[x+2016]:4=1331(du1)
(x+2016)/4=1331 DU1
(x+2016)/4=1331 dư 1
(x+2016)=1331*4+1
x+2016=5325
x=5325-2016
x=3309
(x+2016)=1331*4
x+2016=5324
x=5324-2016
x=3308
Vay x=3308
(x+2016):4=1331 dư 1
(x+2016):4=1331 dư 1
x+2016 =1331x4+1
x+2016 =5325
x =5325-2016
x =3309
mik giải đầy đủ nha
tích mik, mik tích lại
Chứng minh:
11331+21331+31331+......+20201331-6 chia hết cho 11
A x A x A = 1331 . Tìm A .
thế 1 chử A=1 thì ta có: A . A . A = 11 . 11 . 11 . Vậy A=11
90:20=4(du1) Đ hay S??
( 2- x/13)^3 =1331/2197
\(\left(2-\frac{x}{13}\right)^3=\frac{1331}{2197}\)
=> \(\left(2-\frac{x}{13}\right)^3=\left(\frac{11}{13}\right)^3\)
=> \(2-\frac{x}{13}=\frac{11}{13}\)
=> \(\frac{x}{13}=2-\frac{11}{13}=\frac{2\cdot13-11}{13}=\frac{15}{13}\)
=> x = 15
Tìm x,y,x biết:
\(\dfrac{x}{6}=\dfrac{y}{4}=\dfrac{z}{3};\) \(x^2-y^2-z^2=1331\)
ta có : \(\dfrac{x}{6}=\dfrac{y}{4}=\dfrac{z}{3}\Leftrightarrow\dfrac{x^2}{36}=\dfrac{y^2}{16}=\dfrac{z^2}{9}\)
áp dụng tính chất dãy tỉ số bằng nhau
ta có : \(\dfrac{x^2-y^2-z^2}{36-16-9}=\dfrac{1331}{11}=121\)
\(\Rightarrow\left\{{}\begin{matrix}\dfrac{x^2}{36}=121\\\dfrac{y^2}{16}=121\\\dfrac{z^2}{9}=121\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x^2=4356\\y^2=1936\\z^2=1089\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=\pm66\\y=\pm44\\z=\pm33\end{matrix}\right.\)
vậy \(x=\pm66;y=\pm44;z=\pm33\)
Ta có : \(\dfrac{x}{6}=\dfrac{x^2}{36};\dfrac{y}{4}=\dfrac{y^2}{16};\dfrac{z}{3}=\dfrac{z^2}{9}\)
Áp dụng tính chất của dãy tỉ số bằng nhau có :
\(\dfrac{x^2}{36}=\dfrac{y^2}{16}=\dfrac{z^2}{9}=\dfrac{x^2-y^2-z^2}{36-16-9}=\dfrac{1331}{11}=121\)
\(\Rightarrow\left\{{}\begin{matrix}\dfrac{x^2}{36}=121\\\dfrac{y^2}{16}=121\\\dfrac{z^2}{9}=121\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x^2=4356\\y^2=1936\\z^2=1089\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=66\\y=44\\z=33\end{matrix}\right.\)
\(\dfrac{x}{6}=\dfrac{y}{4}=\dfrac{z}{3}\)
\(\Rightarrow\left(\dfrac{x}{6}\right)^2=\left(\dfrac{y}{4}\right)^2=\left(\dfrac{z}{3}\right)^2\)
\(\Rightarrow\dfrac{x^2}{36}=\dfrac{y^2}{16}=\dfrac{z^2}{9}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x^2}{36}=\dfrac{y^2}{16}=\dfrac{z^2}{9}=\dfrac{x^2-y^2-z^2}{36-16-9}=\dfrac{1331}{11}=121\)
Áp dụng tính
x:102=203(du1)
1234:x=9 (du 1)
x : 102 = 203 ( dư 1 )
=> x = 203 x 102 + 1
=> x = 20707
1234 : x = 9 ( dư 1 )
=> ( 1234 - 1 ) : x = 9
=> 1233 : x = 9
x = 1233 : 9
x = 137
x : 102 = 203 ( dư 1 )
=> x = 203 x 102 + 1
=> x = 20707
1234 : x = 9 ( dư 1 )
=> ( 1234 - 1 ) : x = 9
=> 1233 : x =9
x = 1233 : 9
x = 137
Bằng 137 bạn nhé
\(\dfrac{x}{y}=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{1329}-\dfrac{1}{1330}+\dfrac{1}{1331}\)
CM x⋮ 1997