\(6^2-\left(x+3\right)=45\)

\(36-\left(x+3\right)=45\)

\(x+3=35-45\)

\(x+3=-10\)

\(x=-13\)

lớp 6 mà bạn

\(6^2-\left(x+3\right)=45\)

\(\Rightarrow36-\left(x+3\right)=45\)

\(\Rightarrow x+3=36-45\)

\(\Rightarrow x+3=-9\)

\(\Rightarrow x=-9-3=-12\)

\(125-5\left(3x-1\right)=5^5.5^3\)

\(\Rightarrow5^3-5\left(3x-1\right)=5^5.5^3\)

\(\Rightarrow5^3-15x+5=5^5.5^3\)

\(\Rightarrow5\left(5^2-3x+1\right)=5^5.5^3\)

\(\Rightarrow5^2-3x+1=5^5.5^3:5\)

\(\Rightarrow25-3x+1=5^7\)

Từ đây làm nốt nhé

\(4^x+1+4^0=65\)

\(\Rightarrow4^{x+1}+1=65\)

\(\Rightarrow4^{x+1}=64\)

\(\Rightarrow4^{x+1}=4^3\)

\(\Rightarrow x+1=3\)

\(\Rightarrow x=2\)

\(70-5\left(x-3\right)=5.3^2\)

\(\Rightarrow70-5\left(x-3\right)=5.9=45\)

\(\Rightarrow5\left(x-3\right)=70-45=25\)

\(\Rightarrow x-3=25:5=5\)

\(\Rightarrow x=8\)

Chúc em học tốt hơn nhé!!

5.3^x=45

3^x=45:5

3^x=9

Có 3^2=9

=>x=2.

5 . 3^x = 45

3^x = 45 : 5

3^x = 9

3^x = 3²

=> x = 2

a) \(3^x+5.3^x=45\)

\(3^x.1+5.3^x=45\)

\(3^x\left(1+5\right)=45\)

\(3^x.6=45\)

Xin lỗi mik nhấn nhầm 

a) bn tính típ nhé

b) thiếu đầu bài

c) \(2^{3x+2}=4^{x+5}\)

bạn giải quyết nhé

a) 5.3²⁰²³ = 50.3²⁰²³ - 5.9ˣ

5.9ˣ = 50.3²⁰²³ - 5.3²⁰²³

5.(3²)ˣ = 5.3²⁰²³.(10 - 1)

5.(3²)ˣ = 5.3²⁰²³.9

3²ˣ = 3²⁰²³.3²

3²ˣ = 3²⁰²⁵

2x = 2025

x = 2025/2

b) 2.3ˣ + 5.3ˣ⁺¹ = 153

3ˣ.(2 + 5.3) = 153

3ˣ.17 = 153

3ˣ = 153/17

3ˣ = 9

3ˣ = 3²

x = 2

a) 5.3^x-3=45

=>3^x-3=9

=>3^x-3=3²

=>x-3=2

=>x=5

b) 50 ⋮ x

=>x\(\inƯ\left(50\right)=\left\{\pm1;\pm2;\pm5;\pm10;\pm25\pm50\right\}\)

c) x ϵ B(8) và 64 ≤ x \(\le\)100

B(8)={0;8;16;....;56;64;71;80;88;96;104 ...}

mà 64\(64\le x\le100\)

thì x\(\in\left\{64;72;80;88;96\right\}\)

d) x ϵ Ư(36) và 2< x < 15

5.3^x = 5.3⁴

=> x = 4

5.3⁴ = 7.3⁵ - 2.3⁵

       = 3⁵ . (7 - 2)

       = 5. 3⁵

  => 3^x = 3⁵

=> x = 5

a) Ta có: \(5\cdot3^x=5\cdot3^4\)

\(\Leftrightarrow3^x=3^4\)

hay x=4

\(\frac{20\cdot3^{37}+2^{35}\cdot45}{5\cdot3^{37}+45\cdot2^{33}}\)

\(=\frac{2^2\cdot5\cdot3^{37}+2^{35}\cdot5\cdot3^2}{5\cdot3^{37}+5\cdot3^2\cdot2^{33}}\)

\(=\frac{2^2\cdot5\cdot3^2\cdot\left(3^{35}+2^{33}\right)}{5\cdot3^2\left(3^{35}+2^{33}\right)}\)

\(=2^2=4\)

Ta có : \(\frac{20.3^{37}+2^{35}.45}{5.3^{37}+45.2^{33}}=\frac{5.2^2.3^{37}+2^{33}.2^2.45}{5.3^{37}+45.2^{33}}=\frac{2^2\left(5.3^{37}+2^{33}.45\right)}{5.3^{37}+45.2^{33}}=2^2=4\)

a) \(\frac{3}{8}.27\frac{1}{5}-51\frac{1}{5}.\frac{3}{8}+19\)

\(=\frac{3}{8}.\left(27\frac{1}{5}-51\frac{1}{5}\right)+19\)

\(=\frac{3}{8}.\left(\frac{136}{5}-\frac{256}{5}\right)+19\)

\(=\frac{3}{8}.\left(-24\right)+19\)

\(=\left(-9\right)+19\)

\(=10.\)

b) \(35\frac{1}{6}:\left(-\frac{4}{5}\right)-45\frac{1}{6}:\left(-\frac{4}{5}\right)\)

\(=\left(35\frac{1}{6}-45\frac{1}{6}\right):\left(-\frac{4}{5}\right)\)

\(=\left(\frac{211}{6}-\frac{271}{6}\right):\left(-\frac{4}{5}\right)\)

\(=\left(-10\right):\left(-\frac{4}{5}\right)\)

\(=\frac{25}{2}.\)

Chúc bạn học tốt!