1.
A= (3/10 - 4/15 - 7/20) . 5/19 / [1/14 + 1/7 - (-3/35)] . -4/3
NA
Những câu hỏi liên quan
(3/10-4/15-7/20)×5/19
-------------------------------------
[1/14+1/7-(-3/35)]×(-4/3)
(3/10-4/15-7/20).5/19 trên (1/14+1/7+3/35).-4/3
tính: (9/10-4/15-7/20).5/19/(1/14+1/7+3/35).-4/5
Tính
( 3/10 - 4/15 - 7/20 ) * 5/19
(1/14 + 1/7 + 3/35 ) * -4/3
\(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right)\cdot\frac{5}{19}}{\left(\frac{1}{14}+\frac{1}{7}+\frac{3}{35}\right)\cdot\left(\frac{-4}{3}\right)}=\frac{\left(\frac{18}{60}-\frac{16}{60}-\frac{21}{60}\right)\cdot\frac{5}{19}}{\left(\frac{5}{70}+\frac{10}{70}+\frac{6}{70}\right)\cdot\left(\frac{-4}{3}\right)}=\frac{\left(\frac{-19}{60}\right)\cdot\frac{5}{19}}{\frac{3}{10}\cdot\left(\frac{-4}{3}\right)}\)
\(=\frac{\frac{-1}{12}}{\frac{-2}{5}}=\left(\frac{-1}{12}\right):\left(\frac{-2}{5}\right)=\frac{5}{24}\)
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Tính bằng cách hợp lý :
[(3/10- 4/15 - 7/20).5/19] / {[1/14+1/7- (-3) /35].[(-4)/3]
\(\dfrac{\left[\left(\dfrac{3}{10}-\dfrac{4}{15}-\dfrac{7}{20}\right)\cdot\dfrac{5}{19}\right]}{\left[\dfrac{1}{14}+\dfrac{1}{7}-\dfrac{\left(-3\right)}{35}\right]\cdot\left(-\dfrac{4}{3}\right)}\)
\(=\dfrac{\left(\dfrac{18}{60}-\dfrac{16}{60}-\dfrac{21}{60}\right)\cdot\dfrac{5}{19}}{\left(\dfrac{5}{70}+\dfrac{10}{70}+\dfrac{6}{70}\right)\cdot\dfrac{-4}{3}}=\dfrac{\dfrac{-19}{60}\cdot\dfrac{5}{19}}{\dfrac{21}{70}\cdot\dfrac{-4}{3}}\)
\(=-\dfrac{1}{12}:\dfrac{-2}{5}=\dfrac{1}{12}\cdot\dfrac{5}{2}=\dfrac{5}{24}\)
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tính
a. 1/100.99 - 1/ 99.98 - 1/98-97 -........- 1/3.2-1/2.1
b . ( 3/10-4/15-7/20).5/19 / ( 1/14+1/7- -3/35 ). -4/3
A=\(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{19}}{\left(\frac{1}{14}+\frac{1}{7}-\frac{-3}{35}\right).\frac{-4}{3}}\)
a)(3/10-4/15-7/20).5/19 / (1/14+1/7-(-3/35)).(-4/3)
b)(1+2+3+...+100).(1/3-1/5-1/7-1/9).(6,3.12-21.3,6) / 1/2+1/3+1/4+...+1/100
LÀM GIÚP MIK VỚI Ạ MIK GẤP LẮM RỒI
\(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{19}}{\left(\frac{1}{14}+\frac{1}{7}-\frac{-3}{35}\right).\frac{-4}{3}}=???\)
\(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{19}}{\left(\frac{1}{14}+\frac{1}{7}-\frac{-3}{35}\right).\frac{-4}{3}}=\frac{\left(\frac{18}{60}-\frac{16}{60}-\frac{21}{60}\right).\frac{5}{19}}{\left(\frac{5}{70}+\frac{7}{70}-\frac{-6}{70}\right).\frac{-4}{3}}\)
\(=\frac{-\frac{19}{60}.\frac{5}{19}}{\frac{3}{10}.\frac{-4}{3}}=\frac{-\frac{1}{12}}{-\frac{2}{5}}=\frac{5}{24}\)
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\(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{19}}{\left(\frac{1}{14}+\frac{1}{7}-\frac{-3}{35}\right).-\frac{4}{3}}=\frac{\left(\frac{18}{60}-\frac{16}{60}-\frac{21}{60}\right).\frac{5}{19}}{\left(\frac{5}{70}+\frac{10}{70}-\frac{-6}{70}\right).\frac{-4}{3}}=\frac{\left(-\frac{19}{60}\right).\frac{5}{19}}{\frac{3}{10}.-\frac{4}{3}}=\frac{\left(-\frac{1}{12}\right)}{\left(-\frac{2}{5}\right)}=\left(\frac{-1}{12}\right).\left(-\frac{5}{2}\right)=\frac{5}{24}\)
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