a) (7x – 15).8 – 21 = 27
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a) (7x – 15).8 – 21 = 27
(7x - 15).8 - 21 = 27
(7x - 15).8 = 27 + 21
(7x - 15).8 = 48
7x - 15 = 48:8
7x - 15 = 6
7x = 6 + 15
7x = 21
x = 21 : 7
x = 3
Vậy x = 3
(7x - 15).8 - 21 = 27
(7x - 15).8 = 27 + 21
(7x - 15).8 = 48
7x - 15 = 48:8
7x - 15 = 6
7x = 6 + 15
7x = 21
x = 21 : 7
x = 3
Vậy x = 3
a) (7x – 15).8 – 21 = 27
a: =>(7x-15)x8=48
=>7x-15=6
=>7x=21
hay x=3
\(\left(7x-15\right)8=27+21\\ \left(7x-15\right)8=48\\ 7x-15=48:8\\ 7x-15=6\\ 7x=6+15\\ 7x=21\\ x=21:7\\ x=3\)
\(\left(7x-15\right).8-21=27\\ \Rightarrow\left(7x-15\right).8=48\\ \Rightarrow7x-15=6\\ \Rightarrow7x=21\\ \Rightarrow x=3\)
3. tìm số tự nhiên x biết
a 100 - 7x [ x - 5] = 58
b 24+5 nhân x = 49
c x- 105 : 21 = 15
d { x- 105] : 21 =15
a, 100 - 7 x ( x - 5 ) = 58
7 x ( x - 5 ) = 100 - 58
7 x ( x - 5 ) = 42
( x - 5 ) = 42 : 7
x - 5 = 6
x = 6 + 5
x = 11
b, 24 + 5 * x = 49
5 * x = 49 - 24
5 * x = 25
x = 25 : 5
x = 5
c, x - 105 : 21 = 15
x - 5 = 15
x = 15 + 5
x = 20
d, ( x - 105 ) : 21 = 15
( x - 105 ) = 15 x 21
x - 105 = 315
x = 315 + 105
x = 420
3. tìm số tự nhiên x biết
a 100 - 7x [ x - 5] = 58
b 24+5 nhân x = 49
c x- 105 : 21 = 15
d { x- 105] : 21 =15
a, 100 - 7 x ( x - 5 ) = 58
7 x ( x - 5 ) = 100 - 58
7 x ( x - 5 ) = 42
( x - 5 ) = 42 : 7
x - 5 = 6
x = 6 + 5
x = 11
b, 24 + 5 * x = 49
5 * x = 49 - 24
5 * x = 25
x = 25 : 5
x = 5
Tìm x, y nguyên
a, xy + 5x - 3y - 15 = 7
b, xy + 7x -4y = 21
a, => x ( y + 5 ) - 3 ( y + 5 ) = 7
=> ( x - 3 )( y+ 5 ) = 7
MÀ 7 = 1.7 = 7.1 = -1.-7 = -7.-1
(+) với x - 3 = 1 và y + 5 = 7
=> x = 4 và y = 2
(+) xét tương tự ba trường hợp còn lại
b, xy + 7x - 4y = 21
=> x( x + 7 ) - 4y - 28 = 21 - 28
=> x(x+7) - 4 ( x+ 7 )= -7
=> ( x - 4 )( x + 7 ) = -7
-7 = 1.-7 = -7.1 = -1.7 = 7.-1
(+) cũng xét 4 TH
Tìm x, y là số nguyên
a, xy + 5x - 3y - 15 = 7
b, xy + 7x -4y = 21
Ban thich co vua lam hay sao ma dat ten la chess vay
(7x+15)-(2x-6)-21=-125
\(\left(7x+15\right)-\left(2x-6\right)-21=-125\)
\(\Leftrightarrow7x+15-2x+6=-104\)
\(\Leftrightarrow5x+21=-104\)
\(\Leftrightarrow5x=-125\)
\(\Leftrightarrow x=-25\)
(7x+15)-(2x-6)-21=-125
<=>7x+15-2x+6-21=-125
<=>5x=-125
<=>x=-25
Vậy x=-25
hok tốt
a, 3-x=x-5 b, 7x+21=0 c, 0,25x+1,5=0 d, 6,36-5,3x=0
e, 3x+1=7x-11 f, 15-4x=6x+5 g, 2(x+1)=3+2x
h, 3(1-x)+4x-3 = 0
a: =>-2x=-8
hay x=4
b: =>7x=-21
hay x=-3
c: =>0,25x=-1,5
hay x=-6
d: =>5,3x=6,36
hay x=6/5
e: =>-4x=-12
hay x=3
f: =>-10x=-10
hay x=1
g: =>2x+2-3-2x=0
=>-1=0(vô lý)
h: =>3-3x+4x-3=0
=>x=0
a,
\(3-x=x-5\\ \Leftrightarrow3x-x+5=0\Leftrightarrow2x+5=0\)
\(\Rightarrow x=-\dfrac{5}{2}\)
b, \(\Rightarrow x=-\dfrac{21}{7}=-3\)
c, \(\Leftrightarrow x=\left(0-1,5\right):0,25=-6\)
a. <=> 2x=8 hay x=4
b.<=> x= -21/7 = -3
c. <=> x= -1,5/ 0,25=-6
d. <=> x= -6,36/-5,3=1,2
e.<=> 4x=12 hay x= 3
f. <=> 10x = 10 hay x = 1
g. <=> 2x +2 = 3 + 2x
<=> 2=3 ( vô lí )
h.<=> 3 - 3x + 4x -3 =0
<=> x=0
Phân tích thành nhân tử
\(x^2+5x+4\\ x^2-7x+6\\ x^2-6x+8\\ x^2-10x+21\\ x^2-2x+8\\ x^2+2x-15\\ x^2-3x-28\)
a.x2+5x+4
=>x2+4x+x+4
=>x(x+4)+x+4
=>(x+4)(x+1)
b. x2-7x=6
=>x2-x-6x=6
=>x(x-1)-6(x-1)
=>(x-1)(x-6)
c.x2-6x+8
=>x2-2x-4x+8
=>x(x-2)-4(x-2)
=>(x-2)(x-4)
d.x2-10x+21
=>x2-3x-7x+21
=>x(x-3)-7(x-3)
=>(x-3)(x-7)
e.Bạn xem lại í e đi xem có đúng đề không?
