\(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}\)                                    \(\frac{3}{5}.\frac{2}{8}+\frac{-6}{16}.\frac{2}{5}+\frac{-6}{15}:\left(-16\right)\)

\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}\right)\)                                 \(=\frac{3}{20}+\frac{-3}{20}+\frac{1}{40}\)

\(=\frac{-5}{7}.1=\frac{-5}{7}\)                                       \(=0+\frac{1}{40}=\frac{1}{40}\)

\(x-\frac{2}{5}=0,24\)                                           \(\left(\frac{7}{3}x-0,6\right):3\frac{2}{5}=1\)

\(\Rightarrow x=0,24+\frac{2}{5}=\frac{16}{25}\)                         \(\Rightarrow\left(\frac{7}{3}x-0,6\right):\frac{17}{5}=1\)

vậy x = 16/25                                                       \(\Rightarrow\frac{7}{3}x-0,6=\frac{17}{5}\)

                                                                          \(\Rightarrow\frac{7}{3}x=\frac{17}{5}+0,6=4\)

                                                                           \(\Rightarrow x=4:\frac{7}{3}=\frac{12}{7}\) 

                                                                           vậy x = 12/7

câu 1 = 0

câu 2 : X=\(\frac{16}{105}\)

           X =\(\frac{180}{77}\) 

         X  = 63

(18\(\dfrac{1}{2}+5\dfrac{3}{8}-7\dfrac{5}{24}\)) - 16\(\dfrac{2}{3}\) 

=( \(\dfrac{37}{2}\) + \(\dfrac{43}{8}\) - \(\dfrac{171}{24}\) ) - \(\dfrac{50}{3}\) 

= \(\dfrac{50}{3}\) - \(\dfrac{50}{3}\) 

=0

a)\(x:\dfrac{2}{5}=\dfrac{4}{7}:\dfrac{3}{2}\) 

\(x:\dfrac{2}{5}=\dfrac{8}{21}\)

x =\(\dfrac{8}{21}\times\dfrac{2}{5}\) 

x= \(\dfrac{16}{105}\)

b)\(\dfrac{12}{17}:x+\dfrac{2}{3}=\dfrac{7}{5}\)

\(\dfrac{12}{17}:x=\dfrac{7}{5}-\dfrac{2}{3}\)

\(\dfrac{12}{17}:x=\dfrac{11}{15}\) 

       \(x=\dfrac{12}{17}:\dfrac{11}{15}\)

       \(x=\dfrac{180}{187}\)

a)\(\left(x+3\right)\times5+1=20\Leftrightarrow5x+15=19\)

\(\Leftrightarrow5x=4\Leftrightarrow x=\frac{4}{5}\)

b)sai đề

c)\(2\frac{3}{7}\times x+1\frac{5}{4}=5\frac{3}{42}\)\(\Leftrightarrow\frac{17}{7}\times x+\frac{9}{4}=\frac{71}{14}\) \(\Leftrightarrow\frac{17}{7}\times x+\frac{63}{28}=\frac{142}{28}\)

\(\Leftrightarrow\frac{17}{7}\times x=\frac{79}{28}\Leftrightarrow x=\frac{17}{7}:\frac{79}{28}\) \(\Leftrightarrow x=\frac{17}{7}\times\frac{28}{79}\Leftrightarrow x=\frac{476}{553}=\frac{68}{79}\)

d)\(10\frac{2}{3}-x:\frac{6}{7}=8\frac{1}{3}-6\frac{2}{7}\Leftrightarrow\frac{32}{3}-x:\frac{6}{7}=\frac{25}{3}-\frac{44}{7}\) \(\Leftrightarrow\frac{224}{21}-x:\frac{6}{7}=\frac{75}{21}-\frac{132}{21}\Leftrightarrow-\frac{57}{21}-\frac{224}{21}\)

\(\Leftrightarrow-x:\frac{6}{7}=-\frac{281}{21}\Leftrightarrow-x=-\frac{281}{21}\times\frac{6}{7}\) \(\Leftrightarrow-x=-\frac{1686}{147}\Leftrightarrow x=\frac{562}{49}=11\frac{23}{49}\)

Giải:

a) \(\dfrac{-5}{8}=\dfrac{x}{16}\) 

\(\Rightarrow x=\dfrac{16.-5}{8}=-10\) 

\(\dfrac{3x}{9}=\dfrac{2}{6}\) 

