`Tìm` `x`
`|14-19x|` `=` `|7x-15|`
-15+19x=9+7x
`-15 + 19x = 9 + 7x`
`=> 12x = 24`
`=> x = 2`.
x + 3 +7x -19x = 38 , biết x là cùng 1 số, tìm x ?
\(x+3+7x-19x=38\)
\(-11x+3=38\)
\(-11x=38-3\)
\(-11x=35\)
\(x=-\frac{35}{11}\)
( 19x + 2.52 ) : 14= (13 - 8)2 - 4 tìm x
\(...\Rightarrow\left(19x+50\right):14=5^2-4\Rightarrow\left(19x+50\right):14=21\Rightarrow\left(19x+50\right)=21.14\)
\(\Rightarrow19x+50=294\Rightarrow19x=244\Rightarrow x=\dfrac{244}{19}\)
Tìm x
(19x+2.52) :14= (13-8)2 - 42
\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Rightarrow\left(19x+50\right):14=5^2-4^2\)
\(\Rightarrow\left(19x+50\right):14=9\)
\(\Rightarrow19x+50=126\)
\(\Rightarrow19x=76\)
\(\Rightarrow x=4\)
Vậy x = 4
#Kễnh
tìm x
3x^2 - 11x + 8 = 0
7x^2 - 19x = 6
x^3 - 7x^2 + 14x = 8
giải chi tiết giùm mình nha mình cần gấp
(x³ - 4x² - 3x² + 12x + 2x - 8 =0
x²(x - 4) - 3x(x - 4) + 2(x - 4) =0
(x - 4)(x² - 3x + 2) =0
(x - 4)(x - 1)(x - 2) =0
=>X-4=0 hoặc x-1=0 hoặc x-2=0
(tự giải tiếp nhá)
Tìm chữ số tận cùng của:1x 3x 7x 9x 11x 13x 17x 19x ...x 2011x 2013x 2017x 20019
Tìm x
$( 19x + 2 . 5^{2}$ ) ; 14 = $( 13 - 8 )^{2}$ - $4^{2}$
`( 19x + 2*5^2 ) : 14 = ( 13-8)^2 - 4^2`
`=> ( 19x + 50 ) : 14 = 5^2 - 4^2`
`=> ( 19x + 50 ) : 14 = 9`
`=> 19x + 50 = 9*14`
`=> 19x + 50 = 126`
`=> x = ( 126 - 50 )/19`
`=> x = 4`
Vậy `x=4`
(19x + 2.5\(^2\) ) : 14 = 5\(^2\)- 4\(^2\)
(19x + 2.5\(^2\) ) : 14 = 9
19x + 2.5\(^2\) = 9.14
19x + 50 = 126
19x = 126-50=76;19
x = 4
(19x+2.52):14=(13-8)2-42
(19x+2.25):14=52-42
(19x+50):14=25-16
(19x+50):14=9
19x+50=9.14
19x+50=126
19x =126-50
19x =76
x =76:19
x =4
Tìm x :
3/7.(7x+2/3)-2.(5/14-3x)=15/5
\(\frac{3}{7}\left(7x+\frac{2}{3}\right)-2\left(\frac{5}{14}-3x\right)=\frac{15}{5}\)
\(\Leftrightarrow3x+\frac{2}{7}-\frac{5}{7}+6x=3\)
\(\Leftrightarrow9x=\frac{24}{7}\)
\(\Leftrightarrow x=\frac{8}{21}\)
\(\frac{3}{7}.\left(7x+\frac{2}{3}\right)-2.\left(\frac{5}{14}-3x\right)=\frac{15}{5}\)
\(\Leftrightarrow3x+\frac{2}{7}.x-\frac{5}{7}+6x=3\)
\(\Leftrightarrow\frac{65}{7}.x-\frac{5}{7}=3\)
\(\Leftrightarrow\frac{65}{7}.x=3+\frac{5}{7}\)
\(\Leftrightarrow\frac{65}{7}.x=\frac{26}{7}\)
\(\Leftrightarrow x=\frac{26}{7}:\frac{65}{7}\)
\(\Leftrightarrow x=\frac{2}{5}\)
3/7.(7x+2/3)-2.(5/14-3x)=15/5
\(\Leftrightarrow3x+\frac{2}{7}.x-\frac{5}{7}+6x=3\)
\(\Leftrightarrow\frac{65}{7}.x-\frac{5}{7}=3\)
\(\Leftrightarrow\frac{65}{7}.x=\frac{26}{7}\)\(\Leftrightarrow x=\frac{2}{5}\)
Vậy x =\(\frac{2}{5}\)
tìm x biết : ( 19x + 2.5^2 ) : 14 = ( 13 - 8 ) ^ 2 - 4 ^2
( 19x + 2.52 ) : 14 = ( 13 - 8 )2- 4 2
( 19x + 2.52 ) : 14 = 52- 4 2
( 19x + 2.52 ) : 14 = 25- 16
( 19x + 2.52 ) : 14 =9
( 19x + 50 ) : 14 =9
19x + 50=9 . 14
19x + 50=126
19x=126-50
19x=76
x=76:19
x=4
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(19x+2*5^2)/14=(13-8)^2-4^
(19x+2*25)/14=(13-8)^2-16
(19x+2.25)/14=5^-16
(19x+2.25)/14=25-16
(19+2.25)=9*14
19X=126+50
x=76/19
x=4