 - 29 . 85

= 29 . 85 . ( -29 . 47 + 85 . 47 )

= 29 . 85 . [ 47( -29 + 82 ) ]

= 29 . 85 . ( 47 . 53 )

= 6140315

2) 3 - | x - 7 | = -12

=> | x - 7 | = 3 - ( -12 )

=> | x - 7 | = 15 

=> \(\orbr{\begin{cases}x-7=15\\x-7=-15\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=-8\end{cases}}}\)

Vậy x = { 22; -8 } 

Trả lời :

Câu 1.

29 . (85 - 47) + 85 . (47 - 29)

= 29 . 85 - 29 . 47 + 85 . 47 - 85 . 29

= (29 . 85 - 85 . 29) + (85 . 47 - 29 . 47)

= 0 + 2632 

= 2632

Câu 2.

3 - |x - 7| = - 12

=> |x - 7| = 3 - (- 12)

=> |x - 7| = 3 + 12

=> |x - 7| = 15

=> x - 7 = \(\pm15\)

\(\Rightarrow\orbr{\begin{cases}x-7=15\\x-7=-15\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=-8\end{cases}}}\)