a) -1+2-3+4-5+6-....-2015+2016-2017+2018

= (-1+2)+(-3+4)+(-5+6)+.….+(-2015+2016)+(-2017+2018)

= 1+1+1+....+1+1

( Có tất cả 1009 số 1)

= 1009

b)1-2+3-4+5-6+.….+1245-1246+1247-1248

=(1-2)+(3-4)+(5-6)+....+(1245-1246)+(1247-1248)

=-1+(-1)+(-1)+....+(-1)+(-1)

(Có tất cả 624 số (-1))

= -624

b) 1-3+5-7+9-11+......+2005-2007

=(1-3)+(5-7)+(9-11)+.....+(2005-2007)

=(-2)+(-2)+(-2)+......+(-2)

=(-2).1004

=(-2008)

c) 1+2+3-4-5-6+7+8+9-10-11-12+...+97+98+99-100-101-102

=(1+2+3-4-5-6)+(7+8+9-10-11-12)+.....+(97+98+99-100-101-102)

=(-9)+(-9)+....+(-9)

=(-9).17

=(-153)

Xin lỗi nha 2 dòng cuối mk làm sai 

b)1-3+5-7+9-11+......+2005-2007

=(1-3)+(5-7)+(9-11)+....+(2005-2007)

=(-2)+(-2)+(-2)+....+(-2)

=(-2).502

=(-1004)

S = 1.2 + 2.3 + 3.4 +...+99.100

3S = 1.2.3 + 2.3.(4 - 1) + 3.4(5 - 2) +...+ 99.100(101 - 98)

3S = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 +...+ 99.100.101 - 98.99.100

3S = 99.100.101

3S = 999900

S = 333300

P = 1 + 3 + 5 + 7 +...+ 2015

P = (2015 + 1)1008 : 2 

P = 1016064

T = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 +...+ 97 + 98 - 99 - 100

T = (1 + 2 - 3 - 4) + (5 + 6 - 7 - 8) +...+ (97 + 98 - 99 - 100)

T = (-4) + (-4) +...+ (-4)     

T = (-4)25

T = -100

S=999900

P=1016064

T=-100

S= 333300

quên chưa chia cho 3

1/ 1 + (-2) + 3 + (-4) + . . . + 19 + (-20)

=1-2+3-4+...+19-20

=(1-2)+(3-4)+...+(19-20)

=(-1)+(-1)+...+(-1)
=(-1).10

=-10

2/ 1 – 2 + 3 – 4 + . . . + 99 – 100

=(1-2)+(3-4)+...+(99-100)

=(-1)+(-1)+...+(-1)

=(-1).50

=-50

3/ 2 – 4 + 6 – 8 + . . . + 48 – 50

 =(2-4)+(6-8)+...+(48-50)

 =(-2)+(-2)+...+(-2)

 =(-2).13

 =-26

4/ – 1 + 3 – 5 + 7 - . . . . + 97 – 99

=(-1)+(3-5)+(7-9)+...+(97-99)

=(-1)+(-2)+(-2)+...+(-2)

=(-1)+(-2).45

=(-1)+(-90)

=(-91)

5/ 1 + 2 – 3 – 4 + . . . . + 97 + 98 – 99 - 100

=(1+2-3-4)+...+(97 + 98 – 99 - 100)

=(-4)+...+(-4)

=(-4).25

=-100

\(HT\)

1/ \(1+(-2)+3+(-4)+...+19+(-20)\)

\(=(-1+3+5+...+19)-(2+4+6+...+20)\)

\(=(19-1):2+1=10\)

\(=(1+19).10:2-(20+2).10:2\)

\(=100-110\)

\(=-10\)

2/ \(1 – 2 + 3 – 4 + . . . + 99 – 100\)

\(= ( 1 - 2 ) + ( 3 - 4) + .... + ( 99 - 100 )\)

\(= -1 + ( -1) + ....+ ( -1)\)

\(=(-1).50\)

\(=-50\)

3/ \( 2 – 4 + 6 – 8 + . . . + 48 – 50\)

\(= 2 +( – 4 + 6)+( – 8+10) + . . . +( -44+46)+ ( 48 – 50)\)

\(= 2+2+2+...+2+( -2) \)

\(= 2.12 +( -2 ) \)

\(=22\)

4/ \(-1+3-5+7-...+97-99\)

\(= ( -1 + 3 ) + ( -5 + 7 )+....+( -93 +95 ) + ( 97 - 99 )\)

\(= -2+( -2)+...+( -2)+2\)

\(= -2.24+2\)

