a,\(2\left(2x-3\right)\ge5\left(2+x\right)+13\)

\(\Leftrightarrow4x-6\ge10+5x+13\)

\(\Leftrightarrow4x-5x\ge10+13+6\)

\(\Leftrightarrow-x\ge29\)

\(\Leftrightarrow x\ge-29\)

a,

x=-36

x=11

x=100

x=14

x=-36

x=11

x=100

x=14

2: \(\Leftrightarrow\left(\dfrac{x+1}{12}-1\right)+\left(\dfrac{x+2}{13}-1\right)=\left(\dfrac{x+3}{14}-1\right)+\left(\dfrac{x+4}{15}-1\right)\)

=>x-11=0

=>x=11

3: \(\Leftrightarrow\left(\dfrac{x-85}{15}-1\right)+\left(\dfrac{x-74}{13}-2\right)+\left(\dfrac{x-67}{11}-3\right)+\left(\dfrac{x-64}{9}-4\right)=0\)

=>x-100=0

=>x=100

Câu 2: 

a: \(x^{10}=1^x\)

\(\Leftrightarrow x^{10}=1\)

=>x=1 hoặc x=-1

b: \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Leftrightarrow\left(2x-15\right)^3\left[\left(2x-15\right)^2-1\right]=0\)

\(\Leftrightarrow\left(2x-15\right)^3\cdot\left(2x-16\right)\left(2x-14\right)=0\)

hay \(x\in\left\{\dfrac{15}{2};8;7\right\}\)

c: \(x^{10}=x\)

\(\Leftrightarrow x\left(x^9-1\right)=0\)

=>x=0 hoặc x=1

c , d giải nốt:

c) 2x + 3/6 = 7x - 13/15

=> (2x + 3) . 15 = (7x - 13) x 6

=> 30x +45 = 42x - 78

=> 30x - 42x = -78 - 45

=> -12x = -123

=> x = 41/4

d) 2-x/4 = 3x - 1/ - 3

=> (2-x) . -3 = 4. (3x - 1)

=> -6 - (-3x) = 12x - 4

(-6) + 4 = 12x - - (-3x)

=> -2 = 9x

=> x = -2/9    

Rút gọn hết ta được :

a/ 41x - 17 = -21

=> 41x = -4 => x = 4/41

b/ 34x - 17 = 0 

=> 34x = 17

=> x = 17/34 = 1/2

c/ 19x + 56 = 52 

=> 19x = -4

=> x = -4/19

d/ 20x² - 16x - 34 = 10x² + 3x - 34

=> 10x² - 19x = 0

=> x(10x - 19) = 0

=> x = 0 

hoặc 10x - 19 = 0 => 10x = 19 => x = 19/10

Vậy x = 0 ; x = 19/10

Rút gọn hết ta được :

a/ 41x - 17 = -21

=> 41x = -4 => x = 4/41

b/ 34x - 17 = 0

=> 34x = 17

=> x = 17/34 = 1/2

c/ 19x + 56 = 52

=> 19x = -4

=> x = -4/19

d/ 20x 2 - 16x - 34 = 10x 2 + 3x - 34

=> 10x 2 - 19x = 0

=> x(10x - 19) = 0

=> x = 0 hoặc 10x - 19 = 0

=> 10x = 19

=> x = 19/10

Vậy x = 0 ; x = 19/10 

a) ( 6x - 3 ) ( 2x + 4 ) + ( 4x - 1 ) ( 5 - 3x ) = -21

<=> 12x² + 24x - 6x - 12 + 20x - 12x² - 5 + 3x = -21

<=> 41x = -21 + 12 + 5 

<=> 41x = -4

<=> x = -4/41

a) \(\left(2x-1\right)+\frac{3}{15}=\frac{3}{2}\)

\(\Rightarrow2x-1=\frac{3}{2}-\frac{3}{15}=\frac{13}{10}\)

\(\Rightarrow2x=\frac{13}{10}+1=\frac{23}{10}\)

\(\Rightarrow x=\frac{23}{20}\)

b) \(x+\frac{46}{15}=1,5\)

\(\Rightarrow x+\frac{46}{15}=\frac{3}{2}\)

\(\Rightarrow x=\frac{3}{2}-\frac{46}{15}\)

\(\Rightarrow x=\frac{-47}{30}\)

c) \(\left(-2x+1\right)+\frac{3}{15}=\frac{5}{3}\)

\(\Rightarrow-2x+1=\frac{5}{3}-\frac{3}{15}=\frac{22}{15}\)

\(\Rightarrow-2x=\frac{7}{15}\Rightarrow x=\frac{-7}{30}\)

a; -2\(x\) - 3.(\(x-17\)) = 34 - 2.( - \(x\) + 25)

    - 2\(x\) - 3\(x\) + 51 = 34 + 2\(x\) - 50

       2\(x\) + 2\(x\) + 3\(x\) = - 34 + 50 + 51

            7\(x\)            = 67

               \(x\)           =  67 : 7

                \(x\)         =  \(\dfrac{67}{7}\)

Vậy \(x\) = \(\dfrac{67}{7}\) 

b; 17\(x\) + 3.(- 16\(x\) - 37) = 2\(x\) + 43 - 4\(x\)

    17\(x\) - 48\(x\)  - 111 =  2\(x\) - 4\(x\) + 43

    - 31\(x\) - 2\(x\) + 4\(x\) = 111 + 43

        - \(x\) x (31 + 2 - 4) = 154

        - \(x\) x (33 - 4) =  154

         - \(x\) x 29 = 154

         - \(x\)         = 154 : (-29)

           \(x\)        = - \(\dfrac{154}{29}\)

          Vậy \(x=-\dfrac{154}{29}\) 

c; {-3\(x\) + 2.[45 - \(x\) - 3(3\(x\) + 7) - 2\(x\)] + 4\(x\) } = 55

    {-3\(x\) + 2.[45 - \(x\) - 9\(x\) - 21 - 2\(x\)] + 4\(x\)} = 55

    {- 3\(x\) + 2.[(45 - 21) - (\(x+9x\)+2\(x\))] + 4\(x\) } = 55

     { (- 3\(x\) + 4\(x\)) + 2.[24 - 12\(x\)] } = 55

                   \(x\) + 48 - 24\(x\) = 55

                   \(x-24x\)         = 55 - 48

                     - 23\(x\)           = 7

                            \(x\)           = 7 : - 23

                             \(x=-\dfrac{7}{23}\)

Vậy \(x=-\dfrac{7}{23}\)