\(\dfrac{2x-1}{3}=\dfrac{-5}{0,6}\)

⇔\(0,6\left(2x-1\right)=3.-5\)

⇔\(1,2x-0,6=-15\)

⇔\(1,2x=-14,4\)

⇔\(x=-12\)

hay x = -12

Tìm x biết : \(\dfrac{2x-1}{3}=\dfrac{-5}{0,6}\)

\(2x-1=3.\left(\dfrac{-5}{0,6}\right)\)

\(2x-1=3.\left(\dfrac{-50}{6}\right)\)

\(2x-1=3\left(\dfrac{-25}{3}\right)\)

\(2x-1=-25\)

\(2x=-25+1\)

\(2x=-24\)

\(x=\dfrac{-24}{2}\)

\(x=-12\)

x = -12 nha

a) \(\left(2x-1\right)+\frac{3}{15}=\frac{3}{2}\)

\(\Rightarrow2x-1=\frac{3}{2}-\frac{3}{15}=\frac{13}{10}\)

\(\Rightarrow2x=\frac{13}{10}+1=\frac{23}{10}\)

\(\Rightarrow x=\frac{23}{20}\)

b) \(x+\frac{46}{15}=1,5\)

\(\Rightarrow x+\frac{46}{15}=\frac{3}{2}\)

\(\Rightarrow x=\frac{3}{2}-\frac{46}{15}\)

\(\Rightarrow x=\frac{-47}{30}\)

c) \(\left(-2x+1\right)+\frac{3}{15}=\frac{5}{3}\)

\(\Rightarrow-2x+1=\frac{5}{3}-\frac{3}{15}=\frac{22}{15}\)

\(\Rightarrow-2x=\frac{7}{15}\Rightarrow x=\frac{-7}{30}\)

a, \(\dfrac{3}{4}x=-\dfrac{9}{8}\)
x= \(-\dfrac{3}{2}\)
b, |x| + 0,25= 5,25
|x | = 5
=> x\(\in\){ +- 5}
Ko chắc đúng, kiểm tra trc khi làm

\(\dfrac{2x-1}{3}=\dfrac{-5}{0.6}\)

\(\Leftrightarrow2x-1=-25\)

hay x=-12

`@``dn10`

`a,`

`P(x)=-2x^5-3x^4+2x^5+2x-0,6`

`P(x)=(-2x^5+2x^5)-3x^4+2x-0,6`

`P(x)=-3x^4+2x-0,6`

`b,`

Thay `x=1` vào đa thức `B(x)`

`B(1)=-4*1^3+6*1-4=-4*1+6-4=-4+6-4=2-4=-2`

a: =-2x^5+2x^5+3x^4+2x-0,6

=3x^4+2x-0,6

b: B(1)=-4+6-4=-8+6=-2

b: \(x+\dfrac{5}{6}=\dfrac{3}{8}\)

=>\(x=\dfrac{3}{8}-\dfrac{5}{6}\)

=>\(x=\dfrac{9}{24}-\dfrac{20}{24}=-\dfrac{11}{24}\)

c: \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{5}{6}\)

=>\(\dfrac{2}{3}x=\dfrac{5}{6}+\dfrac{1}{2}=\dfrac{8}{6}=\dfrac{4}{3}\)

=>2x=4

=>x=4/2=2

d: \(\dfrac{x}{7}=\dfrac{6}{-21}\)

=>\(\dfrac{x}{7}=\dfrac{-2}{7}\)

=>x=-2

e: \(\left(\dfrac{7}{3}x-0,6\right):\dfrac{3^2}{5}=1\)

=>\(\dfrac{7}{3}x-0,6=\dfrac{3^2}{5}=1,8\)

=>\(\dfrac{7}{3}x=2,4\)

=>\(x=2,4:\dfrac{7}{3}=2.4\cdot\dfrac{3}{7}=\dfrac{7.2}{7}=\dfrac{36}{35}\)

f: \(\dfrac{x}{45}=\dfrac{5}{6}+\dfrac{-29}{30}\)

=>\(\dfrac{x}{45}=\dfrac{25}{30}-\dfrac{29}{30}=-\dfrac{4}{30}=-\dfrac{2}{15}\)

=>\(x=-\dfrac{2}{15}\cdot45=-6\)

g: \(\left(4,5-2x\right)\cdot\left(-\dfrac{1^4}{7}\right)=\dfrac{11}{14}\)

=>\(4,5-2x=\dfrac{11}{14}:\dfrac{-1}{7}=\dfrac{-11}{2}\)

=>\(2x=4,5+\dfrac{11}{2}=\dfrac{20}{2}=10\)

=>x=10/2=5

h: \(-\dfrac{2}{7}+\dfrac{4}{7}x=\dfrac{5}{7}\)

=>\(\dfrac{4}{7}x=\dfrac{5}{7}+\dfrac{2}{7}=\dfrac{7}{7}\)

=>4x=7

=>\(x=\dfrac{7}{4}\)

http://123link.pro/moDVA3N

\(-\frac{16}{3}-2x-1=0,6\)\(=\frac{3}{5}\)

\(\Rightarrow-\frac{16}{3}-2x=\frac{3}{5}+1=\frac{8}{5}\)

\(\Rightarrow2x=-\frac{16}{3}-\frac{8}{5}=-\frac{104}{15}\)

\(\Rightarrow x=-\frac{104}{15}:2=-\frac{52}{15}\)

\(\frac{-16}{3}-2x-1=0,6.\)

\(\frac{-16}{3}-2x=0,6+1\)

\(\frac{-16}{3}-2x=1,6\)

\(2x=\frac{-16}{3}-1,6\)

\(2x=\frac{-104}{15}\)

\(x=\frac{-104}{15}:2\)

\(x=\frac{-52}{15}\)

a ) \(2x:6=5:3\)

\(\Leftrightarrow\frac{2x}{6}=\frac{5}{3}\)

\(\Leftrightarrow2x=5.6:3\)

\(\Leftrightarrow2x=10\)

\(\Leftrightarrow x=5\)

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