\(\Rightarrow3x=\dfrac{2.9}{6}=3\) 

\(\Rightarrow x=1\)

b) \(\dfrac{x+3}{15}=\dfrac{1}{3}\)  

\(\Rightarrow x+3=\dfrac{1.15}{3}=5\) 

\(\Rightarrow x=2\)

\(\dfrac{6}{2x+1}=\dfrac{2}{7}\) 

\(\Rightarrow2x+1=\dfrac{6.7}{2}=21\) 

\(\Rightarrow x=10\)

c) \(\dfrac{4}{x-6}=\dfrac{y}{24}=\dfrac{-12}{18}\) 

\(\Rightarrow\dfrac{4}{x-6}=\dfrac{-12}{18}\) 

\(\Rightarrow x-6=\dfrac{18.4}{-12}=-6\) 

\(\Rightarrow x=0\) 

\(\Rightarrow\dfrac{y}{24}=\dfrac{-12}{18}\) 

\(\Rightarrow y=\dfrac{-12.24}{18}=-16\) 

 \(\dfrac{3-x}{-12}=\dfrac{16}{y+1}=\dfrac{192}{-72}\) 

\(\Rightarrow\dfrac{3-x}{-12}=\dfrac{192}{-72}\) 

\(\Rightarrow3-x=\dfrac{192.-12}{-72}=32\) 

\(\Rightarrow x=-29\) 

\(\Rightarrow\dfrac{16}{y+1}=\dfrac{192}{-72}\) 

\(\Rightarrow y+1=\dfrac{16.-72}{192}=-6\) 

d) \(\dfrac{-2}{3}< \dfrac{x}{5}< \dfrac{-1}{6}\) 

\(\Rightarrow\dfrac{-20}{30}< \dfrac{6x}{30}< \dfrac{-5}{30}\) 

\(\Rightarrow6x\in\left\{-18;-12;-6\right\}\) 

\(\Rightarrow x\in\left\{-3;-2;-1\right\}\) 

\(\dfrac{-1}{5}\le\dfrac{x}{8}\le\dfrac{1}{4}\) 

\(\Rightarrow\dfrac{-8}{40}\le\dfrac{5x}{40}\le\dfrac{10}{40}\) 

\(\Rightarrow5x\in\left\{-5;0;5;10\right\}\) 

\(\Rightarrow x\in\left\{-1;0;1;2\right\}\) 

e) \(\dfrac{x+46}{20}=x\dfrac{2}{5}\) 

\(\Rightarrow\dfrac{x+46}{20}=x+\dfrac{2}{5}\) 

\(\Rightarrow\dfrac{x+46}{20}=\dfrac{5x+2}{5}\) 

\(\Rightarrow5.\left(x+46\right)=20.\left(5x+2\right)\) 

\(\Rightarrow5x+230=100x+40\) 

\(\Rightarrow5x-100x=40-230\) 

\(\Rightarrow-95x=-190\) 

\(\Rightarrow x=-190:-95\) 

\(\Rightarrow x=2\) 

\(y\dfrac{5}{y}=\dfrac{86}{y}\) 

\(\Rightarrow y+\dfrac{5}{y}=\dfrac{86}{y}\) 

\(\Rightarrow\dfrac{y^2+5}{y}=\dfrac{86}{y}\) 

\(\Rightarrow y^2+5=86\) 

\(\Rightarrow y^2=86-5\) 

\(\Rightarrow y^2=81\) 

\(\Rightarrow\left[{}\begin{matrix}y=9\\y=-9\end{matrix}\right.\) 

Chúc bạn học tốt!

Bài 2 

a)  \(x\times1\frac{1}{4}=3\frac{3}{4}\)

\(x\times\frac{5}{4}=\frac{15}{4}\)

\(x=\frac{15}{4}.\frac{4}{5}\)

\(x=3\)

b) \(x-\frac{3}{4}=6\times\frac{3}{8}\)

\(x-\frac{3}{4}=\frac{9}{4}\)

\(x=\frac{9}{4}+\frac{3}{4}\)

\(x=3\)

Những câu còn lại tương tự

\(x+\frac{2}{3}=2\frac{1}{2}\)

\(x+\frac{2}{3}=\frac{5}{2}\)

\(x=\frac{5}{2}-\frac{2}{3}\)

\(x=\frac{11}{6}\)

\(8,75.x+1,25.x=26,3\)

\(x.\left(8,75+1,25\right)=26,3\)

\(x.10=26,3\)

