tinh nhsnh : 75 x 23 + 25 x 26
NT
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giải phương trình sau
\(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=0\)
Sửa đề: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)Ta có: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)
\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)
mà \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}>0\)
nên 100-x=0
hay x=100
Vậy: S={100}
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Ta có : \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)
\(\Leftrightarrow\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}+5=0\)
\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)
Thấy : \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\ne0\)
\(\Rightarrow100-x=0\)
\(\Leftrightarrow x=100\)
Vậy ...
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6^2 : 4 x 3 + 2 x5^2
5 x 4^2 - 18 : 3^2
80 - (4 x 5^2 - 3 x 2^3)
23 x 75 + 25 + 23 +180
2448 : [199 - (26-6)]
\(\frac{74-x}{26}+\frac{75-x}{25}+\frac{76-x}{24}+\frac{77-x}{23}+\frac{78-x}{22}=-5\)
Tìm X
\(\frac{74-x}{26}+\frac{75-x}{25}+\frac{76-x}{24}+\frac{77-x}{23}+\frac{78-x}{22}=-5\)
\(\frac{74-x}{26}+1+\frac{75-x}{25}+1+\frac{76-x}{24}+1+\frac{77-x}{23}+1+\frac{78-x}{22}=-5+5\)
\(\frac{74-x}{26}+\frac{26}{26}+\frac{75-x}{25}+\frac{25}{25}+\frac{76-x}{24}+\frac{24}{24}+\frac{77-x}{23}+\frac{23}{23}+\frac{78-x}{22}+\frac{22}{22}=0\)
\(\frac{100-x}{26}+\frac{100-x}{25}+\frac{100-x}{24}+\frac{100-x}{23}+\frac{100-x}{22}=0\)
\(\left(100-x\right)\left(\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{23}+\frac{1}{22}\right)=0\)
=>100-x=0 ( \(\left(\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{23}+\frac{1}{22}\right)\ne0\))
x=100
hahaha
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Cộng 1 vào mỗi hạng tử trong vế trái là dc
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a) frac{x-23}{24}+frac{x-23}{25}frac{x-23}{26}+frac{x-23}{27}Leftrightarrowfrac{x-23}{24}+frac{x-23}{25}-frac{x-23}{26}-frac{x-23}{27}0Leftrightarrowleft(x-23right)left(frac{1}{24}+frac{1}{25}-frac{1}{26}-frac{1}{27}right)0Leftrightarrow x-230( vì frac{1}{24}+frac{1}{25}-frac{1}{26}-frac{1}{27}ne0)Leftrightarrow x23Vậy nghiệm của pt x23
Đọc tiếp
a) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\Leftrightarrow\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
\(\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
\(\Leftrightarrow x-23=0\)( vì \(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\ne0\))
\(\Leftrightarrow x=23\)
Vậy nghiệm của pt x=23
1 tinh:
480 : 125 = ?
120 : 75 = ?
2001 : 25 = ?
1999 : 25 = ?
26 : 5 x 3 = ?
39 x 3 = ?
35 x 5 = ?
1)3,84
2)1,6
3)80,04
4)79,96
5)15,6
6)117
7)175
Chúc bạn học tốt!
k cho mình nhé! cảm ơn nhiều!
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480 : 125 = 3,84
120 : 75 = 1,6
2001 : 25 = 80,04
1999 : 25 = 79,96
26 : 5 x 3 = 15,6
39 x 3 = 117
35 x 5 = 175
tk mk nha bn
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480 : 125 = 3,84
120 : 75 = 1,6
2001 : 25 = 80,04
1999 : 25 = 79,96
26 : 5 x 3 = 43,333....
39 x 3 = 117
35 x 5 = 175
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x-23/24 + x-23/25=x-23/26 + x-23/27
\(\dfrac{x-23}{24}\)+\(\dfrac{x-23}{25}\)=\(\dfrac{x-23}{26}\)+\(\dfrac{x-23}{27}\)
tinh nhanh
237 . (-26) + 26 .137
63. ( -25 ) + 25 . ( - 23 )
237.(-26)+26.137= (-237+137).26= -100.26= -2600
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237.(-26) + 26.137 = 26.137 - 26.237 = (137 - 237).26 = -100.26 = -2600
63.(-25) + 25.(-23) = -23.25 - 63.25 = (-23 - 63).25 = -89.25 = -2225
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Bai 1
Thuc hien phep tinh
a,(135-35) .(-47)+53 .(-48-52)
b,25 .(75-49)+75 .|25-49|
Bai 2
Tim x\(\varepsilon\)Z biet
a,(-x+31)-39=-69+11
b,x-{57-[42+(-23-x)]}=13-{47+[25-(32-x)]}
c,|2-x|+2=x
Giup minh voi
Tập ghi có dấu đi bạn ei
ghi như thế méo ai hiểu đâu
và......kết bạn nha!
>< :3 :))
a. ( 135 - 35 ) ( -47 ) + 53 ( -48 - 52 )
= 100 ( -47 ) + 53 ( -100 )
= -4700 + -5300
= -10000
b. 25 ( 75 - 49 ) + 75 | 25 - 49 |
= 25 . 26 + 75 | -24 |
= 650 + 75 . 24
= 650 + 1800
=2450
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