\(=-46\)

5/ \( 1+2-3-4+...+97+98-99-100\)

\(= ( 1+2-3-4)+...+( 97+98-99-100)\)

\(= -4+...+( -4)\)

\(=(-4).25\)

\(=-100\)

Thanks mn nhìu nhaaaaaa! Chúc mn hok tốt ah! Xin lỗi mn nhìu nha mik k k đúng đc! Srr mn nhiều ah!!! T^T

Ta có : 

\(A=\frac{3}{4.5}+\frac{3}{5.6}+\frac{3}{6.7}+...+\frac{3}{99.100}\)

\(A=3\left(\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{99.100}\right)\)

\(A=3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{100}\right)\)

\(A=3\left(\frac{1}{4}-\frac{1}{100}\right)\)

\(A=3.\frac{6}{25}\)

\(A=\frac{18}{25}\)

Vậy \(A=\frac{18}{25}\)

Chúc bạn học tốt ~ 

\(A=\frac{3}{4.5}+\frac{3}{5.6}+\frac{3}{6.7}+...+\frac{3}{99.100}\)

\(\Rightarrow A=3.\left(\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{99.100}\right)\)

\(\Rightarrow A=3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{99}-\frac{1}{100}\right)\)

\(\Rightarrow A=3.\left(\frac{1}{4}-\frac{1}{100}\right)=\frac{3.24}{100}\)

\(=\frac{3.4.6}{25.4}\)

\(\Rightarrow A=\frac{18}{25}\)

cám ơn 2 bạn nhiềuạ!

1+5+3+9+5+7=30

Bằng 30 nha

k Đúng cho mình nhá

30 nhe bn

BÀI 1:

a)    \(\frac{4}{5}+\frac{3}{8}+\frac{1}{4}\)

\(=\frac{32}{40}+\frac{15}{40}+\frac{10}{40}\)

\(=\frac{32+15+10}{40}\)\(=\frac{57}{40}\)

b)    \(\frac{5}{9}+\frac{2}{3}+\frac{1}{2}\)

\(=\frac{10}{18}+\frac{12}{18}+\frac{9}{18}\)

\(=\frac{10+12+9}{18}=\frac{31}{18}\)

bài 23,, 5 nữa

1. 

a.57/40

b.31/18

`A = 2 + 2^2+ ... + 2^2017`

`=> 2A = 2^2 + 2^3 + ... + 2^2018`

`=> 2A - A = (2^2 + 2^3 + ... + 2^2018) - (2 + 2^2 + ... +2^2017)`

`=> A         = 2^2018 - 2`

`B = 1 + 3^2 + ... + 3^2018`

`=> 3^2B = 3^2 + 3^4 + ... + 3^2020`

`=> 9B-B =(3^2 + 3^4 + ... + 3^2020) - (1 + 3^2 + ... + 3^2018`

`=> 8B     = 3^2020 - 1`

`=> B       = (3^2020 - 1)/8`

`C = 5 + 5^2 - 5^3 + ... + 5^2018`

`=> 5C = 5^2 + 5^3 - 5^4 + ... +5^2019`

`=> 5C + C = ( 5^2 + 5^3 - 5^4 + ... 5^2019) + (5 + 5^2 - 5^3 + ... + 5^2018)`

`=> 6C = 55 + 5^2019`

`=> C  = (5^2019 + 55)/6`

a: 14/5-7/5=7/5

b: 7/8-1/3+5/4

=21/24-8/24+30/24

=43/24

c; =7/6+5/6+2/15+13/15

=2+1

=3

d: =4*5/3*11=20/33

e: =2/9*1/6*1/4=2/9*1/24=1/108

2:
a: \(=\dfrac{3}{9}\cdot\dfrac{4}{4}\cdot\dfrac{5}{5}\cdot\dfrac{6}{6}\cdot\dfrac{7}{7}=\dfrac{1}{3}\)

b: \(=\dfrac{1}{6}\left(\dfrac{22}{3}-\dfrac{2}{3}\right)=\dfrac{10}{3}\cdot\dfrac{1}{6}=\dfrac{10}{18}=\dfrac{5}{9}\)

c; \(=\dfrac{1}{3}\left(9-\dfrac{2}{5}-\dfrac{3}{5}\right)=\dfrac{8}{3}\)

14/5-7/5=7/5 

7/8-1/3+5/4=13/24+5/4=43/24 

7/6+2/15+5/6+13/15=13/10+5/6+13/15=32/15+13/15=3

4/3*5/11=20/35

2/9:6*1/4=1/27*1/4=1/108