( x - 1/2 ) : 2 + 2/3 = 5/6
Giúp mik với ạ
a)x-1/5=y-2/3=z-2/2 và x+2y-z=6
giúp mik câu này vs
\(\dfrac{x-1}{5}=\dfrac{y-2}{3}=\dfrac{z-2}{2}=\dfrac{2y-4}{6}=\dfrac{x-1+2y-4-z+2}{5+6-2}=\dfrac{6-5}{9}=\dfrac{1}{9}\)
\(\Rightarrow\left\{{}\begin{matrix}9x-9=5\\9y-18=3\\9z-18=2\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{14}{9}\\y=\dfrac{7}{3}\\z=\dfrac{20}{9}\end{matrix}\right.\)
Cho S = 1 + 2 + 2^2 + 2^3 + 2^4 + 2^5 +...+ 2^2020 + 2^2021 chia hết cho
A. 10
B. 3
C. 4
D. 6
Giúp mik với
mình đang cần gấp m.n giúp mình nha :33
chia hết cho mấy vậy bạn?
Cho S = 1 + 2 + 2^2 + 2^3 + 2^4 + 2^5 +...+ 2^2020 + 2^2021 chia hết cho
A. 10
B. 3
C. 4
D. 6
Giúp mik với
( y – 2/3 ) : 4/5 = 5/6
Giúp mình với ạ!
\(\left(y-\dfrac{2}{3}\right):\dfrac{4}{5}=\dfrac{5}{6}\)
\(y-\dfrac{2}{3}=\dfrac{5}{6}\times\dfrac{4}{5}\)
\(y-\dfrac{2}{3}=\dfrac{2}{3}\)
\(y=\dfrac{2}{3}+\dfrac{2}{3}\)
\(y=\dfrac{4}{3}\)
\(y-\dfrac{2}{3}=\dfrac{5}{6}\times\dfrac{4}{5}\)
\(y-\dfrac{2}{3}=\dfrac{2}{3}\)
\(y=\dfrac{2}{3}+\dfrac{2}{3}\)
\(y=\dfrac{4}{3}\)
y – 2/3 = 5/6 x 4/5
y – 2/3 = 2/3
y= 2/3 + 2/3
y = 4/3
0,5x-2/3.(x-2)=1/6
Giúp mik vs.Mik đg gấp.Pls!!!
0,5x-\(\dfrac{2}{3}.\left(x-2\right)=\dfrac{1}{6}\)
\(\dfrac{1}{2}x-\dfrac{2}{3}x-\dfrac{4}{3}=\dfrac{1}{6}\)
\(x.\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{1}{6}+\dfrac{4}{3}\)
\(x.\dfrac{7}{6}=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}:\dfrac{7}{6}\)
\(x=\dfrac{9}{7}\)
`0,5x-2/3 .(x-2)=1/6`
`0,5x - 2/3 x + 4/3= 1/6`
` -1/6x = -7/6`
`x=7`
\(0,5x-\dfrac{2}{3}.\left(x-2\right)=\dfrac{1}{6}\)
\(\dfrac{1}{2}x-\dfrac{2}{3}x-\dfrac{4}{3}=\dfrac{1}{6}\)
\(x.\left(\dfrac{1}{2}-\dfrac{2}{3}\right)=\dfrac{1}{6}+\dfrac{4}{3}\)
\(x.\dfrac{-1}{6}=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}:\dfrac{-1}{6}\)
\(x=-9\)
X x 3/5 = 2/3 + 1/6
Giúp mình trình bày với
\(x\times\dfrac{3}{5}=\dfrac{2}{3}+\dfrac{1}{6}=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}:\dfrac{3}{5}=\dfrac{25}{18}\)
\(x\times\dfrac{3}{5}=\dfrac{2}{3}+\dfrac{1}{6}\)
\(x\times\dfrac{3}{5}=\dfrac{4}{6}+\dfrac{1}{6}\)
\(x\times\dfrac{3}{5}=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}:\dfrac{3}{5}\)
\(x=\dfrac{5}{6}\times\dfrac{5}{3}\)
\(x=\dfrac{25}{18}\)
câu 1 : phân tích thành nhân tử .
c,x^2+7x+6
giúp mk với ạ ^^
\(=x^2+x+6x+6\\ =x\left(x+1\right)+6\left(x+1\right)\\ =\left(x+6\right)\left(x+1\right)\)
\(c,x^2+7x+6=x^2+x+6x+6=\left(x^2+x\right)+\left(6x+6\right)=x.\left(x+1\right)+6.\left(x+1\right)=\left(x+1\right).\left(x+6\right)\)
`=> x ^2 + x + 6 x + 6`
`=>x ( x + 1 ) + 6 ( x + 1 )`
`=> ( x + 6 ) ( x + 1 )`
Bài 1 : giải pt
a, 11- 3(2x-1)=-8x+5
b,x-3/5 +1+2x/3=6
GIÚP MK VỚI Ạ ><
a) 11 - 3(2x - 1) = -8x + 5
⇔ 11 - 6x + 3 = -8x + 5
⇔ -6x + 8x = 5 - 11 - 3
⇔ 2x = -9
⇔ x = -9/2
Vậy S = {-9/2}
b) (x - 3)/5 + (1 + 2x)/3 = 6
⇔ 3(x - 3) + 5(1 + 2x) = 6.15
⇔ 3x - 9 + 5 + 10x = 90
⇔ 13x = 90 + 9 - 5
⇔ 13x = 94
⇔ x = 94/13
Vậy S = {94/13}
Biết x+ y + z = 11 và 2x = 3y = z thì giá trị của z - x bằng:
A. 3 B. 1 C. 2 D. 6
Giúp mk với chỉ cần đáp án thôi ạ
\(\Rightarrow\dfrac{2x}{6}=\dfrac{3y}{6}=\dfrac{z}{6}\Rightarrow\dfrac{x}{3}=\dfrac{y}{2}=\dfrac{z}{6}=\dfrac{x+y+z}{3+2+6}=\dfrac{11}{11}=1\\ \Rightarrow\left\{{}\begin{matrix}x=3\\y=2\\z=6\end{matrix}\right.\Rightarrow z-x=6-3=3\left(A\right)\)
12/2 = 2 : ............/ 12 : .............. =..........6
giúp mik với trả lời mik tick cho nhé