(2x+1)6-24=3.24
NT
Những câu hỏi liên quan
So sánh
a) 3^300+4^300 và 3.24^100
b) 2^23+1/2^28+1 và 2^25+1/2^24+1
So sánh :
a) 3300 + 4300 và 3.24100
b) \(\frac{2^{23}+1}{2^{24}+1}\) và \(\frac{2^{24}+1}{2^{25}+1}\)
bài 1 :tìm x , biết :
(x-7)^ x+1(x-7)^x+11=0
bài 2 :tìm x , biết :
a,|2x-3| > 5 c,|3x-1| ≤ 7 d,|3x-5| + |2x+3| = 7
bài 3 :
a,tính tổng S = 1 + 5^2 + 5^4 + ....... + 5^200.
b,so sánh 2^30 + 3^30 + 4^30 và 3.24^10
\(\frac{2x+1}{6}=\frac{24}{2x+1}\)
\(\frac{2x+1}{6}=\frac{24}{2x+1}\)
Theo đề bài ta có:
\(\left(2x+1\right)\left(2x+1\right)=24.6=144\)
\(\Rightarrow\left(2x+1\right)^2=144\)
\(\Rightarrow2x+1=12\)
\(\Rightarrow2x=12-1\)
\(\Rightarrow2x=11\)
\(\Rightarrow x=\frac{11}{2}\)
\(\Rightarrow5,5\)
Vậy x = 5,5
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Ta có: \(\frac{2x+1}{6}=\frac{24}{2x+1}\Rightarrow\left(2x+1\right)^2=24\times6=144\)
\(\Rightarrow2x+1=\sqrt{144}=12\)
\(\Rightarrow2x=12-1=11\Rightarrow x=\frac{11}{2}=5,5\)
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Ta có : 2x + 1 / 6 = 24 / 2x + 1 => ( 2x + 1 )2 = 24 x 6 = 144
=> 2x + 1 = căn 144 = 12
=> 2x = 12 - 1 = 11 => x = 11/2 = 5,5
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Cho biểu thức: \(M=\left(\dfrac{1+2x}{4+2x}-\dfrac{x}{3x-6}+\dfrac{2x^2}{12-3x^2}\right).\dfrac{24+12x}{6+13x}\)
a) 10-{[(x:3+17):10+3.24 ]:10}=5
b) 2448:[119-(x-6)]=24
c)165-(35:x+3).19=13
a: Ta có: \(10-\left\{\left[\left(x:3+17\right):10+3\cdot2^4\right]:10\right\}=5\)
\(\Leftrightarrow\left[\left(x:3+17\right):10+48\right]:10=5\)
\(\Leftrightarrow\left(x:3+17\right):10+48=50\)
\(\Leftrightarrow\left(x:3+17\right):10=2\)
\(\Leftrightarrow x:3+17=20\)
\(\Leftrightarrow x:3=3\)
hay x=9
b: Ta có: \(2448:\left[119-\left(x-6\right)\right]=24\)
\(\Leftrightarrow119-\left(x-6\right)=102\)
\(\Leftrightarrow x-6=17\)
hay x=23
c: Ta có: \(165-\left(35:x+3\right)\cdot19=13\)
\(\Leftrightarrow\left(35:x+3\right)\cdot19=152\)
\(\Leftrightarrow\left(35:x+3\right)=8\)
\(\Leftrightarrow35:x=5\)
hay x=7
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3/4.[2x-5]+1/6=5/24
=???
\(\dfrac{3}{4}\left(2x-5\right)+\dfrac{1}{6}=\dfrac{5}{24}\\ \Rightarrow\dfrac{3}{4}\left(2x-5\right)=\dfrac{1}{24}\\ \Rightarrow2x-5=\dfrac{1}{18}\\ \Rightarrow2x=\dfrac{91}{18}\\ \Rightarrow x=\dfrac{91}{36}\)
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15/16 . -7/13 + 15/16 . -6/13 -1/16
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Cho biểu thức: \(M=\left(\dfrac{1+2x}{4+2x}-\dfrac{x}{3x-6}+\dfrac{2x^2}{12-3x^2}\right).\dfrac{24+12x}{6+13x}\). Rút gọn M
1+5^2+5^4+...+5^2x=25^6-1:24
\(A=1+5^2+5^4+...+5^{2x}\)
\(\Rightarrow25A=5^2+5^4+...+5^{2x+2}\)
\(\Rightarrow24A=25A-A=5^2+5^4+...+5^{2x+2}-1-5^2-...-5^{2x}=5^{2x+2}-1\)
\(\Rightarrow A=\dfrac{5^{2x+2}-1}{24}=\dfrac{25^6-1}{24}\)
\(\Rightarrow2x+2=6\Rightarrow x=2\)
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\(A=\left(\dfrac{1+2x}{4+2x}-\dfrac{x}{3x-6}-\dfrac{2x^2}{3x^2-12}\right):\dfrac{6+13x}{24-12}\)
\(A=\left(\dfrac{2x+1}{2\left(x+2\right)}-\dfrac{x}{3\left(x-2\right)}-\dfrac{2x^2}{3\left(x-2\right)\left(x+2\right)}\right)\cdot\dfrac{24-12x}{13x+6}\)
\(=\dfrac{3\left(2x+1\right)\left(x-2\right)-2x\left(x+2\right)-4x^2}{6\left(x-2\right)\left(x+2\right)}\cdot\dfrac{12\left(2-x\right)}{13x+6}\)
\(=\dfrac{3\left(2x^2-3x-2\right)-2x^2-4x-4x^2}{x+2}\cdot\dfrac{-2}{13x+6}\)
\(=\dfrac{6x^2-9x-6-6x^2-4x}{x+2}\cdot\dfrac{-2}{13x+6}=\dfrac{2}{x+2}\)
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