A: Oh! Look at that house, it's so beautiful.
B: Yes, It's C's house. It's bigger than my house and yours, too.
C: Hello guys, what are you talking about?
B: We are talking about your house. Uhm...Hey C, How many rooms are there in your house?
C: There are 10 rooms in my house and a big garden behind its.
A: Is it expensive?
C: Yeah, It's nearly 1,5 billions.
A: OMG, your house is more expensive than mine. My house only need about 1 billions to buy it!
B: Your house looks like very convinient.
C: You are right. Do you see our school? It takes me 5 mins to walk to school, so it's the reason why I never late for school.
A: Really? I have many things not as well as you.....
B: It's ok A. You can have it when you learn better than now

Có gì sai sót bạn cứ nói nhé, mình chỉ kịp nghĩ ra đúng đủ 12 câu thôi bạn ạ :)))))

A: Oh! Look at that house, it's so beautiful.
B: Yes, It's C's house. It's bigger than my house and yours, too.
C: Hello guys, what are you talking about?
B: We are talking about your house. Uhm...Hey C, How many rooms are there in your house?
C: There are 10 rooms in my house and a big garden behind its.
A: Is it expensive?
C: Yeah, It's nearly 1,5 billions.
A: OMG, your house is more expensive than mine. My house only need about 1 billions to buy it!
B: Your house looks like very convinient.
C: You are right. Do you see our school? It takes me 5 mins to walk to school, so it's the reason why I never late for school.
A: Really? I have many things not as well as you.....
B: It's ok A. You can have it when you learn better than now

bài j vậy bn

? đề đâu

chiu ma lai

II.

1. D

2. A

3. B

4. C

5. D (đoán thế)

III.

1. playing

2. car

3. hobby

4. flu

5. weight

6. homeless

IV:

1. C

2. C

3. D

I:Đáp án

1a

2b

3c

4a

5c

Lời giải:

$\frac{b}{2}=\frac{c}{5}\Leftrightarrow \frac{b}{4}=\frac{c}{10}$

Vậy: $\frac{a}{3}=\frac{b}{4}=\frac{c}{10}$

Áp dụng tính chất dãy tỉ số bằng nhau:

$\frac{a}{3}=\frac{b}{4}=\frac{c}{10}=\frac{a+b-c}{3+4-10}=\frac{3}{-3}=-1$

$\Rightarrow a=-1.3=-3; b=-1.4=-4; c=-1.10=-10$

3: Ta có: A=B|x-4|

\(\Leftrightarrow\dfrac{\sqrt{x}-2}{\sqrt{x}-5}:\dfrac{1}{\sqrt{x}-5}=\left|x-4\right|\)

\(\Leftrightarrow\left|x-4\right|=\sqrt{x}-2\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=\sqrt{x}-2\left(x\ge4;x\ne25\right)\\x-4=2-\sqrt{x}\left(0< x< 4\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-\sqrt{x}-2=0\\x+\sqrt{x}-6=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\left(nhận\right)\\x=4\left(loại\right)\end{matrix}\right.\)

1: Thay x=9 vào A, ta được:

\(A=\dfrac{3-2}{3-5}=\dfrac{-1}{-2}=\dfrac{1}{2}\)

2: Ta có: \(B=\dfrac{3}{\sqrt{x}+5}+\dfrac{20-2\sqrt{x}}{x-25}\)

\(=\dfrac{3\sqrt{x}-15+20-2\sqrt{x}}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}\)

\(=\dfrac{1}{\sqrt{x}-5}\)

A

A