\(49\dfrac{8}{23}-\left(5\dfrac{7}{32}+14\dfrac{8}{23}\right)=49\dfrac{8}{23}-5\dfrac{7}{32}-14\dfrac{8}{23}=\left(49\dfrac{8}{23}-14\dfrac{8}{23}\right)-5\dfrac{7}{32}=35-5\dfrac{7}{32}=\dfrac{953}{32}\)

\(A=\frac{1135}{23}-\left(\frac{167}{32}+\frac{330}{23}\right)=\frac{1135}{23}-\frac{330}{23}+\frac{167}{32}=35+\frac{167}{32}=\frac{1287}{32}\)

giải

49/8/23-(5/7/32+14/8/23)

=49/8/23-5/7/32-14/8/23

=(49/8/23-14/8/23)-5/7/32

=35-5/7/32

=953/32

\(=49+\dfrac{8}{23}-5-\dfrac{7}{32}-14-\dfrac{8}{32}\)

\(=30-\dfrac{89}{736}=\dfrac{21991}{736}\)

=30−89/736=21991/736

= 21991/736

49\(\frac{8}{23}\) - (5\(\frac{7}{32}\) + 14\(\frac{8}{23}\) )

= \(\frac{1135}{23}\) - (\(\frac{167}{32}\) +\(\frac{330}{23}\) )

= \(\frac{1135}{23}\) - \(\frac{14401}{736}\) 

=\(\frac{953}{32}\)

\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

\(=\frac{1135}{23}\left(\frac{135}{32}+\frac{330}{23}\right)\)

\(=\frac{1135}{23}.\frac{13665}{736}\)

\(=916,2201678\)

=1135/23-(167/32+330/23)

=(1135/23-330/23)-167/32

=35-167/32

=1120/32-167/32

=953/32

=hỗn số 29:25/32

  \(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

\(=35\frac{0}{23}-5\frac{7}{32}\)

\(=\frac{805}{23}-\frac{167}{32}\)

\(\frac{25760}{736}-\frac{3841}{736}\)

\(=\frac{21919}{736}=\frac{953}{32}\)

1135/23-167/32+330/23

=(1135/23-330/23)+167/32

=805/23+167/32

=35+167/32

=1120/32+167/32

=1287/32