(x-2013)2013=x-2013 tim x và giải thích
tim x; (1+1/2+1/3+...+1/2013).x+2013=2014/1+2015/2+...+4026/2013
câu này cũng không được tick hả thầy @phynit
tim x ;
(1+1/2+1/3+...+1/2013).x+2013=2014/1+2015/2+...+4026/2013
tìm x giải ra cho 10 tick
2013*x+x*(1/2013)-2013=1/2013
GIẢI RA CHO 10 TICK
2013*x +x* 1/2013 = 1/2013 + 2013
x* (2013+1/2013)=1/2013+2013
x = 1
So Sánh : ( giải thích lí do )
a) 2012 x 2010/2011 x 2011 và 2013 x 2009/2014 x 2008
tim x biet (1/2+1/3+...+1/2014).x=2013/1+2012/2+...+1/2013
Giải giúp mk bài toán này: ^^
y x 2016 - y = 2012 x 2013 + 2013 x 2 + 2013
Giải nhanh giúp mk nhé! Mơn nhìu ^^
y x 2016 - y = 2012 x 2013 + 2013 x 2 + 2013
y x 2016 - y = 2013 x ( 2012 + 2 +1 )
y x 2016 - y = 2013 x 2015
y x 2016 - y = 4056195
y x 2015 = 4056195
y = 4056195 : 2015 = 2013
Vậy y = 2013.
k cho mình nha!
y x 2016 - y = 2012 x 2013 + 2013 x 2 + 2013
y x 2016 - y x 1 = 2013 x 2012 + 2013 x 2 + 2013 x 1
y x 2015 = 2013 x [ 2012 + 2 + 1 ]
y x 2015 = 2013 x 2015
Vậy suy ra : y = 2013
Đáp số : 2013
Giải phương trình x-3/2013 + x-2/2014 = x-2014/2 + x-2013/3
\(\dfrac{x-3}{2013}+\dfrac{x-2}{2014}=\dfrac{x-2014}{2}+\dfrac{x-2013}{3}\)
\(\Leftrightarrow\dfrac{x-3}{2013}-1+\dfrac{x-2}{2014}-1=\dfrac{x-2014}{2}-1+\dfrac{x-2013}{3}-1\)
\(\Leftrightarrow\dfrac{x-3-2013}{2013}+\dfrac{x-2-2014}{2014}=\dfrac{x-2014-2}{2}+\dfrac{x-2013-3}{3}\)
\(\Leftrightarrow\dfrac{x-2016}{2013}+\dfrac{x-2016}{2014}=\dfrac{x-2016}{2}+\dfrac{x-2016}{3}\)
\(\Leftrightarrow\dfrac{x-2016}{2013}+\dfrac{x-2016}{2014}-\dfrac{x-2016}{2}-\dfrac{x-2016}{3}=0\)
\(\Leftrightarrow\left(x-2016\right)\left(\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2}-\dfrac{1}{3}\right)=0\)
Vì \(\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2}-\dfrac{1}{3}\ne0\)
\(\Rightarrow x-2016=0\)
\(\Leftrightarrow x=2016\)( thỏa mãn )
Vậy x = 2016
\(\dfrac{x-3}{2013}+\dfrac{x-2}{2014}=\dfrac{x-2014}{2}+\dfrac{x-2013}{3}\)
\(\Leftrightarrow\dfrac{x-3}{2013}-1+\dfrac{x-2}{2014}-1=\dfrac{x-2014}{2}-1+\dfrac{x-2013}{3}-1\)
\(\Leftrightarrow\dfrac{x-2016}{2013}+\dfrac{x-2016}{2014}=\dfrac{x-2016}{2}+\dfrac{x-2016}{3}\)
\(\Leftrightarrow\left(x-2016\right)\left(\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2}-\dfrac{1}{3}\right)=0\)
\(\Leftrightarrow x-2016=0\) (do \(\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2}-\dfrac{1}{3}\ne0\))
\(\Rightarrow x=2016\)
\(\dfrac{x-3}{2013}+\dfrac{x-2}{2014}=\dfrac{x-2014}{2}+\dfrac{x-2013}{3}\)
\(\Leftrightarrow(\dfrac{x-3}{2013}-1)+(\dfrac{x-2}{2014}-1)=(\dfrac{x-2014}{2}-1)+(\dfrac{x-2013}{3}-1)\)
\(\Leftrightarrow\dfrac{x-2016}{2013}+\dfrac{x-2016}{2014}=\dfrac{x-2016}{2}+\dfrac{x-2016}{3}\)
\(\Leftrightarrow\left(x-2016\right)\left(\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2}-\dfrac{1}{3}\right)=0\)
\(\Leftrightarrow x-2016=0\) (Vì \(\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2}-\dfrac{1}{3}\ne0\))
\(\Leftrightarrow x=2016\)
Vậy \(S=\left\{2016\right\}\)
What is the value of the digit in the ones place of the following?
A = 2013 x 2013 x 2013 x.......x 2013 x 2013
2011 thừa số 2013
Ta có:
3 x 3 x 3 x 3 x 3 có chữ số tận cũng là 3
=> cứ 5 số 3 nhân vào nhau ra số tận cùng là 3
=> Số cặp là:
2011 : 5 = 402 cặp dư 1
Vậy số tận cùng là:
3 x 3 = 9
Đ/s:..
2013 x X + X x 1/2013 - 2013 = 1/2013
Xx(2013+1/2013)=1/2013+2013
X=(1/2013+2013):(1/2013+2013)
X=1