j) x + 5 – (-11) = 31 + (-48)
Tìm số nguyên tố x,biết:
a)x+5-(-11)=31-48 b)31+(-21+x)=253 -(25+252)
9 *x -2 *x = 6 mũ 27 / 6 mũ 25 +48 /12
11 mũ x = 5 *x + 5 mũ 31 / 5 mũ 29 +3*2 mũ 2 -10 mũ 0
a) \(9.x-2.x=\frac{6^{27}}{6^{25}}+\frac{48}{12}\)
\(\Leftrightarrow7x=6^2+4\)
\(\Leftrightarrow7x=36+4=40\)
\(\Leftrightarrow x=\frac{40}{7}\)
Vậy : \(x=\frac{40}{7}\)
b) \(11^x=5.x+\frac{5^{31}}{5^{29}}+3.2^2-10^0\)
\(\Leftrightarrow11^x=5x+5^2+12-1\)
\(\Leftrightarrow11^x=5x+36\)
\(\Rightarrow x\in\varnothing\)
31 phần 48; 5 phần 16 ; -11 phần 16 quy dồng ạ
31/48
5x3 / 16x6 = 15/48
-11 x 3/ 16x3 = -33/48
\(\dfrac{31}{48};\dfrac{5}{16};\dfrac{-11}{16}\) MSC 48
\(\dfrac{5}{16}=\dfrac{5\cdot3}{16\cdot3}=\dfrac{15}{48}\)
\(\dfrac{-11}{16}=\dfrac{\left(-11\cdot3\right)}{16\cdot3}=\dfrac{-33}{48}\)
quy đồng mẫu số các phân số sau 31/48 ; 5/16 ; -11/16 eheheheheheheheheheh
\(\dfrac{31}{48};\dfrac{15}{48};\dfrac{-33}{48}\)
Quy đồng mẫu các phân số sâu
a)\(\dfrac{11}{8}\),\(\dfrac{-5}{9}\),\(\dfrac{-7}{12}\) b)\(\dfrac{31}{48}\),\(\dfrac{5}{10}\),\(\dfrac{-11}{16}\)
a: 11/8=99/72
-5/9=-40/72
-7/12=-42/72
a) 2\6 + 8\9= b) 7\24 +5\48 = c) 4 + 11\3 = d) 31\10 + 3 =
Tìm x € Z biết:
a) x - (11 - x) = -48 + (-12 + x)
b) (15 - x) + (x - 12) = 7 - (-8 + x)
c) (x - 12) - (2x + 31) = -6 - 5
d) |x + 5| - (-17) = 20 ; 12x2 - 3x = 0
a) x - (11 - x) = -48 + (-12 + x)
x - 11 + x = -48 + (-12) + x
x + x - x = -48 + (-12) + 11
x + 0 = (-60) + 11
x = -49
b) (15 - x) + (x - 12) = 7 - (-8 + x)
15 - x + x - 12 = 7 + 8 + x
15 - x + x - 12 = 15 + x
x + x - x = 15 - 15 + 12
x + 0 = 0 + 12
x = 12
c) (x - 12) - (2x + 31) = -6 - 5
x - 12 - 2x - 31 = -1
x - 12 - 2x = -1 + 31
x - 12 - 2x = 30
x - 2x = 30 + 12
-1x = 42
=> x = -42
d) |x + 5| - (-17) = 20
=> |x + 5| + 17 = 20
=> |x + 5| = 20 - 17
=> |x + 5| = 3
=> \(\orbr{\begin{cases}x+5=3\\x+5=-3\end{cases}}\)
=> \(\orbr{\begin{cases}x=3-5\\x=-3-5\end{cases}}\)
=> \(\orbr{\begin{cases}x=-2\\x=-8\end{cases}}\)
12x2 - 3x = 0
=> 12x2 - 3x = (22 . 3x2) - 3x = 0
=> 3x . (4x - 1) = 0
=> 3x . 4x - 3x . 1 = 0
=> 3x . 4x - 3x = 0
=> 12x - 3x = 0
=> 4x =0
=> x = 0
Tính hợp lý:
1) 35 x 18 - 5 x 7 x 18
2) 45 - 5 x ( 12 + 9)
3) 24 x ( 16 - 5) - 16 x ( 24 - 5)
4) 29 x ( 19 - 13) - 19 x ( 29 - 13 )
5) 31 x (-18) + 31 x (-81) - 31
6) (-12) x 47 + (-12) x 52 + (-12)
7) 13 x ( 23 + 22 ) - 3 x ( 17 + 28 )
8) -48 + 48 x (-78) + 48 x (-21)
1) = 35 . 18 - 35 . 18 = 0
2) = 45 - 5 . 12 + 5 . 9 = 45 - 60 + 45 = 30
3) = 24 . 16 - 24 . 5 - 16 . 24 - 16 . 5
= (24 . 16 - 16 . 24) - 5 (24 - 16)
= 0 - 5 . 8 = 0 - 40 = -40
4) = 29 . 19 - 29 . 13 - 19 . 29 - 19 . 13
= (29 . 19 - 29 . 19) - 13 (29 - 19)
= 0 - 13 . 10 = 0 - 130 = -130
5) = 31 . (-18) + 31 . (-81) - 31 . 1
= 31 [(-18) + (-81) - 1]
= 31 . (-100) = -3100
6) = (-12) . 47 + (-12) . 52 + (-12). 1
= (-12) . (47 + 52 + 1)
= (-12) . 100 = -1200
7) = 13 . 45 - 3 . 45
= 45 (13 - 3)
= 45 . 10 = 450
8) = (-48) + 48 . (-78) + 48 . (-21)
= (-48) . 1 + 48 . (-78) + 48 . (-21)
= 48 . (-1) + 48 . (-78) + 48 . (-21)
= 48 . [(-1) + (-78) + (-21)]
= 48 . (-100) = -4800
1) 35x18-5x7x18
= 35x18-35x18
= 35x(18-18)
= 35x0=0
3) 24.(16-5)-16.(24-5)
= 24.16-24.5-16.24-16.5
=[24.16-16.24]-[24.5-16.5]
= [ 24. (16-16)]- [(24-16).5]
= [24.0]-[8.5]
= 0-40=-40
4) 29.(19-13)-19.(29-13)
=29.19-29.13-19.29-19.13
=[ 29.19-19.29]-[ 29.13-19.13]
= [ 29.(19-19)]-[(29-19).13]
=[29.0]-[10.13]
= 0-130= -130
5) 31.(-18)+31.(-81)-31
= 31.(-18)+31.(-81)-31.1
= 31.[(-18)+(-81)-1]
=31.(-100)
= -3100
6);7);8 tương tự 4);5);6)
1) 2-x/16= -4/x-2
j) 3/x-5=-4/x+2
h) 3-x/5-x= ( -3/5)^2
v) 12x-15y/7 = 20z-12x/9 = 15y-20z/11 và x+y+z= 48
s) 1+2y/18 = 1+4y/24 = 1+6y/6x