g.x2+2x-15
=>x2+5x-3x-15
=>x(x+5)-3(x+5)
=>(x-5)(x-3)
h.x2-3x-28
=>x2+4x-7x-28
=>x(x+4)-7(x+4)
=>(x+4)(x-7)
Nhớ tick cho mình nhé
1, \(x^2+5x+4\)
\(=x^2+x+4x+4\)
\(=x\left(x+1\right)+4\left(x+1\right)\)
\(=\left(x+1\right).\left(x+4\right)\)
2, \(x^2-7x+6\)
\(=x^2-x-6x+6\)
\(=x\left(x-1\right)-6\left(x-1\right)\)
\(=\left(x+1\right)\left(x-6\right)\)
3, \(x^2-6x+8\)
\(=x^2-2x-4x+8\)
\(=x\left(x-2\right)-4\left(x-2\right)\)
\(=\left(x-2\right)\left(x-4\right)\)
4, \(x^2-10x+21\)
\(=x^2-3x-7x+21\)
\(=x\left(x-3\right)-7\left(x-3\right)\)
\(=\left(x-3\right)\left(x-7\right)\)
5, \(x^2-2x+8\)
\(=x^2+2x-4x+8\)
\(=x\left(x+2\right)-4\left(x-2\right)\)
\(=x\left(x+2\right)+4\left(x+2\right)\)
\(=\left(x+2\right)\left(x+4\right)\)
6, \(x^2+2x-15\)
\(=x^2+5x-3x-15\)
\(=x\left(x+5\right)-3\left(x+5\right)\)
\(=\left(x+5\right)\left(x-3\right)\)
7, \(x^2-3x-28\)
\(=x^2+4x-7x-28\)
\(=x\left(x+4\right)-7\left(x+4\right)\)
\(=\left(x+4\right)\left(x-7\right)\)
a) \(x^2+5x+4\)
\(=x^2+x+4x+4\)
\(=x\left(x+1\right)+4\left(x+1\right)\)
\(=\left(x+4\right)\left(x+1\right)\)
b) \(x^2-7x+6\)
\(=x^2-x-6x+6\)
\(=x\left(x-1\right)-6\left(x-1\right)\)
\(=\left(x-6\right)\left(x-1\right)\)
c) \(x^2-6x+8\)
\(=x^2-2x-4x+8\)
\(=x\left(x-2\right)-4\left(x-2\right)\)
\(=\left(x-4\right)\left(x-2\right)\)
d) \(x^2-10x+21\)
\(=x^2-3x-7x+21\)
\(=x\left(x-3\right)-7\left(x-3\right)\)
\(=\left(x-7\right)\left(x-3\right)\)
e) \(x^2-2x-8\)
\(=x^2-2x-4-4\)
\(=\left(x-2\right)\left(x+2\right)-2\left(x+2\right)\)
\(=\left(x-2-2\right)\left(x+2\right)=\left(x-4\right)\left(x+2\right)\)
f) \(x^2+2x-15\)
\(=x^2+5x-3x+15\)
\(=x\left(x+5\right)-3\left(x+5\right)\)
\(=\left(x-3\right)\left(x+5\right)\)
g) \(x^2-3x-28\)
\(=x^2+7x-4x-28\)
\(=x\left(x+7\right)-4\left(x+7\right)\)
\(=\left(x-4\right)\left(x+7\right)\)
Bài 1:Tìm x
a) 5x+x=39-3^11:3^9
b) 7x-x=5^21:5^19+3.2^2-7^0
c) 7x-2x =6^17:6^15+44:11