\(x=26,3\div10\)

\(x=2,63\)

\(x-4\frac{5}{6}=2\frac{1}{6}+\frac{5}{6}\)

\(x-\frac{29}{6}=3\)

\(x=\frac{47}{6}\)

\(5\frac{4}{5}+x-7\frac{7}{18}=15\frac{3}{4}\)

\(\frac{29}{5}+x-\frac{133}{18}=\frac{63}{4}\)

\(\frac{29}{5}+x=\frac{63}{4}+\frac{133}{18}\)

\(\frac{29}{5}+x=\frac{259}{8}\)

\(x=\frac{259}{8}-\frac{29}{5}\)

\(x=\frac{1063}{40}\)

1/ 10(X-7)-8(X+5)=6(-5)+24
10x - 70 - 8x - 40 = -30 +24
2x - 110 = -6
2x = 104
x=52

2/ 8(X-|-7|)-6(X-2)=|-8|.6-50
8(x - 7) - 6(x-2) = 8.6 - 50
8x - 56 - 6x +12 =48 -50
2x - 44 = -2
2x = 42
x=21

3/ 2(4X-8)-7(3+X)=|-4|(3-2)
8x-16 - 21 - 7x = 4.1
x-37=4
x=41

4/ 12(X-4)=6(x-2)-16(X+3)=7|-4|
12x - 48 = 6x - 12 - 16x -48 =7.4
12x - 48 = 28
12x=76
x=19/3

5/ 4(X-5)-7(5-X)+10(5-X)=-3
4x - 20 -35 +7x + 50 -10x = -3
x - 5 = -3
x = -2
Chúc bạn học tốt!

\(x+2\dfrac{1}{4}=4\dfrac{5}{6}\)

\(x=4\dfrac{5}{6}-2\dfrac{1}{4}\)

\(x=4+\dfrac{5}{6}-2-\dfrac{1}{4}\)

\(x=2+\dfrac{7}{12}\)

\(x=\dfrac{31}{12}\)

_____________

\(9\dfrac{3}{5}-x=3\dfrac{3}{8}\)

\(x=9\dfrac{3}{5}-3\dfrac{3}{8}\)

\(x=9+\dfrac{3}{5}-3-\dfrac{3}{8}\)

\(x=6+\dfrac{9}{40}\)

\(x=\dfrac{249}{40}\)

\(x+2\dfrac{1}{4}=4\dfrac{5}{6}\)

\(=>x+\dfrac{9}{4}=\dfrac{29}{6}\)

\(=>x=\dfrac{29}{6}-\dfrac{9}{4}=\dfrac{58}{12}-\dfrac{27}{12}\)

\(=>x=\dfrac{31}{12}\)

_______

\(9\dfrac{3}{5}-x=3\dfrac{3}{8}\)

\(=>\dfrac{48}{5}-x=\dfrac{27}{8}\)

\(=>x=\dfrac{48}{5}-\dfrac{27}{8}=\dfrac{384}{40}-\dfrac{135}{40}\)

\(=>x=\dfrac{249}{40}\)

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

\(=>\frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\)

\(\frac{10}{3}x=-30\)

x = -30 : \(\frac{10}{3}\)

= > x = -9

a: \(\Leftrightarrow\left(\dfrac{13}{4}:x\right)\cdot\left(-\dfrac{5}{4}\right)=\dfrac{-10}{6}-\dfrac{5}{6}=\dfrac{-15}{6}=\dfrac{-5}{2}\)

\(\Leftrightarrow\dfrac{13}{4}:x=\dfrac{5}{2}\cdot\dfrac{5}{4}=\dfrac{25}{8}\)

hay \(x=\dfrac{13}{4}:\dfrac{25}{8}=\dfrac{13}{4}\cdot\dfrac{8}{25}=\dfrac{26}{25}\)

b: \(\Leftrightarrow\dfrac{3}{4}:x=\dfrac{11}{36}-\dfrac{1}{4}=\dfrac{2}{36}=\dfrac{1}{18}\)

=>\(x=\dfrac{3}{4}:\dfrac{1}{18}=\dfrac{54}{4}=\dfrac{27}{2}\)

c: \(\Leftrightarrow\left(-\dfrac{6}{5}+x\right):\left(-3.6\right)=-\dfrac{7}{4}+\dfrac{1}{4}\cdot8=\dfrac{1}{4}\)

=>x-6/5=-9/10

=>x=3/10