2x+3.(2x-4)=36
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Những câu hỏi liên quan
24x-4(2x-3/4)-4(3+2x/2)=36-3(x-3/2)-3(3-2x/3)
\(24x-4\left(2x-\frac{3}{4}\right)-4\left(3+\frac{2x}{2}\right)=36-3\left(x-\frac{3}{2}\right)-3\left(3-\frac{2x}{3}\right)\)
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Bài 20*: Tìm x,y nguyên sao cho.1) 2y. (x+1)=6 2) (2x-1). (y-2)=6 3) (2x-4). 2y= -12 4) (2x-2y).3x=-36 5) (x+y+1). (2y+3)=36
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Rút gọn :
1. (2x-5)(3x+1)-(x-3)^2+(2x+5)^2-(3x+1)^3
2. (2x-1)(2x+1)-3x-2)(2x+3)-(x-1)^3+(2x+3)^3
3. (x-2)(x^2+2x+4)-(3x-2)^3+(3x-4)^2
4. (7x-1)(8x+2)-(2x-7)^2-(x-4)^3-(3x+1)^3
5. (5x-1)(5x+1)-(x+3)(x^2-3x+9)-(2x+4)^2-(3x-4)^2+(2x-5)^3
6. (4x-1)(x+2)-(2x+5)^2-(3x-7)^2+(2x+3)^3=(3x-1)^3
1: \(=6x^2+2x-15x-5-x^2+6x-9+4x^2+20x+25-27x^3-27x^2-9x-1\)
=-27x^3-18x^2+4x+10
2: =4x^2-1-6x^2-9x+4x+6-x^3+3x^2-3x+1+8x^3+36x^2+54x+27
=7x^3+37x^2+46x+33
5:
\(=25x^2-1-x^3-27-4x^2-16x-16-9x^2+24x-16+\left(2x-5\right)^3\)
\(=8x^3-60x^2+150-125+12x^2-x^3+8x-60\)
=7x^3-48x^2+8x-35
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Tìm x a, (4x-15)-(2x-3)=36 b, 2x-4=x+5
a: =>4x-15-2x+3=36
=>2x-12=36
=>2x=48
hay x=24
b: =>2x-x=5+4
hay x=9
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Thực hiện phép tính : a) (x-3)(2x - 4) - 2x(x - 5) c) (3x²-17x² + 11x +15): (3x-5) d) b) (2x-5)²-(2x - 3)(2x + 3) 5x² x+2 x 2-x 4x x²-4 e) x-3 x+3 x + 36 x-3 9-x²
a: \(=2x^2-4x-6x+12-2x^2+10x=12\)
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[(2x-4)+9]3=36
\(\left[\left(2x-4\right)+9\right]^3=3^6\)
\(\Leftrightarrow2x-4=0\)
hay x=2
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cíu tui zới
tui hứa sẽ tick
3) 2x + 3 + 2x = 36
4) 4x+1 - 22x = 12
5) 5x+3 - 5x+1= 3000
4) 4x+1 - 22x
3) \(...\Rightarrow2^x\left(2^3+1\right)=36\)
\(\Rightarrow2^x.9=36\)
\(\Rightarrow2^x=4\)
\(\Rightarrow2^x=2^2\Rightarrow x=2\)
4) \(...\Rightarrow4^{x+1}-4^x=12\)
\(\Rightarrow4^x\left(4-1\right)=12\)
\(\Rightarrow4^x.3=12\)
\(\Rightarrow4^x=4=4^1\Rightarrow x=1\)
5) \(...\Rightarrow5^{x+1}\left(5^2-1\right)=3000\)
\(\Rightarrow5^{x+1}.24=3000\)
\(\Rightarrow5^{x+1}=125\)
\(\Rightarrow5^{x+1}=5^3\)
\(\Rightarrow x+1=3\)
\(\Rightarrow x=2\)
6) Bạn xem lại đề
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a. \(2^x.2^3+2^x=36\)
\(2^x\left(2^3+1\right)=36\)
\(2^x.9=36\)
\(2^x=4\Rightarrow x=2\)
b. \(4^x.4^1-\left(2^2\right)^x=12\)
\(4^x.4-4^x=12\)
\(4^x\left(4-1\right)=12\)
\(4^x.3=12\)
\(4^x=4\)
x = 1
c. \(5^x.5^3-5^x.5^1=3000\)
\(5^x\left(5^3-5^1\right)=3000\)
\(5^x.120=3000\)
\(5^x=25\)
x = 2
d. \(4^{x+1}=2^{2x}\)
\(4^x.4=\left(2^2\right)^x\)
\(4^x.4=4^x\)
Có vẻ như câu 4 này để bài thiếu
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4/2x+3/=36
4/2x+3/ = 36
/2x+3/ = 36 : 4
/2x+3/ = 9
\(\Rightarrow\left[{}\begin{matrix}2x+3=9\\2x+3=-9\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=9-3\\2x=\left(-9\right)-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=6\\2x=-12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=6:2\\x=\left(-12\right):2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-6\end{matrix}\right.\)
Vậy x \(\in\) { 3;-6 }
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4/2x+3/ = 36
/2x+3/ = 36 : 4
/2x+3/ = 9
⇒[2x+3=92x+3=−9⇒[2x+3=92x+3=−9
⇒[2x=9−32x=(−9)−3⇒[2x=9−32x=(−9)−3
⇒[2x=62x=−12⇒[2x=62x=−12
⇒[x=6:2x=(−12):2⇒[x=6:2x=(−12):2
⇒[x=3x=−6⇒[x=3x=−6
Vậy x ∈∈ { 3;-6 }
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(2x+1)^3=125
(2x-1)^4=16
6.3^x-2.3^x=36
2^x+1-2^x=32
\(\left(2x+1\right)^3=125\\ \Rightarrow\left(2x+1\right)^3=5^3\\ \Rightarrow2x+1=5\\ \Rightarrow2x=4\\ \Rightarrow x=2.\\ b,\left(2x-1\right)^4=16\\ \Rightarrow\left(2x-1\right)^4=2^4\\ \Rightarrow2x-1=2\\ \Rightarrow2x=3\\ \Rightarrow x=\dfrac{3}{2}.\\ c,6.3^x-2.3^x=36\\ \Rightarrow3^x.\left(6-2\right)=36\\ \Rightarrow3^x.4=36\\ \Rightarrow3^x=9\\ \Rightarrow3^x=3^2\\ \Rightarrow x=2.\\ d,2^{x+1}-2^x=32\\ \Rightarrow2^x.\left(2-1\right)=32\\ \Rightarrow2^x=2^5\\ \Rightarrow x=5.\)
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